UPDATE statement using two arrays at the same index in WHERE clause - postgresql

Question

I am trying to update a table, entities with a column, contacts that is an array of ids from another table, contacts. The contacts table has the columns first_name and last_name, and I have an array of first names, firstNames and last names, lastNames to pass in.
How would you update the contacts column in the entities table with one query that properly gets all of the contacts with first name firstNames[0] AND last name lastNames[0], and all of the contacts with first name firstNames[1] AND last name lastNames[1], and [...] all of the contacts with first name firstNames[n] AND last name lastNames[n]?
My initial thought was something like UPDATE entities SET contacts = (SELECT id FROM contacts WHERE first_name = ANY(firstNames) AND last_name = ANY(lastNames).
The problem with this arrises when the contacts table is like this:
first_name | last_name
----------------------
Bob | Jones
Bob | Miller
David | Miller
If I wanted to set the contacts column to the Ids for Bob Jones and David Miller, but NOT Bob Miller, and I passed in ['Bob', 'David'] for firstNames and ['Jones', 'Miller'] for lastNames in the above query, Bob Miller would also get added to the contacts column.

Answer 1

May be you look for something like this:
WITH x AS (
SELECT 'Bob'::text AS firstName, 'Jones'::text AS lastName
UNION SELECT 'David', 'Miller'
UNION SELECT 'Bob', 'Miller'
)
SELECT *
FROM x
WHERE (firstName, lastName) = ANY (ARRAY [
('Bob'::text, 'Jones'::text),
('David'::text, 'Miller'::text)
]);
Yet another way:
WITH x AS (
SELECT 'Bob'::text AS firstName, 'Jones'::text AS lastName
UNION SELECT 'David', 'Miller'
UNION SELECT 'Bob', 'Miller'
)
SELECT *
FROM x
WHERE EXISTS (
SELECT 1
FROM (SELECT ARRAY [
['Bob', 'Jones'],
['David', 'Miller']]::text[][] AS n
) AS n
JOIN LATERAL generate_series(1, array_upper(n, 1)) AS i ON true
WHERE firstName = n[i][1]
AND lastName = n[i][2]
);