I have a column as date (CHARACTER VARYING) in table And it may contain dd/mm/yyyy or mm/dd/yyyy format dates. Now i need to convert all dates in dd/mm/yyyy ..
select c.trial_id,c.name,c.gender,age(cast(c.dob as date)) as p_age,c.relationship_name,c.relationship,c.dob,c.staff_id from mas_patient_details c
Even i tried doing like this
select to_char(dob::date, 'DD/MM/YYYY')from mas_patient_details
both of query returns
ERROR: date/time field value out of range: "12/21/1989" HINT:
Perhaps you need a different "datestyle" setting.
********** Error **********
ERROR: date/time field value out of range: "12/21/1989" SQL state:
22008 Hint: Perhaps you need a different "datestyle" setting.
Related
I have a table with a bunch of records, with different values for a date and I need them all parsed as a date value, so I'm trying to parse a date in postgres and I'm receiving an error which doesn't tell me much
select to_Date(:original_date, 'YYYYmmDD');
When I pass this value to original_date is when I get the error: '2022-11-18T11:02:08-03:00'
Here's the error I'm getting:
SQL Error [22008]: ERROR: date/time field value out of range: "2022-11-18T11:02:08-03:00"
Where: SQL statement "select to_Date(original_date, 'YYYYmmDD')"
PL/pgSQL function parse_date(character varying) line 5 at SQL statement
As mentioned by Hambone in the comment below the question, changing my date format to 'YYYY-mm-DD' works like a charm.
Thanks for that Hambone!
I am trying to store a date in a Postgres table with the below SQL command
update card_order set valid_until = to_date('23/12/17,Σαβ 11:00πμ', 'YYYY-MM-DD,Day HH:MIa');
But I get the error:
ERROR: invalid value "Σαβ 11" for "Day"
DETAIL: The given value did not match any of the allowed values for this field.
I have setup my db with
Encoding UTF8
Collation Greek_Greece.1253
Character type Greek_Greece.1253
You'd need to set lc_time to a Greek locale and use the TM modifier as in TMDY.
But that still won't help, because, as the documentation says:
to_timestamp and to_date ignore the TM modifier.
This question already has answers here:
in postgres, can you set the default formatting for a timestamp, by session or globally?
(3 answers)
Closed 6 years ago.
INSERT into Group (Name,CreatedDate) VALUES ('Test',UTC_TIMESTAMP(), 1);
This is the query I have used for mysql to insert current date time.
When I am using this in postgresql, I am getting below error.
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
********** Error **********
ERROR: function utc_timestamp() does not exist
SQL state: 42883
I have tried like below using now(), however it is inserting like "2016-07-07 17:01:18.410677". I need to insert in 'yyyymmdd hh:mi:ss tt' format.
INSERT into Group (Name,CreatedDate) VALUES ('Test',UTC_TIMESTAMP(), 1);
How to insert current date time in insert query of postgresql in above format ?
timestamp (or date or time columns) do NOT have "a format".
Any formatting you see is applied by the SQL client you are using.
To insert the current time use current_timestamp as documented in the manual:
INSERT into "Group" (name,createddate)
VALUES ('Test', current_timestamp);
To display that value in a different format change the configuration of your SQL client or format the value when SELECTing the data:
select name, to_char(createddate, 'yyyymmdd hh:mi:ss tt') as created_date
from "Group"
For psql (the default command line client) you can configure the display format through the configuration parameter DateStyle: https://www.postgresql.org/docs/current/static/runtime-config-client.html#GUC-DATESTYLE
For current datetime, you can use now() function in postgresql insert query.
You can also refer following link.
insert statement in postgres for data type timestamp without time zone NOT NULL,.
You can of course format the result of current_timestamp().
Please have a look at the various formatting functions in the official documentation.
I have the following function:
CREATE function SEMANA_ISO (fecha date) returns text as $$
select to_char(fecha, 'mm-dd-yyyy');
$$ LANGUAGE sql;
It works with:
Select SEMANA_ISO ('28/12/2014');
Select SEMANA_ISO ('01/01/2015');
Select SEMANA_ISO ('01/07/2015');
As you may see below
But not with:
Select SEMANA_ISO ('12/31/2014');
It shows:
********** Error **********
ERROR: The value of time / date is out of range "12/31/2014"
SQL state: 22008
Hint: You may need a different configuration of "dateStyle".
Character: 20
Do you have any suggestion without having to change the datestyle so I can enter
Select SEMANA_ISO ('12/31/2014');
And get an output of:
12-31-2014
using just one function to "parse" all dates?
Your function is declared to get a parameter of type date so you also need to pass such a value. '12/31/2014' is a character value, not a date.
When you pass a character literal (aka string) to the function Postgres is forced to do an implicit data type conversion based on the current datestyle - not something you should rely on.
If you want to call the function independently of the datestyle you need to pass a proper date literal, e.g. DATE '2014-12-31'
For more details on specifying date values, please see the manual: http://www.postgresql.org/docs/current/static/datatype-datetime.html#DATATYPE-DATETIME-INPUT
If you want 12/31/2014 accepted as a date set datestyle to iso, dmy;
if you want 31/12/2014 accepted as a date set datestyle to iso, mdy;
you can't have both at the same time, else 4/1/2015 is ambiguos, and must be rejected.
There is to_date() to input date literals with an arbitrary (given) format:
SELECT to_date('12/31/2014', 'MM/DD/YYYY') AS date1
, to_date('31/12/2014', 'DD/MM/YYYY') AS date2;
That's "without changing any datestyle". Obviously, you need to provide a matching format pattern, though.
To output the same in any desired format, use to_char():
SELECT to_char(to_date('12/31/2014', 'MM/DD/YYYY'), 'DD/MM/YYYY') AS date_as_text
I'd like to change a specific column in my PostgreSQL database from character_varying type to type date. Date is in the format yyyy:mm:dd
I tried to do:
alter table table_name
alter column date_time type date using (date_time::text::date);
But I received an error message:
date/time field value out of range: "2011:06:15"
When you cast text or varchar to date, the default date format of your installation is expected - depending on the datestyle setting of your session, typically set in your postgresql.conf. If in doubt, check with:
SHOW datestyle;
Generally, colon (:) is a time separator, In a simple cast, PostgreSQL will probably try to interpret '2011:06:15' as time - and fail.
To remove ambiguity use to_date() with a matching pattern for your dates:
ALTER TABLE table_name
ALTER COLUMN date_time type date
USING to_date(date_time, 'YYYY:MM:DD'); -- pattern for your example