Substring from range of two characters - swift

Question

Im trying to convert a time displaying string to a Int.
The syntax looks like this and i want to extract the integers and multiply the first and add the later to get the time in minutes.
12h 10m
3h 14m
16h 0m
Since the displayed string can be either hhmm, hmm, hhm or hm I cant substring with a fixed offset.
I'm trying to substring the string by first finding the " " and then the m.
In other languages this would be easy but for some reson I cant get it to work in swift.
Please help me, you're my only hope.

Answer 1

You can get your time components (hour and minutes) using components(separated:) and get the first component (hour), multiply it by 60 and add the last component (minutes) to it.
extension String {
var minutes: Int {
var minutes = 0
if let hourChars = components(separatedBy: " ").first?.characters.dropLast(),
let hours = Int(String(hourChars)) {
minutes += hours * 60
}
if let minChars = components(separatedBy: " ").last?.characters.dropLast(),
let mins = Int(String(minChars)) {
minutes += mins
}
return minutes
}
}
Testing
let str1 = "12h 10m"
let minutes1 = str1.minutes // 730
let str2 = "3h 14m"
let minutes2 = str2.minutes // 194
let str3 = "16h 0m"
let minutes3 = str3.minutes // 960

Answer 2

i think in your case it's better to spilt the string that you have twice
let string = "12h 10m 3h 14m 16h 0m"
var array = string.characters.split(separator: "h").map(String.init)
var result: [String] = []
array.forEach {
result.append(contentsOf: $0.characters.split(separator: "m").map(String.init))
}
// ["12", " 10", " 3", " 14", " 16", " 0"]
print(result)

Answer 3

Since you need to manipulate with date/time strings only I think you should better use a build-in DateFormatter for doing it
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "HH'h' mm'm'"
let date = dateFormatter.date(from: "2h 10m")!
let hour = Calendar.current.component(.hour, from: date)
// returns 2
let minutes = Calendar.current.component(.minute, from: date)
// returns 10

Answer 4

best solution for your question is
func getTime(time:String)->(Int,Int)
{
let arry = time.components(separatedBy: " ")
let hours = arry[0]
let min = arry[1]
let indexForHour = hours.index(hours.startIndex, offsetBy: (hours.characters.count - 1))
let indexForMin = min.index(min.startIndex, offsetBy: (min.characters.count - 1))
let hour = Int(hours.substring(to: indexForHour))
let minut = Int(min.substring(to: indexForMin))
return (hour!,minut!)
}
let str1 = "12h 10m"
let str2 = "3h 14m"
let str3 = "16h 0m"
let firstTime:(hour:Int,min:Int) = getTime(time:str1)
print(firstTime)
let secondTime:(hour:Int,min:Int) = getTime(time:str2)
print(secondTime)
let thirdTime:(hour:Int,min:Int) = getTime(time:str3)
print(thirdTime)
OUTPUT
(hour: 12, min: 10)
(hour: 3, min: 14)
(hour: 16, min: 0)