In the default settings it is possible to set a time in the queue after which an agent leaves the queue via outTimeOut. However, only a fixed time can be entered in the corresponding field, e.g. 12 hours. Is there a possibility to link these 12 hours with a condition? In my case, the agent should only leave the queue after 12 hours via outTimeOut if a certain condition is also met. In my case, if a variable varIN == 1.
Collect the time in queue statistics for each agent. Create a parameter called entryTime. When they enter the block, set agent.entryTime=time();
You can create an event that iterates through the queue every 1 second and removes the agents that meet your conditions from the queue (by using remove(Agent agent) function). That means if (time()-agent.entryTime>12)&&(agent.varIN==1), you will remove that agent.
Loop will look like this:
for (int i=0; i< yourQueue.size(); i++) {
YourAgentType currentAgent = ((YourAgentType)yourQueue.get(i));
if ((time()-currentAgent.entryTime>12)&&(currentAgent.varIN==1)){
yourQueue.remove(currentAgent);
}
}
You can use a function (returning a double) to define and calculate the most complex logic you like. If you provide an argument of type Agent (or the specific agent type flowing through the blocks), it can even account for your agent characteristics.
In the queue block timeout, simply call the function.
Related
I currently have an event that is checked every 30 minutes and calls the function, which is used to check if conditions are met to free an agent Patientthat is in wait1
The event uses the code below and theoretically causes all of the agents in the wait1 to be checked.:
if (wait1.size() > 0){
for (int i = 0; i < wait1.size(); i++)
function(wait1.get(i));}
The function is seen below:
The problem is that although patient should theoretically only go from the wait1 block to the selectOutput3and eventually a seize if they satisfy one of the conditions in the function, it happens that if multiple patient satisfy the same condition, they both get free'd. However, there is only 1 SurgeonMorning and 1 SurgeonAfternoon, so once a patient is freed from the wait, it should seize the surgeon and not allow any of the other patients to be freed.
Yes, this happens because of the order of things happen
Anylogic first does the loop through all the agents in your wait block, and during the loop, the surgeon hasn't been seized yet so idle is always equal to true for all the agents in the wait block
you could so something like this
if (wait1.size() > 0){
for (int i = 0; i < wait1.size(); i++){
if(surgeonMorning.isReserved==false){
surgeonMorning.isReserved=true;
function(wait1.get(i));
}
}
}
then on the release, you can do surgeonMorning.isReserved=false when the time comes.
Nevertheless, your whole model could just be replaced by 1 service block from what I see. You are overdoing the amount of code needed.
The "Assembler" should stop working for 2 hours after 10 assemblies are done.
How can I achieve that?
There are so many ways to do this depending on what it means to stop working and what the implications are for the incoming parts.. but here's one option
create a resourcePool called Machine, this will be used along with the technicians:
on the "on exit" action of the assembler do this (I use 9 instead of 10 because the out.count() doesn't count until the agent is completely out, so when it counts 9, it means that you have produced 10)
if(self.out.count()==9){
machine.set_capacity(0);
create_MyDynamicEvent(2, HOUR);
}
In your dynamice event (that you have to create) you will add the following code:
machine.set_capacity(1);
A second option is to have a variable countAssembler count the number of items produced... then
on exit you write countAssembler++;
on enter delay you write the following:
if(countAssembler==10){
self.suspend(agent);
create_MyDynamicEvent(2, HOUR,agent);
}
on the dynamic event you write:
assembler.resume(agent);
Don't forget to add the parameter needed in the dynamic event:
Create a variable called countAssembler of type int. Increment this as agents pass through the assembler. Also create a variable called assemblerStopTime. You also record the assembler stop time with assemblerStopTime=time()
Place a selectOutputOut block before the and let them in if countAssembler value is less than 10. Otherwise send to a Wait block.
Now, to maintain the FIFO rule, in the first selectOutputOut condition, you need to check also if there is any agent in the wait block and if the current time - assemblerStopTime is greater than 2. If there is, you free it and send to the assembler with wait.free(0) function. And send the current agent to wait. You also need to reset the countAssembler to zero.
I am trying to make a model to simulate the contagion of covid in public spaces using a mix between SEIR and pedestrian models.
In another question I asked to use a static population. They suggested that before deleting the agent a copy be saved in a list and after the first X agents have been generated I want the next agent generated by the pedSource to be one of the list.
Currently what I do is take a random agent from the list and if it is infected I send a message to the new agent so that it goes into the infected state. But by doing that I am resetting the timeout to recover every time an agent enters the zone that I am modeling.
this is the code that currently runs in the pedSource on exit:
if (personasEnCasa.size()+personasEnSuper.size() > poblacionMaxima){
Persona p = randomFrom(personasEnCasa);
if (p.statechart.getState() == Persona.Infeccioso){
send("Contagiado", ped);
};
personasEnCasa.remove(p);
};
personasEnSuper is my population of Persona, personasEnCasa is my list of agents outside the zone and and poblacionMaxima is the maximum number of agents in the lista and the population
I would like to be able to copy the current statechart of the agent in the list to the agent that generates my pedSource. Or use something similar to a pedSource.inject () but inserting an agent from the list instead of a new one. But I did not know how to do it.
is there any way to do this?
your ped already exists and you don't need to copy it you can just move it to the flow like this, with pedWait being any pedestrian block that you want, so instead of send("Contagiado", ped); you would do enter.take(ped);
but if you insist in using the send, then you can use branches on your statechart to define where this ped goes:
you will need in this case before the send, use ped.infectious=true; and the condition in the branch would be infectious==true to move to the infectious state.
As a side note, instead of p.statechart.getState() == Persona.Infeccioso you should use p.statechart.getState().equals(Persona.Infeccioso)
use == only with primitives such as boolean, int and double, otherwise you are susceptible to errors that are very difficult to discover
So I have a vehicle which is going to pick up exact quantity (Wait for) the first 50 minutes in the simulation. After those 50 minutes have gone by, I want the same vehicle to pick up quantity (if available). How do I go about this?
Alternative approach (avoiding complex Java coding) is to use 2 Pickup blocks, each with a different setup. Put a SelectOutput block before them and route agents into the respective block using time()>50*minute() in the SelectOutput condition
Set it up for the first setup by default.
Create an event to trigger after 50 mins and make it execute this code:
myPickupObject.set_pickupType(PickupType.QUANTITY);
Here is a way to allow container entity to wait in a Pickup for some time t and then leave with whatever entities have been picked up. The example model looks like this:
There are two key components:
ReleaseOnTimeout Dynamic event which has a parameter called '_agent' of type Agent and following code:
for (Object o : pickup.getEmbeddedObjects()) {
// find the Delay object inside Pickup
if (Delay.class == o.getClass().getSuperclass()) {
// remove the container from the Delay
Agent a = ((Delay)o).remove(_agent);
if (a != null) {
// send the removed container into Enter
enter.take(a);
}
}
}
In pickup on enter action contains following code: `create_ReleaseOnTimeout(10, container);
How this works:
pickup is configured to have Exact quantity (wait for) behaviour
a container object enters Pickup block pickup
on entry a dynamic event ReleaseOnTimeout is scheduled in 10 units to check up on container
if sufficient number of entities were available then container picks them up and leaves
alternatively to (4), if by the time 10 units elapsed the container is still stuck in pickup then it will be removed and put into enter
I have a model with a queue and two machines, one of which is used just in case of overcrowding of the queue in front of these resources.
My model has a simple Queue and a Delay block and I tried to mutate the Delay capacity based on a previous queue length using a function like this (written in Delay block capacity text field):
if (queue.size() > 5)
return 2;
else
return 1;
But it doesn't seem to work... is it possible to change the number of resources dynamically based on a condition?
the capacity value in the delay block is only considered in the beginning of the simulation, so it can only be considered as the initial value...
To change the capacity later, you can put some code in the on enter and on exit of the queue block:
delay.set_capacity(queue.size() > 5 ? 2 : 1);
Something like that.