I have the following code that gets the sum of sleep hours. However, it is summing inbed and asleep together. What I am trying to get is a sum for just the asleep time.
func readSleepAnalysis(date: Date) {
if let sleepType = HKObjectType.categoryType(forIdentifier: HKCategoryTypeIdentifier.sleepAnalysis) {
let startDate = convertSleepStartDate(StartDate: date)
let endDate = convertSleepEndDate(EndDate: date)
let predicate = HKQuery.predicateForSamples(withStart: startDate, end: endDate, options: .strictStartDate)
let sortDescriptor = NSSortDescriptor(key: HKSampleSortIdentifierEndDate, ascending: false)
let query = HKSampleQuery(sampleType: sleepType, predicate: predicate, limit: 30, sortDescriptors: [sortDescriptor]) {
(query, samples, error) in
guard
error == nil,
samples == samples as? [HKCategorySample] else {
print("Something went wrong getting sleep analysis: \(String(describing: error))")
return
}
let total = samples?.map(self.calculateSleepHours).reduce(0, {$0 + $1}) ?? 0
DispatchQueue.main.async {
self.userSleepMinutes = total
print("userSleepHours = \(self.userSleepMinutes)")
}
}
healthKit.execute(query)
}
}
func calculateSleepHours(sample: HKSample) -> TimeInterval {
let hours = sample.endDate.timeIntervalSince(sample.startDate) / 60 / 60
return hours
}
I previously discovered that Apple records all data based on UTC. Make sense! However, this may work for active energy and other data like that but total sleep time can't be calculated like this. I am calculating the total time from 6 PM the night prior to 05:59 AM that day. Here is how I am doing that (there may be a better way but it's beyond me at this moment).
func convertSleepStartDate(StartDate: Date) -> Date {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyy-MM-dd '18':'00':'01' +0000"
let dateString = dateFormatter.string(from: StartDate)
dateFormatter.dateFormat = "yyy-MM-dd HH:mm:ss +0000"
let date = dateFormatter.date(from: dateString)
let datePrior = Calendar.current.date(byAdding: .hour, value: -24, to: date!)
print(datePrior as Any)
return datePrior!
}
func convertSleepEndDate(EndDate: Date) -> Date {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyy-MM-dd '17':'59':'59' +0000"
let dateString = dateFormatter.string(from: EndDate)
dateFormatter.dateFormat = "yyy-MM-dd HH:mm:ss +0000"
let date = dateFormatter.date(from: dateString)
print(date as Any)
return date!
}
Any ideas?
Better late than never: In your calculateSleepHours function, you should check sample.value against the HKCategoryValueSleepAnalysis constants (inBed, asleep, awake). That will tell you the interval's type. It will also teach you how Apple measures and returns this data. Keep an eye on the intervals, because when you hit the end of the planned sleep time on the watch, it will give you a summary of inBed time.
let value1 = (sample.value == HKCategoryValueSleepAnalysis.inBed.rawValue) ? "InBed" : "Asleep"
let value2 = (sample.value == HKCategoryValueSleepAnalysis.asleep.rawValue) ? "Asleep" : "Awake"
let value3 = (sample.value == HKCategoryValueSleepAnalysis.awake.rawValue) ? "Awake" : "Asleep"
The 3 values contain the type of constant that each interval is measuring. It is almost always asleep, but may differ depending on the Watch OS versions.
You can print the values and see, on a per interval basis, exactly what is being measured. Be sure to print the sample.startDate and sample.endDate too. That will teach you all you need to know to get actual sleep time between two Dates.
I'm trying to get the correct time interval between two times that span two days (Overnight). Here is my code successfully printing out the difference between two times - however for my use case I need the ability to span overnight, how might I do this?
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "HH:mm"
//This time represents (23:00, Aug 07) for example
let date1 = dateFormatter.date(from: "23:00")!
//This time represents (06:00, Aug 08) for example
let date2 = dateFormatter.date(from: "06:00")!
let elapsedTime = date2.timeIntervalSince(date1)
print(abs(elapsedTime)/60/60)
//prints 17.0
My desired result is a print out of 7, as that is the amount of hours between 23:00, Aug 7 and 06:00, Aug 8 - My current code is correctly showing me the interval between those two times (as if they were from the same day) but I am trying to work out how to account for when those times overlap two days. Any help would be much appreciated.
UPDATE:
To give a more complete picture I have an object that has a start and and end date represented by a string:
Activity(startTime: "23:00", endTime: "06:00")
I use some functions to turn those strings into dates:
func startDate(startTime: String) -> Date {
let currentDate = Date().string(format: "dd-MM-yyyy")
let myStartingDate = "\(currentDate) \(startTime)"
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "dd-MM-yyyy HH:mm"
let startDate = dateFormatter.date(from: myStartingDate)
return startDate!
}
func endDate(endTime: String) -> Date {
let currentDate = Date().string(format: "dd-MM-yyyy")
let myEndingDate = "\(currentDate) \(endTime)"
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "dd-MM-yyyy HH:mm"
let endDate = dateFormatter.date(from: myEndingDate)
return endDate!
}
So my more complete workings look more like this:
func calculateTimeInterval(activity: Activity) {
let startHourDate = self.startDate(startTime: activity.startTime)
let endHourDate = self.endDate(endTime: activity.endTime)
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "HH:mm"
//This time represents (23:00, Aug 07) for example
let date1 = startHourDate!
//This time represents (06:00, Aug 08) for example
let date2 = endHourDate!
let elapsedTime = date2.timeIntervalSince(date1)
print(abs(elapsedTime)/60/60)
}
//prints 17.0
Without a date part the only way to determine if the end time is past midnight is if the end time is less than the start time. If so your code can be changed to
var elapsedTime = date2.timeIntervalSince(date1)
if elapsedTime < 0 {
let date3 = date2 + 60 * 60 * 24
elapsedTime = date3.timeIntervalSince(date1)
}
print(elapsedTime/60/60)
You can write an Extension to Date like this:
extension Date {
func hours(from date: Date) -> Int {
return Calendar.current.dateComponents([.hour], from: date).hour ?? 0
}
}
And just use it on any Date directly. This way you don't need DateFormatter at all. Hope this helps!
What would be a clean way to initialise a Swift TimeZone object from timeZoneOffset string of the form: "+HH:MM".
I am looking for something of the form:
extension TimeZone {
init?(UTCOffsetString ofs: String) {
let signIndex = ofs.firstIndex(of: "+") ?? ofs.firstIndex(of: "-")
let sign = ofs[signIndex!]
let separatorIndex = ofs.firstIndex(of: ":")!
let hhRange = ofs.index(signIndex!, offsetBy: 1)..<separatorIndex
let hh = ofs[hhRange]
let mmRange = ofs.index(separatorIndex, offsetBy: 1)..<ofs.index(separatorIndex, offsetBy: 3)
let mm = ofs[mmRange]
var offsetInMin = (Int(String(hh))! * 60) + Int(String(mm))!
if sign == "-" {
offsetInMin.negate()
}
let offsetInSec = offsetInMin * 60
// Convert string to TimeZone, eg.
self.init(secondsFromGMT: offsetInSec)
}
}
let tz = TimeZone.init(UTCOffsetString: "-07:30")
print(tz?.identifier ?? "unknown")
The above code block is a correct solution and prints:
GMT-0730
However I am looking for a cleaner solution where I don't need to extract substrings in order to compute the offset.
My suggestion is to use DateFormatter which is able to parse the time zone string format. refZoneString is the reference to UTC in the current time zone.
extension TimeZone {
init?(UTCOffsetString ofs: String) {
let refZoneString = "+0000"
let formatter = DateFormatter()
formatter.dateFormat = "Z"
guard let refDate = formatter.date(from: refZoneString),
let date = formatter.date(from: ofs) else { return nil }
self.init(secondsFromGMT: Calendar.current.dateComponents([.second], from: date, to: refDate).second!)
}
}
let tz = TimeZone.init(UTCOffsetString: "-07:30")
print(tz?.identifier ?? "unknown")
I don't know what you mean by a cleaner but you can combine collection methods suffix and prefix to avoid the need to use String index to access the desired values:
let time = "-02:00"
let hours = Int(time.suffix(5).prefix(2)) ?? 0
let minutes = Int(time.suffix(2)) ?? 0
var offset = hours * 3600 + minutes * 60
if time.first == "-" { offset = -offset }
print(offset) // -7200
I am able to get current time, Now I want to output it in words.
let date = Date()
let calendar = Calendar.current
let hour = calendar.component(.hour, from: date)
let minutes = calendar.component(.minute, from: date)
let seconds = calendar.component(.second, from: date)
print("hours = \(hour):\(minutes):\(seconds)")
Output
10:30
How to get this like -
It's half past ten
As #MwcsMac points out in his answer, the key to solving this is Formatter (once known as NSFormatter), particularly by setting the .numberStyle to .spellOut.
Although this will pick up the current locale (and thus language), the trouble is that many other languages than English do not use the same "half-past", "quarter-to" terminology - for example, in German 10:30 is "halb elf", literally "half (to) eleven".
Writing code that assumes that the locale is English/American is really bad practice and will probably get the app rejected if it is offered outside those areas, so the best one could really do is format "10:30" as "ten thirty", "zehn dreißig".
Code with apologies to #MwcsMac:
import Foundation
let date = Date()
let calendar = Calendar.current
let hour = calendar.component(.hour, from: date)
let minute = calendar.component(.minute, from: date)
func spell(_ number: Int, _ localeID: String) -> String {
let formatter = NumberFormatter()
formatter.numberStyle = .spellOut
// Specify the locale or you will inherit the current default locale
formatter.locale = Locale(identifier: localeID)
if let s = formatter.string(from: NSNumber(value: number)) {
// AVOID forced unwrapping at all times!
return s
} else {
return "<Invalid>" // or make return optional and return `nil`
}
}
spell(hour, "EN") + " " + spell(minute, "EN") // "nineteen thirty-three"
spell(hour, "FR") + " " + spell(minute, "FR") // ""dix-neuf trente-trois"
spell(hour, "AR") + " " + spell(minute, "AR") // "تسعة عشر ثلاثة و ثلاثون"
This code will show you that it is possible to achieve the end goal. Keep in mind as stated above you will need create the logic for combinations that you want achieve.
Swift 3
let date = Date()
let calendar = Calendar.current
let hour = calendar.component(.hour, from: date)
let minutes = calendar.component(.minute, from: date)
let seconds = calendar.component(.second, from: date)
func spell(_ number: Int) -> String {
let formatter = NumberFormatter()
formatter.numberStyle = .spellOut // This will convert the number to words.
return formatter.string(from: NSNumber(value: number))!
}
if minutes == 30 {
let hourString = spell(hour)
print("It's half past \(hourString)")
}
This could be a way that you would use a range for the time frames.
if case 1 ... 14 = minutes {
let hourString = spell(hour) // This will give your hour in word form
let minString = spell(minutes) // This will give your minutes in word form
print("It's \(minString) past \(hourString)")
}
I have two Date Objects:
2017-01-13 11:40:17 +0000
2016-03-15 10:22:14 +0000
I need to compare just the time of these values and ignore the date
example: 12:00am and 12:01am, 12:01 is later so (12:01am > 12:00am) == true
This is the route I took in the end, which makes it easy to compare just the time of a Date in swift
New Object Time:
class Time: Comparable, Equatable {
init(_ date: Date) {
//get the current calender
let calendar = Calendar.current
//get just the minute and the hour of the day passed to it
let dateComponents = calendar.dateComponents([.hour, .minute], from: date)
//calculate the seconds since the beggining of the day for comparisions
let dateSeconds = dateComponents.hour! * 3600 + dateComponents.minute! * 60
//set the varibles
secondsSinceBeginningOfDay = dateSeconds
hour = dateComponents.hour!
minute = dateComponents.minute!
}
init(_ hour: Int, _ minute: Int) {
//calculate the seconds since the beggining of the day for comparisions
let dateSeconds = hour * 3600 + minute * 60
//set the varibles
secondsSinceBeginningOfDay = dateSeconds
self.hour = hour
self.minute = minute
}
var hour : Int
var minute: Int
var date: Date {
//get the current calender
let calendar = Calendar.current
//create a new date components.
var dateComponents = DateComponents()
dateComponents.hour = hour
dateComponents.minute = minute
return calendar.date(byAdding: dateComponents, to: Date())!
}
/// the number or seconds since the beggining of the day, this is used for comparisions
private let secondsSinceBeginningOfDay: Int
//comparisions so you can compare times
static func == (lhs: Time, rhs: Time) -> Bool {
return lhs.secondsSinceBeginningOfDay == rhs.secondsSinceBeginningOfDay
}
static func < (lhs: Time, rhs: Time) -> Bool {
return lhs.secondsSinceBeginningOfDay < rhs.secondsSinceBeginningOfDay
}
static func <= (lhs: Time, rhs: Time) -> Bool {
return lhs.secondsSinceBeginningOfDay <= rhs.secondsSinceBeginningOfDay
}
static func >= (lhs: Time, rhs: Time) -> Bool {
return lhs.secondsSinceBeginningOfDay >= rhs.secondsSinceBeginningOfDay
}
static func > (lhs: Time, rhs: Time) -> Bool {
return lhs.secondsSinceBeginningOfDay > rhs.secondsSinceBeginningOfDay
}
}
Date Extension for easy access:
//Adds ability to just get the time from a date:
extension Date {
var time: Time {
return Time(self)
}
}
Example:
let firstDate = Date()
let secondDate = firstDate
//Will return true
let timeEqual = firstDate.time == secondDate.time
Much simpler than accepted answer:
SWIFT 4
// date1 and date2 are the dates you want to compare
let calendar = Calendar.current
var newDate = Date(TimeIntervalSinceReferenceDate: 0) // Initiates date at 2001-01-01 00:00:00 +0000
var newDate1 = Date(TimeIntervalSinceReferenceDate: 0) // Same as above
// Recieving the components from the dates you want to compare
let newDateComponents = calendar.dateComponents([.hour, .minute], from: date1)!
let newDate1Components = calendar.dateComponents([.hour, .minute], from: date2)!
// Adding those components
newDate = calendar.date(byAdding: newDateComponents, to: newDate)
newDate1 = calendar.date(byAdding: newDate1Components, to: newDate1)
My approach would be to use Calendar to make them Date objects with the same day and then comparing them using for example timeIntervalSinceReferenceDate.
Another, cleaner (but most likely with more lines of resulting code) would be to create extension for Date called secondsFromBeginningOfTheDay() -> TimeInterval and then comparing the resulting double values.
Example based on the second approach:
// Creating Date from String
let textDate1 = "2017-01-13T12:21:00-0800"
let textDate2 = "2016-03-06T20:12:05-0900"
let dateFormatter: DateFormatter = {
let formatter = DateFormatter()
formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ssZZZ"
formatter.timeZone = TimeZone.current
return formatter
} ()
// Dates used for the comparison
let date1 = dateFormatter.date(from: textDate1)
let date2 = dateFormatter.date(from: textDate2)
// Date extensions
extension Date {
func secondsFromBeginningOfTheDay() -> TimeInterval {
let calendar = Calendar.current
// omitting fractions of seconds for simplicity
let dateComponents = calendar.dateComponents([.hour, .minute, .second], from: self)
let dateSeconds = dateComponents.hour! * 3600 + dateComponents.minute! * 60 + dateComponents.second!
return TimeInterval(dateSeconds)
}
// Interval between two times of the day in seconds
func timeOfDayInterval(toDate date: Date) -> TimeInterval {
let date1Seconds = self.secondsFromBeginningOfTheDay()
let date2Seconds = date.secondsFromBeginningOfTheDay()
return date2Seconds - date1Seconds
}
}
if let date1 = date1, let date2 = date2 {
let diff = date1.timeOfDayInterval(toDate: date2)
// as text
if diff > 0 {
print("Time of the day in the second date is greater")
} else if diff < 0 {
print("Time of the day in the first date is greater")
} else {
print("Times of the day in both dates are equal")
}
// show interval as as H M S
let timeIntervalFormatter = DateComponentsFormatter()
timeIntervalFormatter.unitsStyle = .abbreviated
timeIntervalFormatter.allowedUnits = [.hour, .minute, .second]
print("Difference between times since midnight is", timeIntervalFormatter.string(from: diff) ?? "n/a")
}
// Output:
// Time of the day in the second date is greater
// Difference between times since midnight is 8h 51m 5s
My solution for comparing two times of day while ignoring the date:
let date1 = some time as a date
let date2 = some other time as a date
let time1 = 60*Calendar.current.component(.hour, from: date1!) + Calendar.current.component(.minute, from: date1!)
let time2 = 60*Calendar.current.component(.hour, from: date2!) + Calendar.current.component(.minute, from: date2!)
Now you can compare the integers time1 and time2 without regard to the day. You could add the seconds/60 if you need more precision.
This code works, check it easily in playground
let s1 = "22:31"
let s2 = "14:31"
let f = DateFormatter()
f.dateFormat = "HH:mm"
f.date(from: s1)! //"Jan 1, 2000 at 10:31 PM"
f.date(from: s2)! //"Jan 1, 2000 at 2:31 PM"
f.date(from: s1)! > f.date(from: s2)! // true
There's no standard type for a time-of-day. A reasonable type to start with is just a tuple:
typealias TimeOfDay = (hour: Int, minute: Int, second: Int)
To create these TimeOfDay values, you'll need a Calendar. By default, a Calendar uses the device's system-wide time zone. If you don't want that, set the Calendar's time zone explicitly. Example:
var calendar = Calendar.autoupdatingCurrent
calendar.timeZone = TimeZone(abbreviation: "UTC")!
Now you can use a DateFormatter to convert strings to Dates (if necessary), and then use calendar to extract the time-of-day components from the Dates:
let strings: [String] = ["2017-01-13 11:40:17 +0000", "2016-03-15 10:22:14 +0000"]
let parser = DateFormatter()
parser.dateFormat = "yyyy-MM-dd HH:mm:ss Z"
let timesOfDay: [TimeOfDay] = strings.map({ (string) -> TimeOfDay in
let components = calendar.dateComponents([.hour, .minute, .second], from: parser.date(from: string)!)
return (hour: components.hour!, minute: components.minute!, second: components.second!)
})
Swift.print(timesOfDay)
// Output: [(11, 40, 17), (10, 22, 14)]
Finally, you can compare these TimeOfDay values. Swift comes with standard comparison operators for tuples whose elements are Comparable, so this TimeOfDay type qualifies. You can just say this:
if timesOfDay[0] < timesOfDay[1] {
Swift.print("date[0] comes first")
} else if timesOfDay[0] == timesOfDay[1] {
Swift.print("times are equal")
} else {
Swift.print("date[1] comes first")
}
Let say we got two dates in string format:
// "2017-01-13 11:40:17 +0000"
// "2016-03-15 10:22:14 +0000"
We need to convert this strings to Date format, we create DateFormatter() and set the format ("yyyy-MM-dd' 'HH:mm:ssZ") it gonna convert
//date formatter converts string to date in our case
let firstDateFormatter = DateFormatter()
firstDateFormatter.dateFormat = "yyyy-MM-dd' 'HH:mm:ssZ"
Now we can get our date from string to Date format
//convert string to dates
if let date1 = firstDateFormatter.date(from: "2017-01-13 09:40:17 +0000"),
let date2 = firstDateFormatter.date(from: "2016-03-15 10:22:14 +0000") {
What we want is to compare only Hours and Minutes. So change dateformat to "HH:mm"
//we ve got the dates, now switch dateformat for other job
firstDateFormatter.dateFormat = "HH:mm"
Now get the string value from our date, that only contain "HH:mm"
// convert date to string ( part of string we want to compare )
let HHmmDate1 = firstDateFormatter.string(from: date1) //"17:40"
let HHmmDate2 = firstDateFormatter.string(from: date2) //"18:22"
Final step is to get date from our "HH:mm" values, let say we ask DateFormatter to give us a date, based on time only, in our case "17:40" and "18:22". DateFormatter will put some values for dates, so we get Jan 1, 2000 automatically for both dates, but it will get the time we provide.
//produce "default" dates with desired HH:mm
//default means same date, but time is different
let HH1 = firstDateFormatter.date(from: HHmmDate1) //"Jan 1, 2000 at 5:40 PM"
let HH2 = firstDateFormatter.date(from: HHmmDate2) //"Jan 1, 2000 at 6:22 PM"
Now we could easily compare dates
//compare
HH1! > HH2!
}
There are many options to compare dates with Calendar also
This is very simple in Swift if you use Swifter Swift
date1.day = 1
date1.month = 1
date1.year = 2000
date2.day = 1
date2.month = 1
date2.year = 2000
now you can use >,<,== operators on date1 and date2 to compare just the time components.
edit - you could do this your self by extending the date class, for example swifter-swift does the bellow for the day component.
public var day: Int {
get {
return Calendar.current.component(.day, from: self)
}
set {
let allowedRange = Calendar.current.range(of: .day, in: .month, for: self)!
guard allowedRange.contains(newValue) else { return }
let currentDay = Calendar.current.component(.day, from: self)
let daysToAdd = newValue - currentDay
if let date = Calendar.current.date(byAdding: .day, value: daysToAdd, to: self) {
self = date
}
}
}