Say i have Four tables
1) Studnets:
Student_ID
First Name
Last Name
2) Contact (Will take the latest item)
Contact_ID
Address
ZipCode
DateAdded
3) Phone (Will take the last three items)
Contact_ID
PhoneNumber
DateAdded
4) StudentContactRef
Student_ID
Contact_ID
How can I query this table? I want to have the fields as shows below:
Student_ID
First Name
Last Name
Address
ZipCode
PhoneNumber1
PhoneNumber2
PhoneNumber3
select
s.Student_ID,
s.FirstName,
s.LastName,
c.Contact_ID,
c.Address,
c.ZipCode,
p.PhoneNumber1,
p.PhoneNumber2,
p.PhoneNumber3
from
Students s
inner join StudentContactRef r on
s.Student_ID = r.StudentID
inner join Contact c on
r.Contact_ID = c.Contact_ID
inner join
(select top 3 Contact_ID, PhoneNumber from Phone
pivot (PhoneNumber for PhoneNumber IN
(PhoneNumber1, PhoneNumber2, PhoneNumber3)
where Contact_ID = r.Contact_ID order by DateAdded desc) p on
r.Contact_ID = p.Contact_ID
Update: That should get you what you're looking for!
Related
The domain is:
company (id, name, adress)
employee (id, name, adress, company_id, expertise_id)
dependantrelative (id, name, employee_id)
expertise (id, name, class)
I want to know how to get the number of dependantrelatives of each employee who are unique experts in their respective companies.
The Query below does not return the correct answer. Can you help me?
SELECT DISTINCT dependantrelative.employee_id
, COUNT(*) AS qty_dependantrelatives
FROM dependantrelative
INNER JOIN employee
ON employee.id = dependantrelative.employee_id
GROUP BY dependantrelative.employee_id
I just tried out the Query below and it works, but I want to know if there is a faster and simple way of getting the answer.
SELECT employee.id
,COUNT(dependantrelative.employee_id) AS qty_dependantrelatives
FROM (
SELECT employee.company_id
, employee.expertise_id AS expert
, COUNT(employee.expertise_id)
FROM employee
GROUP BY employee.company_id
, employee.expertise_id
HAVING COUNT(employee.expertise_id)<2
) AS uniexpert
LEFT JOIN employee
ON employee.expertise_id = uniexpert.expert
LEFT JOIN salesorderdetail
ON dependantrelative.employee_id = employee.id
GROUP BY employee.id
ORDER BY employee.id
I have these tables:
person (id primary key, name)
money (acct primary key, loaner)
loan (id primary key, acct)
How would I create a SQL query that shows for each loaner the names of persons who took more than four loans from that specific loaner? And I want the 4 persons that he loaned to be different with each other.
SELECT
p.id, p.name, m.loaner, COUNT(*)
FROM
person p
INNER JOIN
loan l ON p.id = l.id
INNER JOIN
money m ON l.acct = m.acct
GROUP BY
id, name, lower
HAVING
COUNT(*) = 4
With this query you can find the first part of the question - what should I add?
I would try this out and see what happens :D
SELECT distinct *
FROM person as p_loaner_detailed
WHERE p_loaner_detailed.id in (
SELECT loanerId
FROM (
SELECT p.id, p.name, m.loaner as loanerId
COUNT(*)
FROM person p
INNER JOIN loan l
ON p.id = l.id
INNER JOIN money m
ON l.acct = m.acct
GROUP BY id, name, loanerId
HAVING COUNT(*) > 4
)
)
I am creating some queries for my project, but I face some difficulties with the follow ones:
A SELECT statement containing a subquery to retrieve a list of Locations (location id and street_address) that have employees with higher salary than the average of their department. The list must contain the number of those employees and their total salary per location. Name these aggregates respectively "emp" and "totalsalary". The locations in the list must be ordered by location_id.
Select LOCATION_ID, STREET_ADDRESS
from HR.LOCATIONS IN
(Select Employee_id
from HR.Employees
Where Salary > round(avg(SALARY)))
order by location_id;
error: SQL command not properly ended
and the second query is the following
The JOB_HISTORY table can contain more than one entries for an employee who was hired more than once. Create a query to retrieve a list of Employees that were hired more than once. Include the columns EMPLOYEE_ID, LAST_NAME, FIRST_NAME and the aggregate "Times Hired".
SELECT FIRST_NAME,LAST_NAME,EMPLOYEE_ID,
count (*)as TIMES_HIRED
from HR.JOB_HISTORY, HR.EMPLOYEES
where EMPLOYEE_ID= LAST_NAME
having COUNT(*) >1;
error: not a single-group
Try these hope they help. I am making an assumption that employee table has Location_Id column. I am adding Employee_id to Group by to make sure you get correct TotalSalary:
Select LOCATION_ID, STREET_ADDRESS, Count(Employee_id) AS emp, SUM(salary) AS totalsalary
from HR.LOCATIONS INNER JOIN
(Select Employee_id, salary
from HR.Employees
Having Salary > round(avg(SALARY), 0)) AS Emp ON HR.LOCATION_ID = Emp.Location_ID
Group By LOCATION_ID, STREET_ADDRESS, Employee_id
order by location_id;
For the second question:
SELECT FIRST_NAME,LAST_NAME,EMPLOYEE_ID,
count(Employee_id) as TIMES_HIRED
from HR.JOB_HISTORY inner join HR.EMPLOYEES On JOB_HISTORY.Employee_id = Employees.Employee_id
Group By FIRST_NAME,LAST_NAME,EMPLOYEE_ID
Having count(Employee_id) >1;
I have two queries:
SELECT city, count(id) as num_of_applicants
FROM(
select distinct(students.id), city
FROM STUDENTS INNER JOIN APPLICATIONS ON STUDENTS.ID = APPLICATIONS.STUDENT_ID
WHERE APPLICATIONS.COLLEGE_ID = '28'
) AS derivedTable
GROUP BY city;
SELECT city, count(id) as num_of_accepted_applicants
FROM
(select applications.id, city FROM
STUDENTS INNER JOIN APPLICATIONS ON STUDENTS.ID = APPLICATIONS.STUDENT_ID
WHERE status = 'Accepted' and college_id = '28') as tbl
GROUP BY city
one give the number of applicants for each college and one give the number of accepted applicants in each college, but I want to get a result in on query (instead of) where the result is something like:
city | number_of_applicants | number_of_accepted_applicants
You can simplify (fyi: I didn't understand why you used the derived tables, you could have just put the COUNT and GROUP BY on the inner queries) and combine the queries as this:
SELECT city
, COUNT(*) AS num_of_applicants
, SUM( CASE
WHEN status = 'Accepted' THEN 1
ELSE 0
END
) AS num_of_accepted_applicants
FROM STUDENTS
JOIN APPLICATIONS
ON STUDENTS.ID = APPLICATIONS.STUDENT_ID
WHERE college_id='28'
GROUP BY city;
Another way is to continue with the technique of derived tables. Make each of your queries a derived table and JOIN on the city - but that would not perform as well.
I am using t-sql. I have what I thought would be an easy search. There is a 1-to-many relationship between SalesPerson and TradeShow. 1 salesperson could have gone to many trade shows. I need to be able to search on the SalePerson. I also need to be able to search on the LAST trade show they attended. I thought I would be able to do simple join and group on their last trade show, but I can not display the City or State.
SELECT SalePersonID, FirstName, LastName, TradeShow.DateLastWent
FROM SalesPerson INNER JOIN
(SELECT SalePersonID, MAX(DateLastWent) AS DateLastWent
FROM TradeShow
GROUP BY SalesPersonID) AS TradeShow ON SalesPerson.SalePersonID= TradeShow.SalePersonID
This workds, but the Tradeshow also has city and State. I need to be able to search on and display city and state. But if I include them in the subquery, I have to include thm in an aggregate function, and if I do that, I get the incorrect city and state.
The tables are simple
SALEPERSON
salespersonID PK
firstname
lastname
TRADESHOW
tradeshowID PK
datelastwent
city
state
salespersonID FK
Re-word it: what you want is the salesperson, plus the information from the last show that they have been to.
Select
SalePersonID,
FirstName,
LastName,
TradeShow.DateLastWent,
TradeShow.City,
TradeShow.State
From
SalesPerson
Inner Join TradeShow
On SalesPerson.SalePersonID = TradeShow.SalePersonID
Where
TradeShow.TradeShowID =
(Select Top 1 Latest.TradeShowID
From TradeShow As Latest
Where SalesPerson.SalePersonID = Latest.SalePersonID
Order By Latest.DateLastWent Desc)
You can join TradeShow twice :
SELECT SalePersonID, FirstName, LastName, TS1.DateLastWent,
TS2.City, TS2.State
FROM SalesPerson INNER JOIN
(SELECT SalePersonID, MAX(DateLastWent) AS DateLastWent
FROM TradeShow
GROUP BY SalesPersonID
) AS TS1 ON (SalesPerson.SalePersonID= TradeShow.SalePersonID)
INNER JOIN TradeShow TS2 ON
(TS2.SalePersonID = TS1.SalePersonID AND TS2.DateLastWent = TS1.DateLastWent)
WHERE TS2.City = 'CityName'
There is likely a more elegant way to solve this, but my first thought is to simply grab the newest TradeShow record to join with
SELECT SalePersonID, FirstName, LastName, TradeShow.DateLastWent
FROM SalesPerson
INNER JOIN (
SELECT *
FROM (
SELECT TradeShowId, DateLastWent, City, State, SalesPersonId
FROM TradeShow
ORDER BY datelastwent DESC
)
WHERE ROWNUM <= 1
) ON SalesPerson.SalesPersonId = TradeShow.SalesPersonId
Edit
Oops... been playing with Oracle too much
ROW_NUMBER() OVER(order by date) or SELECT TOP X
would be thw SQL Server way for doing this... don't have an instance of SQL-Server running, but pretty sure the syntax ends up being something like
SELECT SalePersonID, FirstName, LastName, TradeShow.DateLastWent
FROM SalesPerson
INNER JOIN (
SELECT TradeShowId, DateLastWent, City, State, SalesPersonId, ROW_NUMBER() OVER(PARTITION BY TradeShow.SalesPersonId ORDER BY DateLastWent DESC) RowNumber
FROM TradeShow
) ON SalesPerson.SalesPersonId = TradeShow.SalesPersonId AN TradeShow.RowNumber = 1