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in postgres, can you set the default formatting for a timestamp, by session or globally?
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Closed 6 years ago.
INSERT into Group (Name,CreatedDate) VALUES ('Test',UTC_TIMESTAMP(), 1);
This is the query I have used for mysql to insert current date time.
When I am using this in postgresql, I am getting below error.
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
********** Error **********
ERROR: function utc_timestamp() does not exist
SQL state: 42883
I have tried like below using now(), however it is inserting like "2016-07-07 17:01:18.410677". I need to insert in 'yyyymmdd hh:mi:ss tt' format.
INSERT into Group (Name,CreatedDate) VALUES ('Test',UTC_TIMESTAMP(), 1);
How to insert current date time in insert query of postgresql in above format ?
timestamp (or date or time columns) do NOT have "a format".
Any formatting you see is applied by the SQL client you are using.
To insert the current time use current_timestamp as documented in the manual:
INSERT into "Group" (name,createddate)
VALUES ('Test', current_timestamp);
To display that value in a different format change the configuration of your SQL client or format the value when SELECTing the data:
select name, to_char(createddate, 'yyyymmdd hh:mi:ss tt') as created_date
from "Group"
For psql (the default command line client) you can configure the display format through the configuration parameter DateStyle: https://www.postgresql.org/docs/current/static/runtime-config-client.html#GUC-DATESTYLE
For current datetime, you can use now() function in postgresql insert query.
You can also refer following link.
insert statement in postgres for data type timestamp without time zone NOT NULL,.
You can of course format the result of current_timestamp().
Please have a look at the various formatting functions in the official documentation.
Related
I have a table with a bunch of records, with different values for a date and I need them all parsed as a date value, so I'm trying to parse a date in postgres and I'm receiving an error which doesn't tell me much
select to_Date(:original_date, 'YYYYmmDD');
When I pass this value to original_date is when I get the error: '2022-11-18T11:02:08-03:00'
Here's the error I'm getting:
SQL Error [22008]: ERROR: date/time field value out of range: "2022-11-18T11:02:08-03:00"
Where: SQL statement "select to_Date(original_date, 'YYYYmmDD')"
PL/pgSQL function parse_date(character varying) line 5 at SQL statement
As mentioned by Hambone in the comment below the question, changing my date format to 'YYYY-mm-DD' works like a charm.
Thanks for that Hambone!
I am dealing with the table which has date information in CHar(20) type. This date is in dd.mm.yyyy HH.MM.SS format but my pgadmin has Month first format. I tried editing posgres config file to change the date format. I tried to use SET timezone and then tried to convert type to timestamp but nothing is working. How can I convert following column into timestamp format? I followed miost of the answers here on stackoverflow but getting out of range error even after using set function or editing config file.
Use to_timestamp:
to_timestamp(stringcol, 'DD/MM/YYYY HH24:MI')
To change the data type of the column, which is highly commendable:
ALTER TABLE mytable ALTER date1 TYPE timestamp
USING CAST (to_timestamp(date1, 'DD/MM/YYYY HH24:MI') AS timestamp);
I'm looking to get a result in Amazon Athena were I can count the quantity of users created by day (or maybe by month)
But previous that I have to convert the unix timestamp to another date format. And this is where i fail.
My last goal is to convert this type of timestamp:
1531888605109
In something like:
2018-07-18
According to Epoch Converter
But when I try to apply the solution i saw in this quiestion: Casting unix time to date in Presto
I got the error:
[Simba]AthenaJDBC An error has been thrown from the AWS Athena client. SYNTAX_ERROR: line 1:13: Unexpected parameters (varchar) for function from_unixtime. Expected: from_unixtime(double) , from_unixtime(double, bigint, bigint) , from_unixtime(double, varchar(x)) [SQL State=HY000, DB Errorcode=100071]
This is my query:
select cast(from_unixtime(created)as date) as date_creation,
count(created)
from datalake.test
group by date_creation
Maybe I've to cast over the sctring because the data type of the field is not a date.
My table description: Link to the table description
line 1:13: Unexpected parameters (varchar) for function from_unixtime. Expected: from_unixtime(double)
This means that your timestamps -- even though they appear numeric -- are varchars.
You need to add a CAST to cast(from_unixtime(created)as date), like:
CAST(from_unixtime(CAST(created AS bigint)) AS date)
Note: When dealing with time-related data, please have in mind that https://github.com/prestosql/presto/issues/37 is not resolved yet in Presto.
I have the following function:
CREATE function SEMANA_ISO (fecha date) returns text as $$
select to_char(fecha, 'mm-dd-yyyy');
$$ LANGUAGE sql;
It works with:
Select SEMANA_ISO ('28/12/2014');
Select SEMANA_ISO ('01/01/2015');
Select SEMANA_ISO ('01/07/2015');
As you may see below
But not with:
Select SEMANA_ISO ('12/31/2014');
It shows:
********** Error **********
ERROR: The value of time / date is out of range "12/31/2014"
SQL state: 22008
Hint: You may need a different configuration of "dateStyle".
Character: 20
Do you have any suggestion without having to change the datestyle so I can enter
Select SEMANA_ISO ('12/31/2014');
And get an output of:
12-31-2014
using just one function to "parse" all dates?
Your function is declared to get a parameter of type date so you also need to pass such a value. '12/31/2014' is a character value, not a date.
When you pass a character literal (aka string) to the function Postgres is forced to do an implicit data type conversion based on the current datestyle - not something you should rely on.
If you want to call the function independently of the datestyle you need to pass a proper date literal, e.g. DATE '2014-12-31'
For more details on specifying date values, please see the manual: http://www.postgresql.org/docs/current/static/datatype-datetime.html#DATATYPE-DATETIME-INPUT
If you want 12/31/2014 accepted as a date set datestyle to iso, dmy;
if you want 31/12/2014 accepted as a date set datestyle to iso, mdy;
you can't have both at the same time, else 4/1/2015 is ambiguos, and must be rejected.
There is to_date() to input date literals with an arbitrary (given) format:
SELECT to_date('12/31/2014', 'MM/DD/YYYY') AS date1
, to_date('31/12/2014', 'DD/MM/YYYY') AS date2;
That's "without changing any datestyle". Obviously, you need to provide a matching format pattern, though.
To output the same in any desired format, use to_char():
SELECT to_char(to_date('12/31/2014', 'MM/DD/YYYY'), 'DD/MM/YYYY') AS date_as_text
I have a sybase 15 DB and for one of my tables, I want to make a column default to the current date/time of the row insert. Is this possible?
In a sybase text, the following is said:
ALTER TABLE sales_order
MODIFY order_date DEFAULT CURRENT DATE
On my DB this doesn't do anything, as CURRENT DATE is not recognized.
using getDate() is a valid solution, you must have had a syntax error. Try it like this:
create table test_tbl (
date_data DATETIME default getDate() NOT NULL
)
Try using getDate() instead
... DEFAULT GETDATE() is correct. the case is irrelevant; mixed case may indicate a Java method, but it is a straight TSQL Function. Please post the exact error msg if you want further assistance.
Also, the ALTER TABLE method sets the Default for future INSERTS; if you want the existing data changed, you need to UPDATE (good for small tables) or unload/reload the table (demanded for the large).
Watch the NULL/NOT NULL: you do not want to change that without understanding. Again, the existing/future issue needs address. NOT NULL prevents NULL being explicitly passed as an INSERT VALUE.
CURRENT_DATE is a SQL standard that isn't universally adopted.
As noted elsewhere the getdate() T-SQL function should be used instead.