I want to pull all AD groups in an OU and then print out each group and the user count thats in that group. The way I currently have it, it just counts how do I get the group name with the count of members?
Import-Module ActiveDirectory
$groups = (Get-ADGroup -Filter {GroupCategory -eq 'security'} -SearchBase 'Path to OU' | select SamAccountName).samaccountname
foreach ($group in $groups){
(Get-ADGroup -Identity $group | select name).count
}
Use members attribute, and count that one.
Import-Module ActiveDirectory
$groups = Get-ADGroup -Filter {GroupCategory -eq 'security'} -SearchBase 'Path to OU' -Properties *
foreach ($group in $groups) {$group.members.count}
Or, since you want both,
$groups | select name, {$_.members.count}
Related
i would like to extract members from an AD Group that contains Members and security group.
Example, Group_A:
User1
User2
User3
Group_B
When I run my script, it shows:
CN=User1,OU=Users,DC=Contoso,DC=com
CN=User2,OU=Users,DC=Contoso,DC=com
CN=User3,OU=Users,DC=Contoso,DC=com
CN=Group_B,OU=Users,DC=Contoso,DC=com
Is there another way to show their Name and/or SamAccountname?
$Groups =
#"
GroupNames;
Group_A
"# | ConvertFrom-Csv -Delimiter ';'
$ADGroups =
Foreach ($Group in $Groups){
Get-ADGroup $Group.GroupNames -Server contoso.com -Properties Members }
$ADGroups.Members
As the other helpful answers show, if you want to play safe, you can use Get-ADGroupMember to get the group membership, this would also be useful because you would be able to distinguish the ObjectClass of each member.
You could also do string manipulation over the elements (distinguishedName) of the member attribute of the AD Group by following this Q&A.
If the members of the group are on different Domains, this should work however it would be quite slow most likely.
foreach($group in $groups) {
$membership = Get-ADGroup $Group -Properties Member
$membership.Member | Group-Object { ($_ -split '(?=DC=)',2)[1] } |
ForEach-Object {
[adsi]$ldap = 'LDAP://{0}' -f $_.Name
[string]$domain = $ldap.Name
foreach($member in $_.Group) {
$obj = Get-ADObject $member -Server $domain
[pscustomobject]#{
MemberOf = $membership.Name
Domain = $domain
SamAccountName = $obj.SamAccountName
ObjectClass = $obj.ObjectClass
}
}
}
}
Get-ADGroupMember has two parameters you can use for that. samaccountname, and name.
Simply do the following:
Get-ADGroupMember -identity $ADGroup | select-object SamAccountName, Name
Or in your code snippet:
Foreach ($group in $groups) {
Get-AdGroup -identity $group | select-object Samaccountname, Name }
Of course you could add:
Get-AdGroup -identity $group | select-object Samaccountname, Name | export-csv C:\mypath\report.csv
You could run a query against the returned values using Get-ADObject since it accepts DistinguishedNames as a value and isn't limited by object class:
foreach ($Group in $Groups)
{
(Get-ADGroup $Group.GroupNames -Server contoso.com -Properties Members).Members |
ForEach-Object -Process {
Get-ADObject -Identity $_ -Properties DisplayName | Select-Object -Property DisplayName
}
}
...or, you can split the results at the desired entry:
foreach ($Group in $Groups)
{
(Get-ADGroup $Group.GroupNames -Server contoso.com -Properties Members).Members |
ForEach-Object -Process {
$_.Split(',',2).Split("=")[1]
}
}
Disclaimer: I don't have the AD Module installed on my system so I can't confirm if this is all that is needed.
The easiest way would be to expand the members property and in Get-ADGroup and then pipe it to Get-ADUser
$adUsers = Foreach ($Group in $Groups) {
Get-ADGroup $Group.GroupNames -Server contoso.com -Properties Members | Select-Object -ExpandProperty Members | Get-aduser
}
I am trying to pull a list of groups from AD that start with "pegp" and a count of how many users are in each group and performing this action in PowerShell. This script will give me a list of the all the groups, but I also need how many users are in each group:
$groups = Get-ADGroup -Filter "Name -like 'pegp*'"
$Output = forEach($group in $groups) {
Get-ADGroup -Identity $group | Select-Object name
}
$Output | Export-Csv C:\temp\file_test2.csv
I then tried this code, but it's not giving me a count of the users in each group and is actually inserting an additional row after each group name in the CSV:
$groups = Get-ADGroup -Filter "Name -like 'pegp*'"
$Output = forEach($group in $groups) {
Get-ADGroup -Identity $group | Select-Object name
(Get-ADGroupMember -Identity $group).count
}
$Output | Export-Csv C:\temp\file_test4.csv
Since I'm still new to PowerShell and programming in general, I thought I'd reach out to the well of knowledge to help me figure out where I'm going wrong. Thanks!
Your current code produces an alternating stream of 1 object with a Name property, and 1 integer, which is why Export-Csv is not producing the results you want - it's expecting uniform input.
What you'll want to do is produce 1 object with 2 properties - for that you could use the Select-Object cmdlet with a calculated property for the member count:
$groupsWithMemberCount = Get-ADGroup -Filter "Name -like 'pegp*'" |Select Name,#{Name='MemberCount';Expression={#(Get-ADGroupMember -Identity $_).Count }}
# no need to call Get-ADGroup again, we already have all the information we need
$groupsWithMemberCount |Export-Csv C:\temp\file_test4.csv -NoTypeInformation
Beware that this counts the total number of members (principals AND nested groups).
If you want only users, filter the ouput from Get-ADGroupMember based on their objectClass:
$groupsWithMemberCount = Get-ADGroup -Filter "Name -like 'pegp*'" |Select Name,#{Name='MemberCount';Expression={#(Get-ADGroupMember -Identity $_ |Where-Object objectClass -eq 'user').Count}}
I'm trying to use powershell to get a list of global groups in an OU and output the global group name, the members and the domain local groups the global group is a member of, so far I have the output below, but how do I get the output for the "member of" details
$OU = 'OU=Role Groups,OU=USG,OU=Groups,OU=xxx,OU=xxxxxx,DC=xxxxxxx,DC=xxx'
$Groups = Get-ADGroup -Filter * -SearchBase $OU
$Data = foreach ($Group in $Groups) {
Get-ADGroupMember -Identity $Group -Recursive | Select-Object #{Name='Group';Expression={$Group.Name}}, #{Name='Member';Expression={$_.Name}}
}
$Data | Export-Csv -Path "C:\Temp\FolderPermissions.csv"
Why not take a more direct approach as defined in the help files?
Get-ADGroup
Get-ADGroupMember
Get-ADGroup |
Where-Object {GroupScope -eq 'Global'} |
Get-ADGroupMember
Or
$OU = 'OU=Role Groups,OU=USG,OU=Groups,OU=xxx,OU=xxxxxx,DC=xxxxxxx,DC=xxx'
Get-ADGroup -Filter "GroupScope -eq 'Global'" -SearchBase $OU |
Get-ADGroupMember | Select-Object -Property SamAccountName
I have this script that extracts the users that belong to the groups I need.
$GroupList = Get-Content C:\Scripts\grouplist.txt
$Results = foreach ($Group in $GroupList) {
$Description = Get-ADGroup -Identity $Group -Properties Description | Select-Object -ExpandProperty Description
Get-ADGroupMember -Identity $Group |
Select-Object -Property SamAccountName, Name, #{Name='GroupName';Expression={$Group}}, #{Name='Description';Expression={$Description}}
}
$Results
$Results | Export-csv -Path C:\Scripts\SecurityGroups.csv -NoTypeInformation
The problem is that I only need users in the enabled state.
And I can't. Could you help me please?
Thanks.
As mentioned per the comments you can use the Get-Aduser cmdlet after you populated your results. Here you have to filter out groups, otherwise the cmdlet will throw exceptions for every group.
$results = #()
foreach ($group in $grouplist) {
$description = (Get-ADGroup $group -Properties description).description
$members = Get-ADGroupMember $group | ?{$_.objectClass -eq "user"} | % {Get-ADUser $_ -Properties enabled}
$results += $members | ? {$_.Enabled -eq $true } | select samaccountname, name, #{name='groupname';expression={$group}}, #{name='description';expression={$description}}
}
Alternatively, you can use LDAP-filters. This option is noticeably faster since you only make one request per group, not one per user.
$results = #()
foreach ($group in $grouplist) {
$group = Get-ADGroup $group -Properties description
$members = Get-ADUser -LDAPFilter "(&(memberof=$($group.DistinguishedName))(!(UserAccountControl:1.2.840.113556.1.4.803:=2)))"
$results += $members | select samaccountname, name, #{name='groupname';expression={$group}}, #{name='description';expression={$group.description}}
}
With LDAP-filters you could also request members of multiple groups at once, but since you want the context in which group a user was found this is not an option here..
I have Universal group with distribution scope and there are contacts and groups and users which are members of this DL. I am trying to below command but not getting details of groups or users with powershell. Those groups have groups nested within them that contain users.
How can i export nested group members and users from distribution group from AD Powershell cmdlet?
Example:
Group A
Members = asmith(Contact), jbloggs,Group B (member = kbrown)
Here is my code :
$memberof=get-adgroup -Filter "Name -like 'IT*'" |select -expandproperty distinguishedname
#$distinguishedName = $memberof -replace "(CN=)(.*?),.*",'$2'
foreach ($memberof1 in $memberof) {
$distinguishedName = $memberof1 -replace "(CN=)(.*?),.*",'$2'
Get-ADObject -Filter 'memberof -eq $memberof1 -and (objectClass -eq "user" -or ObjectClass -eq "contact" -or objectclass -eq "group")' -properties *|select name | Export-csv -Path "C:\temp\$distinguishedName.csv" -NoTypeInformation -Encoding UTF8
}
Either use Get-ADGroupMember with the -Recursive parameter switch:
$AllMembers = Get-ADGroup -Filter "Name -like 'IT*'" |Get-ADGroupMember -Recursive
or use the special in-chain operator in an LDAP query filter for the memberOf attribute:
$GroupDN = Get-ADGroup -Filter "Name -like 'IT*'" |Select -Expand DistinguishedName
$AllMembers = Get-ADUser -LDAPFilter "(memberof:1.2.840.113556.1.4.1941:=$GroupDN)"