sed -i -e "s/.*web_listen_uri.*/web_listen_uri = http://$staticip:9000/ g"
what is the problem in this string ? when executed it is showing this
sed: -e expression #1, char 45: unknown option to `s'
I have tried with delimiters but still same error
Modify your sed command to sed -i -e "s/.*web_listen_uri.*/web_listen_uri = http:\/\/$staticip:9000/g". And here's the example to use this command,
$ cat test
aaaaa web_listen_uri. bbbbb
$ sed -i -e "s/.*web_listen_uri.*/web_listen_uri = http:\/\/$staticip:9000/g" test
$ cat test
web_listen_uri = http://192.168.1.1:9000
You need to escape /to\/ for sed to be used.
You have to escape / in the replacement string. Additionally, there is a space before the final g which might also be problematic.
Related
I want to replace only the first occurence of version: * in a file.
So I have a working sed command that work with GNU sed (source):
sed -i '0,/\(.*"version"\): "\(.*\)",/s//\1: '"\"${NEW_VERSION}\",/" package-lock.json
My problem is that i am executing this in scripts that also can run without GNU sed.
When i replace by sed -i '1,/\(.*"version"\): "\(.*\)",/s//\1: '"\"${NEW_VERSION}\",/" package-lock.json then it work without GNU sed but i have the following error when GNU sed is available:
sed: -e expression #1, char 0: no previous regular expression
EDIT: my main goal
As requested, here is my initial goal:
In a package.json and/or a package-lock.json , i want to replace the first occurence of version: X.X.X by version: Y.Y.Y where $NEW_VERSION containers Y.Y.Y
Using sed:
sed -i.bak -E '/(version: ).*/!{p;d;}
s//\1'"$NEW_VERSION"'/
:a
n
ba
' file
Alternatively this awk would also work:
awk -v ver="$NEW_VERSION" '!done && /^version:/{$2=ver; done=1} 1' file
You could check first occurrence by for example storing something in hold space.
sed '
# If hold space is empty
x;/^$/{x;
# If there is a pattern, replace it and..
/\("version": "\).*",/{
s//\1'"$NEW_VERSION"'"/1
# and hold the line.
h;
};x
};x
'
I'm going to simplify the expressions, since I'm not exactly sure what you're trying to match with the double quotes and the comma, and I think they obscure the main point. To replace just the first occurrence of foo with repl, you can do:
sed -e s/foo/repl/ -e ta -e p -e d -e :a -e n -e ba
The t command branches to the :a after a replacement is made, and the commands after :a just read and print each line without trying the substitution.
eg:
$ printf '%s\n' qux foo bar baz foo | sed -e s/foo/repl/ -e ta -e p -e d -e :a -e n -e ba
qux
repl
bar
baz
foo
But, this is really a lot easier with awk:
awk '/foo/ && !a{gsub("foo", "repl"); a = 1}1'
I'm trying to copy part of a line to append to the end:
ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1_IonXpress_024_genomic.fna.gz
becomes:
ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1/GCA_900169985_IonXpress_024_genomic.fna.gz
I have tried:
sed 's/\(.*(GCA_\)\(.*\))/\1\2\2)'
$ f1=$'ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1_IonXpress_024_genomic.fna.gz'
$ echo "$f1"
ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1_IonXpress_024_genomic.fna.gz
$ sed -E 's/(.*)(GCA_.[^.]*)(.[^_]*)(.*)/\1\2\3\/\2\4/' <<<"$f1"
ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1/GCA_900169985_IonXpress_024_genomic.fna.gz
sed -E (or -r in some systems) enables extended regex support in sed , so you don't need to escape the group parenthesis ( ).
The format (GCA_.[^.]*) equals to "get from GCA_ all chars up and excluding the first found dot" :
$ sed -E 's/(.*)(GCA_.[^.]*)(.[^_]*)(.*)/\2/' <<<"$f1"
GCA_900169985
Similarly (.[^_]*) means get all chars up to first found _ (excluding _ char). This is the regex way to perform a non greedy/lazy capture (in perl regex this would have been written something like as .*_?)
$ sed -E 's/(.*)(GCA_.[^.]*)(.[^_]*)(.*)/\3/' <<<"$f1"
.1
Short sed approach:
s="ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1_IonXpress_024_genomic.fna.gz"
sed -E 's/(GCA_[^._]+)\.([^_]+)/\1.\2\/\1/' <<< "$s"
The output:
ftp://ftp.ncbi.nlm.nih.gov/genomes/all/GCA/900/169/985/GCA_900169985.1/GCA_900169985_IonXpress_024_genomic.fna.gz
I want to replace one string with another but I can't. The code is:
updatedb
MCRYPTINI=$(locate mcrypt.ini | grep 'apache2')
MCRYPTSO=$(locate mcrypt.so | grep "/mcrypt.so")
OLD="extension=mcrypt.so"
NEW="extension=$MCRYPTSO"
echo $MCRYPTINI
echo $MCRYPTSO
echo $OLD
echo $NEW
echo "'s/$OLD/$NEW' $MCRYPTINI"
sed -i 's/$OLD/$NEW' $MCRYPTINI
And the result is:
sudo sh testScript.sh
/etc/php5/apache2/conf.d/20-mcrypt.ini
/usr/lib/php5/20121212/mcrypt.so
extension=mcrypt.so
extension=/usr/lib/php5/20121212/mcrypt.so
's/extension=mcrypt.so/extension=/usr/lib/php5/20121212/mcrypt.so' /etc/php5/apache2/conf.d/20-mcrypt.ini
sed: -e expression #1, char 11: unterminated `s' command
For the response I don't need to use 'sed', but it's looks easy and good.
I use sh not bash because I want the code can use in all the systems, so I prefer answers that follow that principle
UPDATE
sed -i "s/$OLD/$NEW/" $MCRYPTINI
error:
sed: -e expression #1, char 14: unknown option to `s'
Add a slash and double quotes:
sed -i "s/$OLD/$NEW/" file
The solution could be:
sed -i "s/$OLD/$NEW/" $MCRYPTINI
but $NEW is a path, so I need to change "/" by other character, for example "+"
sed -i "s+$OLD+$NEW+" $MCRYPTINI
I'm requesting help with a very simple script...
#!/usr/bin/sed -f
sed '/11,yahoo/d'
sed '/2506,stackover flow/d'
sed '/2536,reddit/d'
Just need it to remove three matches that account for 18408 in my file, data.csv
% sed -f remove.sed < data.csv
sed: 3: remove.sed: unterminated substitute pattern
Doing these same lines individually is no problem at all, so what am I doing wrong with this?
Using freeBSD 10.1 and its implementation of sed, if that matters.
This, being a sed script, should not have "sed" at each line.
Either change it to:
#!/usr/bin/sed -f
/11,yahoo/d
/2506,stackover flow/d
/2536,reddit/d
Or to
#!/bin/sh
sed -e /11,yahoo/d \
-e /2506,stackover flow/d \
-e /2536,reddit/d
I am in directory with files consisting of many lines of lines like this:
98.684807 :(float)
52.244898 :(float)
46.439909 :(float)
and then a line that terminates:
[chuck]: cleaning up...
I am trying to eliminate :(float) from every file (but leave the number) and also remove that cleaning up... line.
I can get:
sed -ie 's/ :(float)//g' *
to work, but that creates files that keeps the old files. Removing the -e flag results in an unterminated substitute pattern error.
Same deal with:
sed -ie 's/[chuck]: cleaning up...//g' *
Thoughts?
sed -i '' -e 's/:(float)//' -e '/^.chuck/d' *
This way you are telling sed not to save a copy (null length backup extention to -i) and separately specifying the sed commands.
sed -ie expression [files...]
is equivalent to:
sed -ie -e expression [files...]
and both mean apply expression to files, overwriting the files, but saving the old files with an "e" as the backup suffix.
I think you want:
sed -i -e expression [files...]
Now if you're getting an error from that there must be something wrong with your expression.
your numbers are separated with (float) by the : character. Therefore, you can use awk/cut to get your numbers. Its simpler than a regex
$ head -n -1 file | awk -F":" '{print $1}'
98.684807
52.244898
46.439909
$ head -n -1 file | cut -d":" -f1
98.684807
52.244898
46.439909
Solution :
sed -i '' 's/ :(float)//g' *
sed -i '' 's/[chuck]: cleaning up...//g' *
Explanation :
I can get:
sed -ie 's/ :(float)//g' *
to work, but that creates files that keeps the old files.
That's because sed's i flag is supposed to work that way
-i extension
Edit files in-place, saving backups with the specified extension. If a zero-length extension is given, no backup will be saved.
In this case e is being interpreted as the extension you want to save your backups with. So all your original files will be backed up with an e appended to their names.
In order to provide a zero-length extension, you need to use -i ''.
Note: Unlike -i<your extension>, -i'' won't work. You need to have a space character between -i and '' in order for it to work.
Removing the -e flag results in an unterminated substitute pattern error.
When you remove the e immediately following -i, i.e.
sed -i 's/ :(float)//g' *
s/ :(float)//g will now be interpreted as the extension argument to i flag. And the first file in the list of files produced by shell expansion of * is interpreted as a sed function (most probably s/regular expression/replacement/flags function) You can verify this by checking the output of
sedfn=$(echo * | cut -d' ' -f1); [[ ${sedfn:0:1} == "s" ]]; echo $?
If the output of the above chain of commands is 0, our assumption is validated.
Also in this case, if somehow the first filename qualifies as a valid s/regular expression/replacement/flags sed function, the other filenames will be interpreted as regular files for sed to operate on.
sed -i -e 's/ :(float)//g' *
Check to see if you have any odd filenames in the directory.
Here is one way to duplicate your error:
$ touch -- "-e s:x:"
$ ls
-e s:x:
$ sed -i "s/ :(float)//g' *
sed: -e expression #1, char 5: unterminated `s' command
One way to protect against this is to use a double dash to terminate the options to sed when you use a wild card:
$ sed -i "s/ :(float)//g' -- *
You can do the same thing to remove the file:
$ rm "-e s:x:"
rm: invalid option -- 'e'
$ rm -- "-e s:x:"