How can I use Swift’s Codable to encode into a dictionary? - swift

Question

I have a struct that implements Swift 4’s Codable. Is there a simple built-in way to encode that struct into a dictionary?
let struct = Foo(a: 1, b: 2)
let dict = something(struct)
// now dict is ["a": 1, "b": 2]

Answer 1

If you don't mind a bit of shifting of data around you could use something like this:
extension Encodable {
func asDictionary() throws -> [String: Any] {
let data = try JSONEncoder().encode(self)
guard let dictionary = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? [String: Any] else {
throw NSError()
}
return dictionary
}
}
Or an optional variant
extension Encodable {
var dictionary: [String: Any]? {
guard let data = try? JSONEncoder().encode(self) else { return nil }
return (try? JSONSerialization.jsonObject(with: data, options: .allowFragments)).flatMap { $0 as? [String: Any] }
}
}
Assuming Foo conforms to Codable or really Encodable then you can do this.
let struct = Foo(a: 1, b: 2)
let dict = try struct.asDictionary()
let optionalDict = struct.dictionary
If you want to go the other way(init(any)), take a look at this Init an object conforming to Codable with a dictionary/array

Answer 2

Here are simple implementations of DictionaryEncoder / DictionaryDecoder that wrap JSONEncoder, JSONDecoder and JSONSerialization, that also handle encoding / decoding strategies…
class DictionaryEncoder {
private let encoder = JSONEncoder()
var dateEncodingStrategy: JSONEncoder.DateEncodingStrategy {
set { encoder.dateEncodingStrategy = newValue }
get { return encoder.dateEncodingStrategy }
}
var dataEncodingStrategy: JSONEncoder.DataEncodingStrategy {
set { encoder.dataEncodingStrategy = newValue }
get { return encoder.dataEncodingStrategy }
}
var nonConformingFloatEncodingStrategy: JSONEncoder.NonConformingFloatEncodingStrategy {
set { encoder.nonConformingFloatEncodingStrategy = newValue }
get { return encoder.nonConformingFloatEncodingStrategy }
}
var keyEncodingStrategy: JSONEncoder.KeyEncodingStrategy {
set { encoder.keyEncodingStrategy = newValue }
get { return encoder.keyEncodingStrategy }
}
func encode<T>(_ value: T) throws -> [String: Any] where T : Encodable {
let data = try encoder.encode(value)
return try JSONSerialization.jsonObject(with: data, options: .allowFragments) as! [String: Any]
}
}
class DictionaryDecoder {
private let decoder = JSONDecoder()
var dateDecodingStrategy: JSONDecoder.DateDecodingStrategy {
set { decoder.dateDecodingStrategy = newValue }
get { return decoder.dateDecodingStrategy }
}
var dataDecodingStrategy: JSONDecoder.DataDecodingStrategy {
set { decoder.dataDecodingStrategy = newValue }
get { return decoder.dataDecodingStrategy }
}
var nonConformingFloatDecodingStrategy: JSONDecoder.NonConformingFloatDecodingStrategy {
set { decoder.nonConformingFloatDecodingStrategy = newValue }
get { return decoder.nonConformingFloatDecodingStrategy }
}
var keyDecodingStrategy: JSONDecoder.KeyDecodingStrategy {
set { decoder.keyDecodingStrategy = newValue }
get { return decoder.keyDecodingStrategy }
}
func decode<T>(_ type: T.Type, from dictionary: [String: Any]) throws -> T where T : Decodable {
let data = try JSONSerialization.data(withJSONObject: dictionary, options: [])
return try decoder.decode(type, from: data)
}
}
Usage is similar to JSONEncoder / JSONDecoder…
let dictionary = try DictionaryEncoder().encode(object)
and
let object = try DictionaryDecoder().decode(Object.self, from: dictionary)
For convenience, I've put this all in a repo… https://github.com/ashleymills/SwiftDictionaryCoding

Answer 3

I have create a library called CodableFirebase and it's initial purpose was to use it with Firebase Database, but it does actually what you need: it creates a dictionary or any other type just like in JSONDecoder but you don't need to do the double conversion here like you do in other answers. So it would look something like:
import CodableFirebase
let model = Foo(a: 1, b: 2)
let dict = try! FirebaseEncoder().encode(model)

Answer 4

There is no built in way to do that.
As answered above if you have no performance issues then you can accept the JSONEncoder + JSONSerialization implementation.
But I would rather go the standard library's way to provide an encoder/decoder object.
class DictionaryEncoder {
private let jsonEncoder = JSONEncoder()
/// Encodes given Encodable value into an array or dictionary
func encode<T>(_ value: T) throws -> Any where T: Encodable {
let jsonData = try jsonEncoder.encode(value)
return try JSONSerialization.jsonObject(with: jsonData, options: .allowFragments)
}
}
class DictionaryDecoder {
private let jsonDecoder = JSONDecoder()
/// Decodes given Decodable type from given array or dictionary
func decode<T>(_ type: T.Type, from json: Any) throws -> T where T: Decodable {
let jsonData = try JSONSerialization.data(withJSONObject: json, options: [])
return try jsonDecoder.decode(type, from: jsonData)
}
}
You can try it with following code:
struct Computer: Codable {
var owner: String?
var cpuCores: Int
var ram: Double
}
let computer = Computer(owner: "5keeve", cpuCores: 8, ram: 4)
let dictionary = try! DictionaryEncoder().encode(computer)
let decodedComputer = try! DictionaryDecoder().decode(Computer.self, from: dictionary)
I am force-trying here to make the example shorter. In production code you should handle the errors appropriately.

Answer 5

I'm not sure if it's the best way but you definitely can do something like:
struct Foo: Codable {
var a: Int
var b: Int
init(a: Int, b: Int) {
self.a = a
self.b = b
}
}
let foo = Foo(a: 1, b: 2)
let dict = try JSONDecoder().decode([String: Int].self, from: JSONEncoder().encode(foo))
print(dict)

Answer 6

let dict = try JSONSerialization.jsonObject(with: try JSONEncoder().encode(struct), options: []) as? [String: Any]

Answer 7

I have modified the PropertyListEncoder from the Swift project into a DictionaryEncoder, simply by removing the final serialisation from dictionary into binary format. You can do the same yourself, or you can take my code from here
It can be used like this:
do {
let employeeDictionary: [String: Any] = try DictionaryEncoder().encode(employee)
} catch let error {
// handle error
}

Answer 8

In some project, i'm used the swift reflection. But be careful, nested codable objects, are not mapped also there.
let dict = Dictionary(uniqueKeysWithValues: Mirror(reflecting: foo).children.map{ ($0.label!, $0.value) })

Answer 9

I definitely think that there's some value in just being able to use Codable to encode to/from dictionaries, without the intention of ever hitting JSON/Plists/whatever. There are plenty of APIs which just give you back a dictionary, or expect a dictionary, and it's nice to be able to interchange them easily with Swift structs or objects, without having to write endless boilerplate code.
I've been playing round with some code based on the Foundation JSONEncoder.swift source (which actually does implement dictionary encoding/decoding internally, but doesn't export it).
The code can be found here: https://github.com/elegantchaos/DictionaryCoding
It's still quite rough, but I've expanded it a bit so that, for example, it can fill in missing values with defaults when decoding.

Answer 10

Here is a protocol based solution:
protocol DictionaryEncodable {
func encode() throws -> Any
}
extension DictionaryEncodable where Self: Encodable {
func encode() throws -> Any {
let jsonData = try JSONEncoder().encode(self)
return try JSONSerialization.jsonObject(with: jsonData, options: .allowFragments)
}
}
protocol DictionaryDecodable {
static func decode(_ dictionary: Any) throws -> Self
}
extension DictionaryDecodable where Self: Decodable {
static func decode(_ dictionary: Any) throws -> Self {
let jsonData = try JSONSerialization.data(withJSONObject: dictionary, options: [])
return try JSONDecoder().decode(Self.self, from: jsonData)
}
}
typealias DictionaryCodable = DictionaryEncodable & DictionaryDecodable
And here is how to use it:
class AClass: Codable, DictionaryCodable {
var name: String
var age: Int
init(name: String, age: Int) {
self.name = name
self.age = age
}
}
struct AStruct: Codable, DictionaryEncodable, DictionaryDecodable {
var name: String
var age: Int
}
let aClass = AClass(name: "Max", age: 24)
if let dict = try? aClass.encode(), let theClass = try? AClass.decode(dict) {
print("Encoded dictionary: \n\(dict)\n\ndata from decoded dictionary: \"name: \(theClass.name), age: \(theClass.age)\"")
}
let aStruct = AStruct(name: "George", age: 30)
if let dict = try? aStruct.encode(), let theStruct = try? AStruct.decode(dict) {
print("Encoded dictionary: \n\(dict)\n\ndata from decoded dictionary: \"name: \(theStruct.name), age: \(theStruct.age)\"")
}

Answer 11

I wrote a quick gist to handle this (not using the Codable protocol). Be careful, it doesn't type-check any values and doesn't work recursively on values that are encodable.
class DictionaryEncoder {
var result: [String: Any]
init() {
result = [:]
}
func encode(_ encodable: DictionaryEncodable) -> [String: Any] {
encodable.encode(self)
return result
}
func encode<T, K>(_ value: T, key: K) where K: RawRepresentable, K.RawValue == String {
result[key.rawValue] = value
}
}
protocol DictionaryEncodable {
func encode(_ encoder: DictionaryEncoder)
}

Answer 12

There no straight forward way of doing this in Codable. You need to implement Encodable/Decodable protocol for your struct. For your example, you might need to write as below
typealias EventDict = [String:Int]
struct Favorite {
var all:EventDict
init(all: EventDict = [:]) {
self.all = all
}
}
extension Favorite: Encodable {
struct FavoriteKey: CodingKey {
var stringValue: String
init?(stringValue: String) {
self.stringValue = stringValue
}
var intValue: Int? { return nil }
init?(intValue: Int) { return nil }
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: FavoriteKey.self)
for eventId in all {
let nameKey = FavoriteKey(stringValue: eventId.key)!
try container.encode(eventId.value, forKey: nameKey)
}
}
}
extension Favorite: Decodable {
public init(from decoder: Decoder) throws {
var events = EventDict()
let container = try decoder.container(keyedBy: FavoriteKey.self)
for key in container.allKeys {
let fav = try container.decode(Int.self, forKey: key)
events[key.stringValue] = fav
}
self.init(all: events)
}
}

Answer 13

I have made a pod here https://github.com/levantAJ/AnyCodable to facilitate decode and encode [String: Any] and [Any]
pod 'DynamicCodable', '1.0'
And you are able to decode & encode [String: Any] and [Any]
import DynamicCodable
struct YourObject: Codable {
var dict: [String: Any]
var array: [Any]
var optionalDict: [String: Any]?
var optionalArray: [Any]?
enum CodingKeys: String, CodingKey {
case dict
case array
case optionalDict
case optionalArray
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
dict = try values.decode([String: Any].self, forKey: .dict)
array = try values.decode([Any].self, forKey: .array)
optionalDict = try values.decodeIfPresent([String: Any].self, forKey: .optionalDict)
optionalArray = try values.decodeIfPresent([Any].self, forKey: .optionalArray)
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
try container.encode(dict, forKey: .dict)
try container.encode(array, forKey: .array)
try container.encodeIfPresent(optionalDict, forKey: .optionalDict)
try container.encodeIfPresent(optionalArray, forKey: .optionalArray)
}
}

Answer 14

After research, we find that if we use the keyword Any in the class which is inherited from the Codable & Decodable it will give the error. So if you want to use a dictionary user with the types of data coming from the server.
For example, the server is sending the dictionary of type [String : Int] then use [String : Int] if you will try [String : Any] it will not work.

Answer 15

Here is dictionary -> object. Swift 5.
extension Dictionary where Key == String, Value: Any {
func object<T: Decodable>() -> T? {
if let data = try? JSONSerialization.data(withJSONObject: self, options: []) {
return try? JSONDecoder().decode(T.self, from: data)
} else {
return nil
}
}
}

Answer 16

Come to think of it, the question does not have an answer in the general case, since the Encodable instance may be something not serializable into a dictionary, such as an array:
let payload = [1, 2, 3]
let encoded = try JSONEncoder().encode(payload) // "[1,2,3]"
Other than that, I have written something similar as a framework.