I have a pyspark dataframe with 4 columns.
id/ number / value / x
I want to groupby columns id, number, and then add a new columns with the sum of value per id and number. I want to keep colunms x without doing nothing on it.
df= df.select("id","number","value","x")
.groupBy( 'id', 'number').withColumn("sum_of_value",df.value.sum())
At the end I want a data frame with 5 columns : id/ number / value / x /sum_of_value)
Does anyone can help ?
The result you are trying to achieve doesn't make sense. Your output dataframe will only have columns that were grouped by or aggregated (summed in this case). x and value would have multiple values when you group by id and number.
You can have a 3-column output (id, number and sum(value)) like this:
df_summed = df.groupBy(['id', 'number'])['value'].sum()
Lets say your DataFrame df has 3 Columns Initially.
df1 = df.groupBy("id","number").count()
Now df1 will contain 2 columns id, number and count.
Now you can join df1 and df based on columns "id" and "number" and select whatever columns you would like to select.
Hope it helps.
Regards,
Neeraj
Related
I have a dataframe with column having values like "COR//xxxxxx-xx-xxxx" or "xxxxxx-xx-xxxx"
I need to compare this column with another column in a different dataframe based on the column value.
If column value have "COR//xxxxx-xx-xxxx", I need to use substring("column", 4, length($"column")
If the column value have "xxxxx-xx-xxxx", I can compare directly without using substring.
For example:
val DF1 = DF2.join(DF3, upper(trim($"column1".substr(4, length($"column1")))) === upper(trim(DF3("column1"))))
I am not sure how to add the condition while joining. Could anyone please let me know how can we achieve this in Spark dataframe?
You can try adding a new column based on the conditions and join on the new column. Something like this.
val data = List("COR//xxxxx-xx-xxxx", "xxxxx-xx-xxxx")
val DF2 = ps.sparkSession.sparkContext.parallelize(data).toDF("column1")
val DF4 = DF2.withColumn("joinCol", when(col("column1").like("%COR%"),
expr("substring(column1, 6, length(column1)-1)")).otherwise(col("column1")) )
DF4.show(false)
The new column will have values like this.
+------------------+-------------+
|column1 |joinCol |
+------------------+-------------+
|COR//xxxxx-xx-xxxx|xxxxx-xx-xxxx|
|xxxxx-xx-xxxx |xxxxx-xx-xxxx|
+------------------+-------------+
You can now join based on the new column added.
val DF1 = DF4.join(DF3, upper(trim(DF4("joinCol"))) === upper(trim(DF3("column1"))))
Hope this helps.
Simply create a new column to use in the join:
DF2.withColumn("column2",
when($"column1" rlike "COR//.*",
$"column1".substr(lit(4), length($"column1")).
otherwise($"column1"))
Then use column2 in the join. It is also possible to add the whole when clause directly in the join but it would look very messy.
Note that to use a constant value in substr you need to use lit. And if you want to remove the whole "COR//" part, use 6 instead of 4.
I have n (length) values in a spark column. I want to create a spark dataframe of k columns (where k is number of samples) and m rows (where m is sample size). I tried using withColumn, it is not working. Join by creating unique id will be very inefficient for me.
e.g. Spark column has following values :
102
320
11
101
2455
124
I want to create 2 samples of fraction 0.5 as columns in data frame.
So sampled data frame will be something like
sample1,sample2
320,101
124,2455
2455,11
Let df has a column UNIQUE_ID_D, I need k samples from this column. Here is the sample code for k = 2
var df1 = df.select("UNIQUE_ID_D").sample(false, 0.1).withColumnRenamed("UNIQUE_ID_D", "ID_1")
var df2 = df.select("UNIQUE_ID_D").sample(false, 0.1).withColumnRenamed("UNIQUE_ID_D", "ID_2")
df1.withColumn("NEW_UNIQUE_ID", df2.col("ID_2")).show
This wont work since withColumn can not access df2 column.
There is only way to join df1 and df2 by adding sequence column(join column) in both df's.
It is very inefficient for my use case since if I want to take 100 samples, I need to join 100 times in a loop for a single column. I need to perform this operation for all columns in original df.
How could I achieve this?
I want to iterate across the columns of dataframe in my Spark program and calculate min and max value.
I'm new to Spark and scala and not able to iterate over the columns once I fetch it in a dataframe.
I have tried running the below code but it needs column number to be passed to it, question is how do I fetch it from dataframe and pass it dynamically and store the result in a collection.
val parquetRDD = spark.read.parquet("filename.parquet")
parquetRDD.collect.foreach ({ i => parquetRDD_subset.agg(max(parquetRDD(parquetRDD.columns(2))), min(parquetRDD(parquetRDD.columns(2)))).show()})
Appreciate any help on this.
You should not be iterating on rows or records. You should be using aggregation function
import org.apache.spark.sql.functions._
val df = spark.read.parquet("filename.parquet")
val aggCol = col(df.columns(2))
df.agg(min(aggCol), max(aggCol)).show()
First when you do spark.read.parquet you are reading a dataframe.
Next we define the column we want to work on using the col function. The col function translate a column name to a column. You could instead use df("name") where name is the name of the column.
The agg function takes aggregation columns so min and max are aggregation functions which take a column and return a column with an aggregated value.
Update
According to the comments, the goal is to have min and max for all columns. You can therefore do this:
val minColumns = df.columns.map(name => min(col(name)))
val maxColumns = df.columns.map(name => max(col(name)))
val allMinMax = minColumns ++ maxColumns
df.agg(allMinMax.head, allMinMax.tail: _*).show()
You can also simply do:
df.describe().show()
which gives you statistics on all columns including min, max, avg, count and stddev
I have a spark dataframe containing 1 million rows and 560 columns. I need to find the count of unique items in each column of the dataframe.
I have written the following code to achieve this but it is getting stuck and taking too much time to execute:
count_unique_items=[]
for j in range(len(cat_col)):
var=cat_col[j]
count_unique_items.append(data.select(var).distinct().rdd.map(lambda r:r[0]).count())
cat_col contains the column names of all the categorical variables
Is there any way to optimize this?
Try using approxCountDistinct or countDistinct:
from pyspark.sql.functions import approxCountDistinct, countDistinct
counts = df.agg(approxCountDistinct("col1"), approxCountDistinct("col2")).first()
but counting distinct elements is expensive.
You can do something like this, but as stated above, distinct element counting is expensive. The single * passes in each value as an argument, so the return value will be 1 row X N columns. I frequently do a .toPandas() call to make it easier to manipulate later down the road.
from pyspark.sql.functions import col, approxCountDistinct
distvals = df.agg(*(approxCountDistinct(col(c), rsd = 0.01).alias(c) for c in
df.columns))
You can use get every different element of each column with
df.stats.freqItems([list with column names], [percentage of frequency (default = 1%)])
This returns you a dataframe with the different values, but if you want a dataframe with just the count distinct of each column, use this:
from pyspark.sql.functions import countDistinct
df.select( [ countDistinct(cn).alias("c_{0}".format(cn)) for cn in df.columns ] ).show()
The part of the count, taken from here: check number of unique values in each column of a matrix in spark
I have a dataframe (df1) which has 50 columns, the first one is a cust_id and the rest are features. I also have another dataframe (df2) which contains only cust_id. I'd like to add one records per customer in df2 to df1 with all the features as 0. But as the two dataframe have two different schema, I cannot do a union. What is the best way to do that?
I use a full outer join but it generates two cust_id columns and I need one. I should somehow merge these two cust_id columns but don't know how.
You can try to achieve something like that by doing a full outer join like the following:
val result = df1.join(df2, Seq("cust_id"), "full_outer")
However, the features are going to be null instead of 0. If you really need them to be zero, one way to do it would be:
val features = df1.columns.toSet - "cust_id" // Remove "cust_id" column
val newDF = features.foldLeft(df2)(
(df, colName) => df.withColumn(colName, lit(0))
)
df1.unionAll(newDF)