count how many times a dialog is triggered WATSON Conversations - chatbot

I need to count how many times a dialog falls into a specific node, and from the third time direct to another node that will request contact information, to talk to it.
It's all done, but I had to make this change.

You start by initialising a counter variable to 0 at your welcome node.
In the related node you just set a context variable.
"context" {
"counter": "<? $counter + 1 ?>"
},
Then add a condition to check if counter has exceeded a certain value.
$counter > 3

Related

Perl: Value of global variable not getting updated when changed in child

Code Snippet:
my $kill=0;
my #array1 = ("abc", "def","ghi");
&runSmokesAndMonitor;
sub runSmokesAndMonitor {
foreach my $smokeTestVarDirName (#array1) {
if ($pid =fork()) {
print "parent\n"; ### Have some other action items as well here in parent
}
else {
$kill++;
print "Value of kill is $kill\n";
exit 0;
}
}
}
Here, I am getting output:
parent
Value of kill is 1
parent
Value of kill is 1
parent
Value of kill is 1
Required/Expected: (As $kill is global variable, so values of $kill must have updated wherever new value would have assigned)
parent
Value of kill is 1
parent
Value of kill is 2
parent
Value of kill is 3
parent
Why is the output not as expected, and how can i achieve it?
A child created by fork is a new process with its own address space. Global variables are per process only, not global per user or per system or even global between all instances of a software running in the world. That's why changes to a global variable are only reflected in the current process.
If you need to share information between processes you need IPC (inter process communication), i.e. things like sockets, pipes, shared memory etc - see perlipc for more. There are ways to make sharing variables across processes easier, like IPC::Shareable.

Anylogic: Queue TimeOut blocks flow

I have a pretty simple Anylogic DE model where POs are launched regularly, and a certain amount of material gets to the incoming Queue in one shot (See Sample Picture below). Then the Manufacturing process starts using that material at a regular rate, but I want to check if the material in the queue gets outdated, so I'm using the TimeOut option of that queue, in order to scrap the outdated material (older than 40wks).
The problem is that every time that some material gets scrapped through this Timeout exit, the downstream Manufacturing process "stops" pulling more material, instead of continuing, and it does not get restarted until a new batch of material gets received into the Queue.
What am I doing wrong here? Thanks a lot in advance!!
Kindest regards
Your situation is interesting because there doesn't seem to be anything wrong with what you're doing. So even though what you are doing seems to be correct, I will provide you with a workaround. Instead of the Queue block, use a Wait block. You can assign a timeout and link the timeout port just like you did for the queue (seem image at the end of the answer).
In the On Enter field of the wait block (which I will assume is named Fridge), write the following code:
if( MFG.size() < MFG.capacity ) {
self.free(agent);
}
In the On Enter of MFG block write the following:
if( self.size() < self.capacity && Fridge.size() > 0 ) {
Fridge.free(Fridge.get(0));
}
And finally, in the On Exit of your MFG block write the following:
if( Fridge.size() > 0 ) {
Fridge.free(Fridge.get(0));
}
What we are doing in the above, is we are manually pushing the agents. Each time an agent is processed, the model checks if there is capacity to send more, if yes, a new agent is sent.
I know this is an unpleasant workaround, but it provides you with a solution until AnyLogic support can figure it out.

Anylogic: Queue timeout & condition

In the default settings it is possible to set a time in the queue after which an agent leaves the queue via outTimeOut. However, only a fixed time can be entered in the corresponding field, e.g. 12 hours. Is there a possibility to link these 12 hours with a condition? In my case, the agent should only leave the queue after 12 hours via outTimeOut if a certain condition is also met. In my case, if a variable varIN == 1.
Collect the time in queue statistics for each agent. Create a parameter called entryTime. When they enter the block, set agent.entryTime=time();
You can create an event that iterates through the queue every 1 second and removes the agents that meet your conditions from the queue (by using remove(Agent agent) function). That means if (time()-agent.entryTime>12)&&(agent.varIN==1), you will remove that agent.
Loop will look like this:
for (int i=0; i< yourQueue.size(); i++) {
YourAgentType currentAgent = ((YourAgentType)yourQueue.get(i));
if ((time()-currentAgent.entryTime>12)&&(currentAgent.varIN==1)){
yourQueue.remove(currentAgent);
}
}
You can use a function (returning a double) to define and calculate the most complex logic you like. If you provide an argument of type Agent (or the specific agent type flowing through the blocks), it can even account for your agent characteristics.
In the queue block timeout, simply call the function.

Anylogic - Assembler should stop working for 2 hours after 10 assemblies done

The "Assembler" should stop working for 2 hours after 10 assemblies are done.
How can I achieve that?
There are so many ways to do this depending on what it means to stop working and what the implications are for the incoming parts.. but here's one option
create a resourcePool called Machine, this will be used along with the technicians:
on the "on exit" action of the assembler do this (I use 9 instead of 10 because the out.count() doesn't count until the agent is completely out, so when it counts 9, it means that you have produced 10)
if(self.out.count()==9){
machine.set_capacity(0);
create_MyDynamicEvent(2, HOUR);
}
In your dynamice event (that you have to create) you will add the following code:
machine.set_capacity(1);
A second option is to have a variable countAssembler count the number of items produced... then
on exit you write countAssembler++;
on enter delay you write the following:
if(countAssembler==10){
self.suspend(agent);
create_MyDynamicEvent(2, HOUR,agent);
}
on the dynamic event you write:
assembler.resume(agent);
Don't forget to add the parameter needed in the dynamic event:
Create a variable called countAssembler of type int. Increment this as agents pass through the assembler. Also create a variable called assemblerStopTime. You also record the assembler stop time with assemblerStopTime=time()
Place a selectOutputOut block before the and let them in if countAssembler value is less than 10. Otherwise send to a Wait block.
Now, to maintain the FIFO rule, in the first selectOutputOut condition, you need to check also if there is any agent in the wait block and if the current time - assemblerStopTime is greater than 2. If there is, you free it and send to the assembler with wait.free(0) function. And send the current agent to wait. You also need to reset the countAssembler to zero.

How do I choose both exact quanitity wait for and quanitity available in the same pick-up block?

So I have a vehicle which is going to pick up exact quantity (Wait for) the first 50 minutes in the simulation. After those 50 minutes have gone by, I want the same vehicle to pick up quantity (if available). How do I go about this?
Alternative approach (avoiding complex Java coding) is to use 2 Pickup blocks, each with a different setup. Put a SelectOutput block before them and route agents into the respective block using time()>50*minute() in the SelectOutput condition
Set it up for the first setup by default.
Create an event to trigger after 50 mins and make it execute this code:
myPickupObject.set_pickupType(PickupType.QUANTITY);
Here is a way to allow container entity to wait in a Pickup for some time t and then leave with whatever entities have been picked up. The example model looks like this:
There are two key components:
ReleaseOnTimeout Dynamic event which has a parameter called '_agent' of type Agent and following code:
for (Object o : pickup.getEmbeddedObjects()) {
// find the Delay object inside Pickup
if (Delay.class == o.getClass().getSuperclass()) {
// remove the container from the Delay
Agent a = ((Delay)o).remove(_agent);
if (a != null) {
// send the removed container into Enter
enter.take(a);
}
}
}
In pickup on enter action contains following code: `create_ReleaseOnTimeout(10, container);
How this works:
pickup is configured to have Exact quantity (wait for) behaviour
a container object enters Pickup block pickup
on entry a dynamic event ReleaseOnTimeout is scheduled in 10 units to check up on container
if sufficient number of entities were available then container picks them up and leaves
alternatively to (4), if by the time 10 units elapsed the container is still stuck in pickup then it will be removed and put into enter