Cron status always remain "running" in magento 2 - magento2

I have created a custom module and added crontab file to run cron related task.
<group id="index">
<job name="custom_orderprocess" instance="Test\Module\Cron\Check" method="execute">
<schedule>* * * * *</schedule>
</job>
</group>
Although I can see the cron is scheduled but its status always remain "running" (never show success).
I have also for infinite loop (removing all code except return statement) but still no luck.
Can some one guide me

If cron is in running state then may be some error in your cron function.

Related

How can i add a cron job run every minute to my elearning site on moodle?

I try to add a cron job on an elearning.mysite.gr(Moodle). Although my host gives this message every hour.
Oct 2 1:10:01 linux CROND[123456]: (admin) CMD (touch /tmp/test.txt > /dev/null)
On my site administration -> notifications get this message:
The admin/cli/cron.php script has not been run for 3 days 2 hours and should run every 1 min.
At moodle documentation
/path/to/moodle/admin/cli/cron.php, can i use it ? in which way ?
I tried this :
/usr/bin/php /path/to/moodle/admin/cli/cron.php
but gives me that the process completed with error at one minute
only this touch /tmp/test.txt > /dev/null
completed with success.
Moodle Documentation:
The CLI (command line interpreter) script. This will be at the path /path/to/moodle/admin/cli/cron.php
If in doubt, this is the correct script to use. This needs to be run by a 'PHP CLI' program on your computer. So the final command may look something like /usr/bin/php /path/to/moodle/admin/cli/cron.php You can (and should) try this on your command line to see if it works. WARNING: Check your command-line PHP version is compatible with your chosen version of Moodle.-How to check it?
The command-line PHP program is different to the one running your web site and is not always the same version.
I don't know what to do...I will appreciate any help!!!
I tried by my host panel interface :
Type of progress:
Command line
URL
PHP
i should choose one from 3.
Command*:
placeholder to add my command to be excecuted
Excecute:
Dropdown
1.Cron style
2.Daily at 00:00
I use command line.
touch /tmp/test.txt
When i add
cron style and 1 * * * * * , get message for syntax.
and for
daily at 00:00 success message but on my notification of my site has
The admin/cli/cron.php script has not been run for 17 days 22 hours and should run every 1 min.
That's the icon of my Plesk Login. To change the path/to/moodle/admin/cli/cron.php xould i check the file manager in order to find cron.php file ??
As you add the cron from a web interface (maybe Plesk ?) you only need this part:
/path/to/moodle/admin/cli/cron.php
replace /path/to/moodle/ with the real path on your server, usulay something like /var/www/moodle/ or /var/www/vhosts/domain.name/httpdocs/moodle
To run every 1 minute cron style is :
* * * * *
If you can choose PHP version, choose the same version as the one you are using for Moodle.
Finally, I give this touch /tmp/test.txt ->and at cron style the touch /tmp/test.txt, as you suggest to me.
Because the other commands cannot complete with success.
But in my notifications,(Site administration-Moodle) i still get the message that cron don't run.

In Celery tasking, is the database scheduler sufficient, or do I need to specify the run_every property as well?

I have a periodic task that is supposed to run once a day, but currently it runs twice a day, and I'm not sure why. The second run occurs milliseconds after the intended one.
My periodic task has the run_every property specified:
run_every = crontab(hour=1, minute=1)
but in my settings file, the database scheduler is specified:
CELERYBEAT_SCHEDULER = 'djcelery.schedulers.DatabaseScheduler'
furthermore in the database, there are tables with the task names and their crontab schedule.
For example we have a table called djcelery_crontabschedule and it also specifies that the same task should run at 1:01 am.
Could this be causing my task to run twice every day?
I never use run_every... Here is an example from the beatconfig.py file that I use:
beat_schedule = {
'company-data-report': {
'task': 'report.company_data_report',
'schedule': crontab(minute=0, hour=7),
'args': [],
'options': {'expires': 120*60}
},
etc
This particular task runs every day at specified time. We use the default Celery scheduler, not some third-party implementation.

How to manipulate the status of current job-execution from inside of an inline script?

The following code returns an error to rundeck.
#!/bin/bash
exit -1
And rundeck decides how to deal with it by running the next step or changing the execution "status" to "failed".
I would like to modify the status directly by inline script to support more than 2 states. I need "succeeded", "failed" and "nodata" to express that the data are missing.
Is there a way to express this?
There is none. Just like bash can return zero or non-zero
One possible alternative is raise an exception with message nodata and exit with non-zero code. Rundeck will mark this job as fail with NonZeroResultCode error. You should be able to get your error message nodata with ${result.message}

Return code of scheduled task prefixed with 0x8007000 in list view, registered as 0 in the event log

I am currently trying to setup monitoring of windows scheduled tasks in Zabbix. It seemed easy enough to just monitor the Microsoft-Windows-TaskScheduler/Operational event log filtered by 201 events and regexing on the return code, but when I started simulating errors to test the monitoring, nothing happened.
It turns out that all our windows 2012 servers always log "return code 0" in the event log, even though it actually, sort of, displays it correctly in the Task Scheduler list view. When I say "sort of", it's because the "Last Run Result" actually displays 0x80070001 if the exit code of the program run by the scheduled task is 1.
I have spend a lot of time tweaking the settings, like user account, Run only when user is logged on, Run whether user is logged on or not, setting path on the action, Run with highest privileges, Configure for Vista/7/2012, etc. Nothing helped.
Finally I did some testing on my local machine, Windows 7, and a 2008R2 server, both of which just worked as expected.
The specific task I was testing ran a PowerShell script, using -Command so that it properly propagates the exit, but to rule out any PS issues I also tested with a batch file containing "exit 1" and finally with a small C# console program, that just returns whatever you supply on the command line.
PS, batch and console program all work fine on 7 and 2008, but they all fail in the same manner on 2012.
I've google this to death, but keep coming up short. Apparently 0x80070005 and other similar error codes are have some meaning, but that's not what happens in my case. In my case it seems that my exit code is bitwise or'ed with 0x80070000.
I should note that in all the cases, even 2012, the program started by the task, actually executes and run to the end, it's just the exit code which is handled weirdly.
Following is the output from the test runs:
From Powershell (my shell writes :( if $LASTEXITCODE > 0 ):
54 :( .\ExitCodeTest.exe 1
55 :( $LASTEXITCODE
1
56 :) .\ExitCodeTest.exe 10
57 :( $LASTEXITCODE
10
Windows Server 2008 R2 Standard:
Last Run Result (from list view): 0xA
Event 201 from event log Microsoft-Windows-TaskScheduler/Operational:
Task Scheduler successfully completed task "\ErrorTest" ,
instance "{b67a26cf-7fd8-461a-93d9-a5e48e72e558}" ,
action "D:\Tasks\ExitCodeTest.exe" with return code 10.
Windows Server 2012 Datacenter (notice that the return code in the event log is 0):
Last Run Result (from list view): 0x8007000A
Event 201 from event log Microsoft-Windows-TaskScheduler/Operational:
Task Scheduler successfully completed task "\error test" ,
instance "{2bde46b8-2858-4772-a7ec-d66b29d893a6}" ,
action "D:\Tasks\ExitCodeTest.exe" with return code 0.
Source for ExitCodeTest.exe:
static void Main( string[] args )
{
int exitCode = 0;
if ( args.Length > 0 )
{
exitCode = Convert.ToInt32( args[0] );
}
Environment.Exit( exitCode );
}
Please help, I am at my wits end.
Thanks,
John
(this is NOT an answer, but StackOverflow is refusing to let me add comments - when I click 'add comment', browser scrolls to top of page :-/)
You may be misinterpreting the Last Run Result column. According to Wikipedia (http://en.wikipedia.org/wiki/Windows_Task_Scheduler), LRR values of 0, 1 and 10 are common. Ignore the 0x8007 prefix - this just indicates a WIN32 error code transformed into an HRESULT (http://msdn.microsoft.com/en-us/library/gg567305.aspx).
Try running the test and forcing an exit code of something other than 1 or 10 to see if this influences LRR.
This does not explain of course why action return code is 0 in 2012. Error code 10 is defined as 'environment is incorrect'. Could it be that 2012 server does not want to run 32bit executable?
One other suggestion (and I'm a little out of my depth); according to (http://msdn.microsoft.com/en-us/library/system.environment.exit(v=vs.110).aspx): "Exit requires the caller to have permission to call unmanaged code. The return statement does not.". Might be worth re-compiling ExitCodeTest as follows:
static int Main(string[] args)
{
int exitCode = 0;
if ( args.Length > 0 )
{
exitCode = Convert.ToInt32( args[0] );
}
return exitCode;
}
I'm seeing a similar issue on Server 2012 with a batch file that looks like it succeeds, shows a return value of 0 in event log, but a Last Run Result of 0x80070001.
I see MSFT has a hotfix available for Server 2012 which might address this issue:
http://support.microsoft.com/kb/3003689
I had this problem and fixed it this way.
Instead of calling a batch file move the commands into the actions section of the scheduled task.
I realize this may not work for you as some batch files are long.
I suspect it has to do with circumventing security on a scheduled task -- if you can change the batch file then you could get a scheduled task to run as the identity without windows being the wiser.

Stopping SpringBatch jobs started from the command line

Spring Batch jobs can be started from the commandline by telling the JVM to run CommandLineJobRunner. According to the JavaDoc, running the same command with the added parameter of -stop will stop the Job:
The arguments to this class can be provided on the command line
(separated by spaces), or through stdin (separated by new line). They
are as follows:
jobPath jobIdentifier (jobParameters)* The command line options are as
follows
jobPath: the xml application context containing a Job
-restart: (optional) to restart the last failed execution
-stop: (optional) to stop a running execution
-abandon: (optional) to abandon a stopped execution
-next: (optional) to start the next in a sequence according to the JobParametersIncrementer in the Job jobIdentifier: the name of the job or the id of a job execution (for -stop, -abandon or -restart).
jobParameters: 0 to many parameters that will be used to launch a job specified in the form of key=value pairs.
However, on the JavaDoc for the main() method the -stop parameter is not specified. Looking through the code on docjar.com I can't see any use of the -stop parameter where I would expect it to be.
I suspect that it is possible to stop a batch that has been started from the command line but only if the batches being run are backed by a non-transient jobRepository? If running a batch on the command line that only stores its data in HSQL (ie in memory) there is no way to stop the job other than CTRL-C etc?
stop command is implemented, see source for CommandLineJobRunner, line 300+
if (opts.contains("-stop")) {
List<JobExecution> jobExecutions = getRunningJobExecutions(jobIdentifier);
if (jobExecutions == null) {
throw new JobExecutionNotRunningException("No running execution found for job=" + jobIdentifier);
}
for (JobExecution jobExecution : jobExecutions) {
jobExecution.setStatus(BatchStatus.STOPPING);
jobRepository.update(jobExecution);
}
return exitCodeMapper.intValue(ExitStatus.COMPLETED.getExitCode());
}
The stop switch will work, but it will only stop the job after the currently executing step completes. It won't kill the job immediately.