I was wondering if there's a way to step through a dictionary in Swift. I know I can iterate through, but I was hoping to step one by one through a dictionary of items as the user taps a "next" button.
I was thinking I could initially iterate through the dictionary and store the keys in an array, then step through the keys and retrieve each item as needed, since the array can be indexed. This seems a little inelegant, though. Any thoughts?
My current approach:
var iterator = 0
var keys = [String]()
func loadKeys() {
for (key, value) in items {
keys.append(key)
}
}
func step() {
iterator += 1
let currentKey = keys[iterator]
let currentItem = items[currentKey]
}
I figure it would work just fine, just not sure it's the best practice.
Thanks for your help!
A dictionary also provides you with an iterator, so you can step through it using that:
var iterator = items.makeIterator()
func step() {
if let v = iterator.next() {
let currentKey = v.key
let currentValue = v.value
}
}
A dictionary is an indexed collection, so you can use a dictionary's index to step through the keys and values:
var i = items.startIndex
func step() {
guard i != items.endIndex else {
// at the end of the dictionary
return
}
let (currentKey, currentValue) = items[i]
i = items.index(after: i)
}
Related
Here is my Array of Dictionary,
var myArrayOfDict = [["vegetables": ["CARROT","BEANS"], "fruits": ["APPLE","MANGO","BANANA"], "letters":["A","B","C","D"],"numbers":["ONE","TWO","THREE"],"shapes":["SQUARE","RECTANGLE","CIRCLE"]]]
How do i get the desired output, actually i need to get random selected elements of the specified range ...(i.e) when i need 3 elements randomnly from dictionary as like,
[["fruits": ["APPLE","MANGO","BANANA"],"shapes":["SQUARE","RECTANGLE","CIRCLE"],"numbers":["ONE","TWO","THREE"]]]
When i need just 2 elements randomnly like,
[["shapes":["SQUARE","RECTANGLE","CIRCLE"],"fruits": ["APPLE","MANGO","BANANA"]]]
Thanks in Advance,
Here is one solution using randomElement().
func randomSelection(from dict: [String: [String]], count: Int) -> [String: [String]] {
guard !dict.isEmpty else { return [:] }
var result = [String: [String]]()
for i in 0..<count {
let element = dict.randomElement()! //We know dictionary is not empty
result[element.key] = element.value
}
return result
}
The above solution might return less elements in a dictionary than expected if the same element is returned more than once from randomElemnt(). If this should be voided the below solution should work
func randomSelection(from dict: [String: [String]], count: Int) -> [String: [String]] {
guard !dict.isEmpty else { return [:] }
guard dict.count > count else { return dict }
var result = [String: [String]]()
while result.count < count {
let element = dict.randomElement()!
if result[element.key] == nil {
result[element.key] = element.value
}
}
return result
}
Since the function takes a dictionary as the first argument the array needs to be looped over
for d in myArrayOfDict {
print(randomSelection(from: d, count: 2))
}
Array myArrayOfDict contains a single Dictionary. So, it doesn't make sense getting a random element from it.
As your example explains, you need to get random elements from the Dictionary itself.
So, you can use randomElement to get that working.
let myArrayOfDict = ["vegetables": ["CARROT","BEANS"], "fruits": ["APPLE","MANGO","BANANA"], "letters":["A","B","C","D"],"numbers":["ONE","TWO","THREE"],"shapes":["SQUARE","RECTANGLE","CIRCLE"]]
var elements = [String : [String]]()
let count = 2
for _ in 0..<count {
if let element = myArrayOfDict.randomElement() {
elements[element.key] = element.value
}
}
print(elements)
This is a little hard to explain, but I'll try my best. I am trying to update a Dictionary inside another Dictionary properly. The following code almost does what I need.
var dictionary = Dictionary<String, [Int : Int]>()
func handleStatsValue(tag: Int ) {
let currentValue: Int = dictionary["Score"]?[tag] ?? 0
dictionary["Score"] = [
tag : currentValue + 1
]
}
However, it seems the dictionary is overridden when the tag value changes (e.g. 1 to 2). I need Dictionary to have multiple dictionaries inside of it. Any tips or suggestions are deeply appreciated.
Edit: I'm trying to have multiple dictionaries nested inside a dictionary. It seems whenever the tag value is changed, the dictionary is overridden.
One way to write this would be:
func handleStatsValue(tag: Int) {
dictionary["Score", default: [:]][tag, default: 0] += 1
}
or, written without [_:default:]
func handleStatsValue(tag: Int) {
var scoreDictionary = dictionary["Score"] ?? [:]
scoreDictionary[tag] = (scoreDictionary[tag] ?? 0) + 1
dictionary["Score"] = scoreDictionary
}
However, it's not a good idea to use nested dictionaries to keep your data. Use a custom struct instead and try to avoid tags too:
struct DataModel {
var score: [Int: Int] = [:]
}
I think you need something like this to either increase the value for an existing tag or add a new tag if it doesn't exist
func handleStatsValue(tag: Int ) {
if var innerDict = dictionary["Score"] {
if let value = innerDict[tag] {
innerDict[tag] = value + 1
} else {
innerDict[tag] = 1
}
dictionary["Score"] = innerDict
}
}
Although the code looks a bit strange with the hardcoded key "Score", maybe it would be better to have multiple simple dictionaries instead, like
var score: [Int, Int]()
or if you prefer
var score = Dictionary<Int, Int>()
I have an array in which there are two values coming. I want to get them out of an array and pass the value according to index base to var1 and var2. I am looping through the array but when run the app it does not come inside the for loop. I have used break points also but it does not come inside the loop.
Code I have tried,
let myarray = UserDefaults.standard.stringArray(forKey: "selectArray") ?? [String]()
for (index, value) in myarray.enumerated() {
print("\(index): \(value)")
if index == 0{
listItem = value
print(listItem)
}else
{
CuisineItem = value
print(CuisineItem)
}
}
How can I get the value out now in two separate variables?
How you set array in UserDefaults. Look here my code works well
var array1: [[String]] = [[String]]()
array1 = [["key1", "val2"],["key2", "val2"]]
UserDefaults.standard.set(array1, forKey: "selectArray")
let myarray = UserDefaults.standard.value(forKey: "selectArray") as? [[String]]
for (index, value) in (myarray?.enumerated())! {
for (index, value) in value.enumerated() {
print("\(index): \(value)")
if index == 0 {
listItem = value
print(listItem)
}else {
CuisineItem = value
print(CuisineItem)
}
}
}
As you have mentioned that your array is of 2-D so , you can try code given below :
for oneDArray in myarray {
for(index,value) in oneDArray.enumerated(){
print("\(index1): \(value1)")
if index == 0{
listItem = value
print(listItem)
}
else {
CuisineItem = value
print(CuisineItem)
}
}
}
It should be noted that myarray is two-dimensional array , and oneDArray is one-dimensional array.
You can easily save and retrieve multi dimensional array in user defaults. Try the below code in XCode Playground, it works like a charm.
import Foundation
let array = [["a", "b", "c"], ["a", "b", "c"]];
func testArray() {
UserDefaults.standard.setValue(array, forKey: "test");
guard let testArray = UserDefaults.standard.array(forKey: "test") as? [[String]] else {
return
};
print(testArray)
}
testArray()
I'm saving lists in a dictionary. These lists need to be updated. But when searching for an item, I need [] operator. When I save the result to a variable, a copy is used. This can not be used, to change the list itself:
item = dicMyList[key]
if item != nil {
// add it to existing list
dicMyList[key]!.list.append(filename)
// item?.list.append(filename)
}
I know, that I need the uncommented code above, but this accesses and searches again in dictionary. How can I save the result, without searching again? (like the commented line)
I want to speed up the code.
In case you needn't verify whether the inner list was actually existing or not prior to adding element fileName, you could use a more compact solution making use of the nil coalescing operator.
// example setup
var dicMyList = [1: ["foo.sig", "bar.cc"]] // [Int: [String]] dict
var key = 1
var fileName = "baz.h"
// "append" (copy-in/copy-out) 'fileName' to inner array associated
// with 'key'; constructing a new key-value pair in case none exist
dicMyList[key] = (dicMyList[key] ?? []) + [fileName]
print(dicMyList) // [1: ["foo.sig", "bar.cc", "baz.h"]]
// same method used for non-existant key
key = 2
fileName = "bax.swift"
dicMyList[key] = (dicMyList[key] ?? []) + [fileName]
print(dicMyList) // [2: ["bax.swift"], 1: ["foo.sig", "bar.cc", "baz.h"]]
Dictionaries and arrays are value types. So if you change an entry you'll need to save it back into the dictionary.
if var list = dicMyList[key] {
list.append(filename)
dicMyList[key] = list
} else {
dicMyList[key] = [filename]
}
It's a little bit late, but you can do something like this:
extension Optional where Wrapped == Array<String> {
mutating func append(_ element: String) {
if self == nil {
self = [element]
}
else {
self!.append(element)
}
}
}
var dictionary = [String: [String]]()
dictionary["Hola"].append("Chau")
You can try this in the Playground and then adapt to your needs.
May I know how to remove the duplicate data which all the data is passing from the Parse database. I just select one column and pass that column data to this picker view.
I've try to find the query.wherekey but it didn't have the DISTINCT function which similar to the SQL statement, so what should I do to avoid the data duplication?
As you add items one by one into your self.pickerString array, just verify if this array contains or not the new value before addObject new value to the array. For example:
if !self.pickerString.contains(object["Intake"] as! String) {
self.pickerString.append(object["Intake"] as! String)
}
There is no built-in function to remove duplicate items in an array in swift (correct me if I'm wrong). However, you can add new features for array with 'extension' keyword:
extension Array {
func distinct<T: Equatable>() -> [T] {
var newArray = [T]()
for item in self {
if !contains(newArray, item as! T) {
newArray.append(item as! T)
}
}
return newArray
}
}
usage:
let s = ["344","333","1","2","333"]
var p = s.distinct() as [String]
I don't think you have anything like distinct on Parse, you'll have to download all rows and then filter out equal values.
For a functional approach:
func distinct<T: Equatable>(source: [T]) -> [T] {
var unique = [T]()
for item in source {
if !contains(unique, item) {
unique.append(item)
}
}
return unique
}
[...]
self.pickerString = distinct(objects)
[...]