My selection formula it works fine, but it shows a $ symbol before amounts. How can I remove this?
if {tblComparativeBalance.iAcctLevel} - {##highest_level} = 0
then if Sum ({tblComparativeBalance.mBalance_amt0}, {tblComparativeBalance.sAccount_cd}) > 0
then ToText(Sum ({tblComparativeBalance.mBalance_amt0}, {tblComparativeBalance.sAccount_cd}),2)
else "(" + ToText(abs(Sum ({tblComparativeBalance.mBalance_amt0}, {tblComparativeBalance.sAccount_cd})),2) + ")"
else ""
You have to right-click on this formula field on your layout, then choose Format Field...
In the number tab, un-check the Display Currency Symbol, then click OK
But since in your formula you are converting it to string, you have to edit your formula to the following:
ToText(Sum ({tblComparativeBalance.mBalance_amt0},{tblComparativeBalance.sAccount_cd}),2, "")
The last parameter is the Character of the Currency symbol, so in this case you are setting it to empty, means no currency symbol.
Same thing is applied to the else formula.
"(" + ToText(abs(Sum ({tblComparativeBalance.mBalance_amt0}, {tblComparativeBalance.sAccount_cd})),2, "") + ")"
If you need to remove it from Strings, you can use:
REPLACE( {yourStringHere} ,"$","")
Convert the number to number first, then text:
ToText(ToNumber({YOUR_VALUE}))````
Related
I have a super simple formula. The problem is that sometimes the data doesn't have a second value, or sometimes the value is blank.
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
ID
111 222
123
123 222
I was thinking if I could come up with some logic to figure out whether the string has multiple value's it would solve my problem, but haven't quiet found what I'm looking for:
If {PO_RECEIVE.VENDOR_LOT_ID} = SingleOrBlankString then
{PO_RECEIVE.VENDOR_LOT_ID} else
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
Better Example Data:
3011111*42011111111
2711 00291111111
711111//12111111111
/J1111 69111111111
170111
If the string can contain a maximum of two values, separated by a space, then you can check if the string contains a space using the InStr function:
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
{PO_RECEIVE.VENDOR_LOT_ID}
Else
Split ({PO_RECEIVE.VENDOR_LOT_ID}," ")[2]
If there can be multiple spaces between the parts you can use following formulas to get the values:
Left part:
This function returns the left part of the string until the first space.
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
Left({PO_RECEIVE.VENDOR_LOT_ID}, InStr({PO_RECEIVE.VENDOR_LOT_ID}, " "))
Right part:
This function returns the right part of the string after the last space.
The InStrRev-function returns the position of the last space because it searches the string backwards.
The Len-function returns the length of the string.
[length] - [position of last space] = [length of the right part]
If InStr({PO_RECEIVE.VENDOR_LOT_ID}, " ") > 0 Then
Right({PO_RECEIVE.VENDOR_LOT_ID}, Len({PO_RECEIVE.VENDOR_LOT_ID}) - InStrRev(testString, " "))
I have a column of strings that look like this:
Target Host: dcmxxxxxxc032.erc.nam.fm.com Target Name:
dxxxxxxgsc047.erc.nam.fm.com Filesystem /u01 has 4.98% available space
- fallen below warning (20) or critical (5) threshold.
The column name is [Description]
The substring I would like returned is (dxxxxxxgsc047.erc.nam.fm.com)
The only consistency in this data is that the desired string occurs between the 5th and 6th occurrences of spaces " " in the string, and after the phrase "Target Name: " The length of the substring varies, but it always ends in another " ", hence my attempt to grab the substring between the 5th and 6th spaces.
I have tried
MID([Description],((FIND([Description],"Target Name: "))+13),FIND([Description]," ",((FIND([Description],"Target Name"))+14)))
But that does not work.
(Edit: We use Tableau 8.2, the Tableau 9 only functions can't be part of the solution, thanks though!)
Thank you in advance for your help.
In Tableau 9 you can use regular expressions in formulas, it makes the task simpler:
REGEXP_EXTRACT([Description], "Target Name: (.*?) ")
Alternatively in Tableau 9 you can use the new FINDNTH function:
MID(
[Description],
FINDNTH([Description]," ", 5) + 1,
FINDNTH([Description]," ", 6) - FINDNTH([Description]," ", 5) - 1
)
Prior to Tableau 9 you'd have to use string manipulation methods similar to what you've tried, just need to be very careful with arithmetic and providing the right arguments (the third argument in MID is length, not index of the end character, so we need to subtract the index of the start character):
MID(
[Description]
, FIND([Description], "Target Name:") + 13
, FIND([Description], " ", FIND([Description], "Target Name:") + 15)
- (FIND([Description], "Target Name:") + 13)
)
Well, you need to find "Target name: " and then the " " after it, not so hard. I'll split in 3 fields just to be more clear (you can mix everything in a single field). BTW, you were in the right direction, but the last field on MID() should be the string length, not the char position
[start]:
FIND([Description],"Target name: ")+13
[end]:
FIND([Description]," ",[start])
And finally what you need:
MID([Description],[start]+1,[end]-[start]-1)
This should do. If you want to pursue the 5th and 6th " " approach, I would recommend you to find each of the " " until the 6th.
[1st]:
FIND([Description], " ")
[2nd]:
FIND([Description], " ",[1st] + 1)
And so on. Then:
MID([Description],[5th]+1,[6th]-[5th]-1)
A simple solution -
SPLIT( [Description], " ", 3 )
This returns a substring from the Description string, using the space delimiter character to divide the string into a sequence of tokens.
The string is interpreted as an alternating sequence of delimiters and
tokens. So for the string abc-defgh-i-jkl, where the delimiter
character is ‘-‘, the tokens are abc, defgh, i and jlk. Think of these
as tokens 1 through 4. SPLIT returns the token corresponding to the
token number. When the token number is positive, tokens are counted
starting from the left end of the string; when the token number is
negative, tokens are counted starting from the right. -
Tableau String Functions
I don't know Tableau, but perhaps something like this?
MID(
MID([Description], FIND([Description],"Target Name: ") + 13, 50),
1,
FIND(MID([Description], FIND([Description],"Target Name: ") + 13, 50), " ")
)
Similar to my first question. I want to show my address in a text box containing the fields as follows
{Company}
{AddLine1}
{AddLine2}
{ZIP}{State}{City}
{Country}
The line that concerns me (and hopefully some of you guys) is {ZIP} {City} {State}. What I want to produce is a consistent addressing format, so that there will be no blank space or indentation even if a ZIP, City or State field has been left blank in the DB. This line should still line up with the rest of the rows and not be indented. I also wish to insert commas between zip, state, city where they are relevant and leave them out where not. For this I have written a formula. Below:
If isnull({BILL_TO.ZIP}) or trim({BILL_TO.ZIP})= "" Then "" else {BILL_TO.ZIP}
+
(If isnull({BILL_TO.State}) or trim({BILL_TO.State})= "" Then ""
else(If not isnull({BILL_TO.ZIP}) and length(trim({BILL_TO.ZIP})) <> 0 Then ", " else "") + {BILL_TO.State})
+
(If isnull({BILL_TO.CITY}) or length(trim({BILL_TO.CITY})) = 0 Then ""
else(
If (not isnull({BILL_TO.State}) and length(trim({BILL_TO.State})) <> 0)
or
(not isnull({BILL_TO.Zip}) and length(trim({BILL_TO.Zip})) <> 0)
Then ", " else "")+ {BILL_TO.CITY}))
The problem is that when there is only a city (no state or zip entered) the formula itself will not display. It does however display when the others are present.
Can anyone see a bug in this code??? Its killing me
Thanks for the help.
Look forward to hearing from you guys!
There are a whole lot of if-then-elses going on in that formula so it's hard to tell, but if it's not displaying anything that probably means that you're using a field somewhere without handling its null condition first. Something simpler might be your best bet:
local stringvar output;
if not(isnull({Customer.Postal Code})) then output:=trim({Customer.Postal Code}) + ', ';
if not(isnull({Customer.Region})) then output:=output + trim({Customer.Region}) + ', ';
if not(isnull({Customer.City})) then output:=output + trim({Customer.City}) + ', ';
left(output,length(output)-2)
Create a formula field for each database field. For example:
// {#CITY}
If Isnull({BILL_TO.CITY}) Then
""
Else
Trim({BILL_TO.CITY})
// {#STATE}
If Isnull({BILL_TO.STATE}) Then
Space(2)
Else
Trim({BILL_TO.STATE})
// {#ZIP}
If Isnull({BILL_TO.ZIP}) Then
Space(5) //adjust to meet your needs
Else
Trim({BILL_TO.ZIP})
Embed each formula field in a text object.
Format text object and its fields to meet your need.
** edit **
I you have data-quality issues, address them in the STATE and ZIP formulas (because they will be a constant length). I would add the commas and spacing the text object.
I have a text field that has the following expression:
$F{casNo} + " Total " + $P{chosenUom} + ": " + $V{total_COUNT}
casNo is a string, chosenUom is a string. total_COUNT is a sum variable of doubles. The total_COUNT variable displays, but it's got 8 - 10 decimal places (1.34324255234), all I need is something along the lines of 1.34.
Here's what I tried already:
$F{casNo} + " Total " + $P{chosenUom} + ": " + new DecimalFormat("0.00").format($V{total_COUNT}).toString()
Any help would be appreciated
For now I'm just doing basic math, but I'm hoping for a real solution, not a workaround
((int)($V{total_COUNT}*100.0))/100.0
You can format the in lline numbers by using:
new DecimalFormat("###0.00").format(YOUR NUMBER)
You might split the text field into two, one containing everything but the $V{total_COUNT}, and the second containing only $V{total_COUNT}, but with the Pattern property set to something like "#0.00".
You'd have to get a bit creative with layout, though, to prevent unwanted word-wrapping and spacing; for example, first text field could be wide and right-aligned, while text field containing the count could be left-aligned and wide enough to accommodate the formatted number.
I am using this following text to delete brackets and text inside the brackets; I need to go threw the entire memo field and it stops after it finds and deletes the first set of brackets and text.
if right({table.col},1) = "]" then
left({table.col},instr({table.col},"[")-1)
else
{table.col}
Any suggestions...
This tested well with Crystal2008, not sure what version you are using, it also would need some error checking to handle mismatched bracket pairs, but it may offer some food for thought:
Dim workString as String
Dim bracketedText as string
if (InStr({table.col},"[") > 0) then
workString = {table.col}
while(InStr(workString,"[") > 0 )
bracketedText = "[" + ExtractString(workString,"[","]") + "]"
workString = replace(workString,bracketedText,"")
Wend
Formula = workString
else
Formula = {table.col}
End If