Drawing hexagon image using Swift 4 - swift

Question

public func roundedPolygonPath(rect: CGRect, lineWidth: CGFloat, sides: NSInteger, cornerRadius: CGFloat, rotationOffset: CGFloat = 0) -> UIBezierPath {
let path = UIBezierPath()
let theta: CGFloat = CGFloat(2.0 * M_PI) / CGFloat(sides) // How much to turn at every corner
let offset: CGFloat = cornerRadius * tan(theta / 2.0) // Offset from which to start rounding corners
let width = min(rect.size.width, rect.size.height) // Width of the square
let center = CGPoint(x: rect.origin.x + width / 2.0, y: rect.origin.y + width / 2.0)
// Radius of the circle that encircles the polygon
// Notice that the radius is adjusted for the corners, that way the largest outer
// dimension of the resulting shape is always exactly the width - linewidth
let radius = (width - lineWidth + cornerRadius - (cos(theta) * cornerRadius)) / 2.0
// Start drawing at a point, which by default is at the right hand edge
// but can be offset
var angle = CGFloat(rotationOffset)
let corner = CGPoint(x: center.x + (radius - cornerRadius) * cos(angle),y: center.y + (radius - cornerRadius) * sin(angle))
path.move(to: CGPoint(x: corner.x + cornerRadius * cos(angle + theta),y: corner.y + cornerRadius * sin(angle + theta)))
for _ in 0..<sides {
angle += theta
let corner = CGPoint(x: center.x + (radius - cornerRadius) * cos(angle),y: center.y + (radius - cornerRadius) * sin(angle))
let tip = CGPoint(x: center.x + radius * cos(angle),y: center.y + radius * sin(angle))
let start = CGPoint(x: corner.x + cornerRadius * cos(angle - theta),y: corner.y + cornerRadius * sin(angle - theta))
let end = CGPoint(x: corner.x + cornerRadius * cos(angle + theta), y: corner.y + cornerRadius * sin(angle + theta))
path.addLine(to: start)
path.addQuadCurve(to: end, controlPoint: tip)
}
path.close()
// Move the path to the correct origins
let bounds = path.bounds
let transform = CGAffineTransform(translationX: -bounds.origin.x + rect.origin.x + lineWidth / 2.0, y: -bounds.origin.y + rect.origin.y + lineWidth / 2.0)
path.apply(transform)
return path
}
public func createImage(layer: CALayer) -> UIImage {
let size = CGSizeMake(CGRect.maxX(layer.frame), CGRect.maxY(layer.frame))
UIGraphicsBeginImageContextWithOptions(size, layer.isOpaque, 0.0)
let ctx = UIGraphicsGetCurrentContext()
layer.render(in: ctx!)
let image = UIGraphicsGetImageFromCurrentImageContext()
UIGraphicsEndImageContext()
return image!
}
let lineWidth = CGFloat(7.0)
let rect = CGRectMake(0.0, 0.0, 150.0, 150.0)
let sides = 6
var path = roundedPolygonPath(rect, lineWidth, sides, 15.0, rotationOffset: CGFloat(-M_PI / 2.0))
let borderLayer = CAShapeLayer()
borderLayer.frame = CGRectMake(0.0, 0.0, path.bounds.width + lineWidth, path.bounds.height + lineWidth)
borderLayer.path = path.CGPath
borderLayer.lineWidth = lineWidth
borderLayer.lineJoin = kCALineJoinRound
borderLayer.lineCap = kCALineCapRound
borderLayer.strokeColor = UIColor.blackColor().CGColor
borderLayer.fillColor = UIColor.whiteColor().CGColor
var image = createImage(borderLayer)}[enter image description here][1]
I cannot convert the Swift 3 with CGRect and CGSizeMake functions to latest Swift 4.
The following errors is due to the conversion of Swift 3 example. I have found,
'CGRectMake' is unavailable in Swift
Extensions may not contain stored properties
'CGSizeMake' is unavailable in Swift
*Im trying to draw the path **

Answer 1

Instead of CGSizeMake you now can use CGSize.init, e.g. CGSize(width: 100, height: 50).
Instead of the static function CGRect.maxX you now can use the member method of the same name: CGRect.maxX(layer.frame) becomes layer.frame.maxX.