Is it a requirement that you must use a time or datetime column in postgres to pull metric's on a Grafana dashboard?
I ask because I have a column just with a date only and I'm unable to show metrics base on dates only. Unless I am missing something in the documentation. Postgres in Grafana
If anyone has any helpful information, it would be greatly appreciated.
All I need is just a starting point.
I am a new user to Grafana and I'm trying to figure this out.
According to documentation:
If you set Format as to Time series, for use in Graph panel for example, then the query must return a column named time that returns either a sql datetime or any numeric datatype representing unix epoch in seconds.
So, all you need is to convert your column with date to unix epoch and name it as time. You can do it yourself or use macros provided by grafana (see docs) for convertion which are expanded into native postgres expressions. It is also helpful to look at 'Generated SQL' to see the actual query sent to database.
Related
I'm trying to find a way to tell Postgres to truncate all datetime columns so that they are displayed and filtered by seconds (ignoring milliseconds).
I'm aware of the
date_trunc('second', my_date_field)
method, but do not want to do that for all datetime fields in every select and where clause that mentions them. Dates in the where clause need to also capture records with the granularity of seconds.
Ideally, I'd avoid stripping milliseconds from the data when it is stored. But then again, maybe this is the best way. I'd really like to avoid that data migration.
I can imagine Postgres having some kind of runtime configuration like this:
SET DATE_TRUNC 'seconds';
similar to how timezones are configured, but of course that doesn't work and I'm unable to find anything else in the docs. Do I need to write my own Postgres extension? Did someone already write this?
I'm using Seekwell to connect my AWS postgres database to Sheets.
I think I'm converting my dates to standard 'date' (YYYY-MM-DD) format in the code, eg.
date(date_trunc('day', u.created_at::date)) Date_Created
However, when the query is run, my dates are iso 8601, eg.
2018-05-16T00:00:00.000Z
Of course, given that my results are going into Google Sheets, I can always convert those dates there in sheets, but that adds a layer of complexity that is hard to manage.
How can I make sure the dates are formatted correctly before the results land in sheets?
Michael from Seekwell tells me this is:
a bit of bug with how JDBC handles dates in the background. You're on Postgres, right? This should work from within the add-on:
to_char(your_date_column, 'YYYY-MM-DD')
Sheets will recognize that result as a date.
This worked.
First of all im a starter,iam using eclipse.
I want to add current date and time of login in to db and search a day and find out the time between login and logout.
°What is the data type for the date colum in mysql ?
°Is it necessary separate column for date and time ?
°which one i want to import, java.util.date or java.sql.date ?
°In Java code simple date format or calender is better ?
Advanced thanks.....
You might want to read this:
Should I use field 'datetime' or 'timestamp'?
For example, if you have mysql populate the log record's date/time (using "DEFAULT CURRENT_TIMESTAMP" in your field definition), you will want to use timestamp. For certain situations where you fill a date value from your application, you may wish to use datetime. Be careful with timezones.
Here are the date functions in mysql:
https://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html
DATEDIFF(), for example, will calculate the number of days between two datetimes. If you use unix timestamps, you can use standard arithmetic between the values to find the number of seconds between them, and then calculate minutes, hours, days, etc. by dividing appropriately.
This answer is focused on how to handle the dates in mysql. Not enough info to provide guidance on java.
I am building a map in CartoDB which uses Postgres. I'm simply trying to display my dates as: 10-16-2014 but, haven't been able to because Postgres includes an unneeded timestamp in every date column.
Should I alter the column to remove the timestamp or, is it simply a matter of a (correct) SELECT query? I can SELECT records from a date range no problem with:
SELECT * FROM mytable
WHERE myTableDate >= '2014-01-01' AND myTableDate < '2014-12-31'
However, my dates appear in my CartoDB maps as: 2014-10-16T00:00:00Z and I'm just trying to get the popups on my maps to read: 10-16-2014.
Any help would be appreciated - Thank you!
You are confusing storage with display.
Store a timestamp or date, depending on whethether you need time or not.
If you want formatted output, ask the database for formatted output with to_char, e.g.
SELECT col1, col2, to_char(col3, 'DD-MM-YY'), ... FROM ...;
See the PostgreSQL manual.
There is no way to set a user-specified date output format. Dates are always output in ISO format. If PostgreSQL let you specify other formats without changing the SQL query text it'd really confuse client drivers and applications that expect the date format the protocol specifies and get something entirely different.
You have two basic options.
1 Change the column from a timestamp to a date column.
2 Cast to date in your SQL query (i.e. mytimestamp::date works).
In general if this is a presentation issue, I don't usually think that is a good reason to muck around with the database structure. That's better handled by client-side processing or casting in an SQL query. On the other hand if the issue is a semantic one, then you may want to revisit your database structure.
I have a decimal date field (TDDATR) that is in the YYYYMMDD format.
I would like to create a field that is TDDATR + 30 days but I am unable to.
Using 'Define Results Field' I have tried a few things;
Simply doing this;
TDDATR + 30 DAYS
But it returned this error: Labeled duration not used correctly.
I tried using the DIGITS and SUBSTR commands to create a field in the DDMMYYYY format and then +30 days but got the same error.
Same as above but in the DD/MM/YYYY format - same error.
Using DATE(TDDATR) but all I see is +'s in the field.
Using DATE( ) on the fields created in step 2 and 3 - still get +'s
I've ran out of ideas - any help would be greatly appreciated.
Query/400 lacks a lot of the features that an SQL based interface has.
I'd urge you to consider switching to Query Manager (STRQM) which is a fully SQL based product. You can even convert Query/400 queries to Query Manager queries with the RTVQMQRY command by having the ALWQRYDFN parm set to *YES.
The other option that IBM is pushing is Web Query. Again, fully SQL based and you can convert Query/400 queries into it.
Having said that, the problem is that FLD + 30 DAYS only works when FLD is a DATE data type. Query/400 includes a DATE() function to convert non-date types into date. But it's very limited in that it only works with character fields formatted according to your job defaults. Assuming you're in the US, it'd only work with a character value of '07/01/15'.
You could do a lot of manipulation in Query/400 and end up with a result field that meets DATE()'s requirements. But a better solution would be to create an SQL view over your table and have your numeric date converted into a date data type in the view.
You can find code examples that show how to convert a numeric YYYYMMDD to a actual date data type in the view. However, I'd recommend create a user defined function (UDF) that will do the conversion for you. That will make it much easier to use in the view and to reuse in other places.
If you'd like, there's an open source package called iDate, that includes all the code required for convert to/from date data types.
Download that, install/compile it and your SQL view becomes
select ... idate(TDDATR,'*CCYMD') as TD_DATE
from myfile
The use of days is as follow
Field Expression
CURDATE_30 days(current(date)) + 30
The solution to your problem is: given the field A dec(8,0)
Field Expression
YYYYMMDD_ date(substr(digits(a),5,2)||'/'||
substr(digits(a),7,2)||'/'||
substr(digits(a),3,2))
NEXT_MONTH DAYS(YYYYMMDD_) + 30
Remember to check the date format in your job description. In the example the format is MDY or MM/DD/YY.
More info here
Based on the information here, I created the below 2 fields;
TDDIGI DIGITS(TDDATR)
TDDAT1 SUBSTR(TDDIGI,7,2)||'/'||
SUBSTR(TDDIGI,5,2)||'/'||
SUBSTR(TDDIGI,3,2)
From here I was able to create a date field;
TDDAT2 DATE(TDDAT1)
Which allowed me to perform the necessary calculations.
The format of TDDAT1 is based on your job description which can be found by;
WRKJOB
Option 2
Page down
Date format..: X
Mine was *DMY, so TDDAT1 was formatted based on this.