JAX-RS Param Converter- Compile time error using it - rest

Question

This is my param converter
import org.springframework.data.domain.Sort;
public class MyParamConverter implements ParamConverter<Sort> {
#Override
public Sort fromString(String s){
return new Sort(new Sort.Order(Sort.Direction.ASC, "ds"));
}
#Override
public String toString(Sort mo){
return mo.toString();
}
}
this is my paramconverter provider
#Provider
public class MyParamConverterProvider implements ParamConverterProvider {
#Override
public <T> ParamConverter<T> getConverter(Class<T> rawType, Type genericType, Annotation[] annotations) {
if(rawType.equals(Sort.class)){
return (ParamConverter<T>) new MyParamConverter();
}
return null;
}
I am trying to use in my API as
#GET
#Path("/")
Response read(#QueryParam("sort") Sort order);
I am expecting the jax to map string that I pass in my url e.g. &sort="asc" to Sort object. But I am getting an compile time error that have a registered implementation of paramconverter provider. I need to find a way when I pass a query param as &sort="somethung" it gets convert to SORT automatically either by using custom annotation or by using Param Converter.

Answer 1

with reference to your comment, try registering your provider like:
#ApplicationPath("/")
public class MyApplication extends ResourceConfig {
#Override
public Set<Class<?>> getClasses() {
final Set<Class<?>> classes = new HashSet<Class<?>>();
classes.add(MyParamConverterProvider.class);
return classes;
}
}
or, if you are using Jersey
#ApplicationPath("/")
public class MyApplication extends ResourceConfig {
public MyApplication() {
packages("my.package");
// or without package scanning
register(MyParamConverterProvider.class);
}
}