Whatsup guys
I am struggling with an issue which is displaying errors on appended inputs in a form after submit. I guess there is a simple solution on this which i dont know of because i am a newbie in Laravel.
Scenario:
I have a form where a user needs to select a category and depending on the selection, a few inputs should be appended (with ajax) into the same form below the category dropdown. I have set up the validations and the error rendering on the html but it doesnt seem to work yet the request doesnt pass since it detects the validations.
Any clues?
You will not be able to display the errors next to form inputs that have been retrieved with Ajax. However, you may use an error box at the top of the screen describing the problem. Or you may simply post the form using Ajax instead of a page refresh, then using JavaScript, you can display the errors to the appended input.
If this is not an answer to the question you are asking, please provide code and more details.
Related
I have a submit form that is once displayed in a PopUp and once shown normal on the page. So I created it in a storage folder and used "insert record" for said plugin twice.
When I submit one of the shown forms, it will be executed twice. Anyone ever had this kind of problem?
The contact request form is selfmade.
You need to distinct your two plugins from each other. I assume you have two times the same plugin on the same page. If you submit your form, both of the plugins respond to the request, because they both feel responsible for it.
If you could give one of the plugins a different name, it would just respond to its own form, and the other plugin would not respond to the other plugins form.
try to modify your plugin so you can configure it to only show the form.then you use two different CEs: one to show only the form, the second to show the form and to handle the submit.
Other possibility: while you are handling the form store the information about handling somewhere and avoid a second handling on the same call
I have form that can be used on front page and search page. Users can fill it on both pages, but if it is filled on front page it has to show filled data on the search page. to achieve this I'm forwarding the data, and using syntax similar to this.
$form->get('field')->setData($form_data['field']);
Everything works fine, except the form has a lot of fields and I was wondering if there is a shorter way to achieve the same?
What about this?
$form_data['return_box'] = (boolean)$form_data['return_box'];
$form->setData($form_data);
I am creating a Google Form. I want to insert a count in the end(anywhere,not specific) of the form which will show the number of responses submit till date.This goes like updating the live count. I have tried using script editor for Google Form Add-ons option.But I am unable to view the results automatically or changes. It asks me to accept "Terms of Service" which I don't want to do right now because I am not sure about the way it may result.
There are various options available to view the form results/responses.But here I don't want to view the results later.They should get updated when we click the submit button on form.Please note..simultaneously many users may fill the form.
To implement this,I have thought of logic like whenever submit button gets clicked..the text in the form should get updated.
Please suggest how I can add the count or apply above logic of whenever submit operation is performed. Is it possible?? Any other suggestions are welcomed..Thanks in Advance!!!
I found another possible way of doing this..I received all the responses in Google Spreadsheet..which I later embedded in my site. Solves the purpose..And the embedded data gets updated automatically for the responses !! Cheers
I trying to add some fields to form depending of checkbox. But I have no idea how can I do that. I think Ajax can be useful, but I dont work with Ajax in Symfony2 yet, and if my form build up not in the controller what value I need specify in url: option of Ajax?
That's quite a broad question, but essentially: the Symfony way is to add them to the Form in the Controller by reacting to FormEvents.
Symfony Docs on Form Events
One way to achieve what you're after is to submit the form twice - the first time code will react to the checked checkbox and arrange the rest of the form as required, the second time the form will be valid and you can take action. Details on the above link. AJAX might help with this, allowing a form submission as soon as you've checked the checkbox.
Although you can create HTML form fields using AJAX, when you submit the form those fields need to exist in the Form object. You can add them just in time, in the controller, before Symfony tries to bind them.
I'm pretty new to Play Framework.
My problem is that when a user clicks on the register link, he will instantly see validation errors.
The problem is that the method that serves the form also validates the form. So when the user clicks on the register link, gets to the validation without any input and then gets validation errors.
One solution would be to have an extra method to only serve the register form. But this would require an extra form and an extra route.
Another solution would be to disable validation on empty forms.
Is this possible? If not is there an other way?
You are on the way to a good solution. Make a second method.
GET /register controllers.RegistrationController.showRegistration()
POST /register controllers.RegistrationController.register()
The first is to display the registration page with the form, the latter to handle the form submit.
A method should stick to do one thing: either to show a registration page or to handle a post. Generally it's not a good idea to write a single method with a lots of if-then-else flow control statements.
Play framework also supports REST principles: in a simplified way GET is to retrieve a resource (=an empty registration page here), POST is to submit data(=do the registration).
Have a good look at Play framework's examples, I think the computer-database is very simple and a good starting point for you.