I don't understand using get-content on a csv - powershell

Question

How come when I do (Get-Content $CSV1)[2] in the Power-shell console on any .csv file I get the field but when I do it in the ISE I get errors like this.
$CSV1 = Import-Csv "C:\Users\Administrator\Documents\lab8\usersF.csv"
(Get-Content $CSV1)[2]
usersF.csv contents
GivenName
Ylnum
Dexcd
Igbos
Rzjlr
Errors
Cannot index into a null array.
At C:\Users\Administrator\Documents\lab8\ovie_lab7_merged.ps1:5 char:1
+ (Get-Content $CSV1)[2]
+ ~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : InvalidOperation: (:) [], RuntimeException
+ FullyQualifiedErrorId : NullArray
I've tried the solution #TheIncorrigible1 gave me and it worked, but now I'd like to export that data to a .csv and instead of the string I got the string length in the .csv file how can I fix this?
$CSV1 = Import-Csv -Path "C:\Users\Administrator\Documents\lab8\usersF.csv"
$test = $CSV1.GivenName[4]
$test | Export-Csv "C:\Users\Administrator\Documents\lab8\test.csv"
#TYPE System.String
Length
5

Answer 1

So the problem you're running into is a simple type understanding problem.
Import-Csv takes the Path you provide to it and imports that into a PSCustomObject. You're trying to Get-Content -Path [PSCustomObject], but that is not a supported type for the -Path argument (if you read the help topic, it expects a [String[]]).
If you want that first line, you should do something like:
$Path = 'C:\Users\Administrator\Documents\lab8\usersF.csv'
#(Get-Content -Path $Path)[1] #Arrays are zero-indexed
Alternatively,
$Csv = Import-Csv -Path $Path
$Csv.GivenName[0]
To address your edit, you aren't calling Export-Csv properly. It expects a PSCustomObject, but you're passing it a single string. I'd suggest using Out-File instead.
$CSV1 = Import-Csv -Path C:\Users\Administrator\Documents\lab8\usersF.csv
$test = $CSV1.GivenName[4]
$test |
OutFile -FilePath C:\Users\Administrator\Documents\lab8\test.csv