I've looked into the underscore for drop/cut, but this only seems to remove the first or last n entries, not characters. Any ideas?
Depends on what you're using drop cut on.
Can you provide an example of your values?
Below shows how cut can be used on a sting and then a list of strings.
It uses each right to drop a value from each item.
http://code.kx.com/q/ref/adverbs/#each-right
q)1_"12456789"
"2456789"
q)
q)1_("12456789";"12456789")
"12456789"
q)
q)1_/:("12456789";"12456789")
"2456789"
"2456789"
#Connor Gervin had almost what I wanted, but if you want to cast back to a string, you can use `$(-3)_'string sym from tab
Related
I have a list, and I need to take only first words including numbers of every row without anything after numbers. How can I achieve that?
A pic is provided
For example:
I have a row like this:
ЛУ 344 ул.Яссауй в районе дома №163 северном направление
As a result I want to get:
ЛУ 344
Left, right won't help because the number of characters can change.
You can use a regex based substring() variant:
substring(the_column from '\w+\s+[0-9]+')
This will extract the first "word characters" followed by one or more spaces followed by one or more numbers
Online example
Maybe split_part() will help.
Or the string_to_array()
Or the substring()
Depends on the use you want and the way you want to get the substring.
I have a field with the following types of string
X000233756_9981900025_201901_EUR_/
I firstly need to take take the characters to the left of the first _
Secondly I need to take the characters between the first and 2nd _
First _ is CHARINDEX('_',[Line_Item_Text],1) AS Position_1
Second _ is CHARINDEX('_',[Line_Item_Text],CHARINDEX('_',[Line_Item_Text],1)+1) AS Position_2
I was then expecting to be able to do
left([Line_Item_Text],CHARINDEX('_',[Line_Item_Text],1)-1) AS Data_1
Substring([Line_Item_Text],CHARINDEX('_',[Line_Item_Text],1)+1),CHARINDEX('_',[Line_Item_Text],CHARINDEX('_',[Line_Item_Text],1)+1) - CHARINDEX('_',[Line_Item_Text],1)+1)) AS Data_2"
Which should give me
X000233756
9981900025
But getting errors with incorrect number of functions when I start adding and subtracting from CHARINDEX Function.
Any ideas where I am going wrong?
TIA
Geoff
Actually, using the base string functions here is going to be an ugly nightmare. You might find that STRING_SPLIT along with some clever logic might be easier:
SELECT value
FROM STRING_SPLIT('X000233756_9981900025_201901_EUR_', '_')
WHERE LEN(value) > 6 AND NOT value LIKE '[A-Z]%';
This answer assumes that the third and fourth components would always be a 6 digit date and 3 letter currency code, and that the first (but not second) component would always start with some letter.
Demo
I'm currently working with postgresql, I learned about this function btrim, I checked many websites for explanation, but I don't really understand.
Here they mention this example:
btrim('xyxtrimyyx', 'xyz')
It gives trim.
When I try this example:
btrim('xyxtrimyyx', 'yzz')
or
btrim('xyxtrimyyx', 'y')
I get this: xyxtrimyyx
I don't understand this. Why didn't it remove the y?
From the docs you point to, the definition says:
Remove the longest string consisting only of characters in characters
(a space by default) from the start and end of string
The reason your example doesn't work is because the function tries to strip the text from Both sides of the text, consisting only of the characters specified
Lets take a look at the first example (from the docs):
btrim('xyxtrimyyx', 'xyz')
This returns trim, because it goes through xyxtrimyyx and gets up to the t and doesn't see that letter in xyz, so that is where the function stops stripping from the front.
We are now left with trimyyx
Now we do the same, but from the end of the string.
While one of xyz is the last letter, remove that letter.
We do this until m, so we are left with trim.
Note: I have never worked with any form of sql. I could be wrong about the exact way that postgresql does this, But I am fairly certain from the docs that this is how it is done.
I am trying to create a filter where I am looking for the first (or last) occurrence of an underscore (or it can be any character) and then start from there to look for the 5th character.
I am thinking of something along the lines of either right or left char index picking a side to start on. Really trying to look for a good explanation of why your answer is written in that manner.
Example: I am looking for __poptarts_________.
So I would want it to start at the leftmost _ and search for the 5th character after that (p).
You could achieve that by using both SUBSTRING and CHARINDEX
SELECT SUBSTRING (string,(CHARINDEX('_',string,0)+1),5)
In your case which would be:
SELECT SUBSTRING ('I am looking for __poptarts_________',(CHARINDEX('_','I am looking for __poptarts_________',0)+1),5)
Result is _popt because you put two '_' before 'p'
I'm typing up a table with org mode, where the equal sign(=) if the first character in the cell and it want to start a formula. how do I get it to display the symbol without it being a formula, of a way to use formulas to display it. I get errors when I use single quotes, and I see the Unicode decimal value when using double quotes.
I have tried the following
='=+'
="=+"
they give
#ERROR
[61, 43]
Use an escaped entity, \equal{} and it should display as you wish. See the variable org-entities for others you can use.
I'm a bit late :D
There may be a better way, but you can try with :='(format "=+")
Source: https://emacs.stackexchange.com/questions/19183/can-i-use-formula-to-manipulate-text-in-org-mode-table
When I ran into this problem just now, I found that I was able to get around it by replacing the equals sign with some other similar-looking character. Two which come to mind are ꞊ ‘U+A78A MODIFIER LETTER SHORT EQUALS SIGN’ and ⹀ ‘U+2E40 DOUBLE HYPHEN’.