SO, I got 2 entities : InitialSituation, having ManytoOne relating with Universe entity.
In the form of InitialSituation, there a select for Universe :
<h:selectOneMenu id="universe" value="#{initialSituationController.initialSituation.universe}" >
<f:selectItems value="#{universeBean.selectItems}" />
</h:selectOneMenu>
Entities (using JPA annotation) :
#Entity
#Table(name = "initial_situation")
public class InitialSituation implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO, generator = "initial_situation_id_seq")
#SequenceGenerator(name = "initial_situation_id_seq", sequenceName = "initial_situation_id_seq", allocationSize = 1)
#Column(name = "id_initial_situation")
protected int idInitialSituation;
protected String name;
protected String content;
protected boolean happy;
#ManyToOne
#JoinColumn(name = "id_universe")
protected Universe universe;
// Getters and setters
}
#Entity
#Table(name = "universe")
public class Universe implements Serializable {
#Id
#GeneratedValue(strategy=GenerationType.AUTO, generator="universe_id_seq")
#SequenceGenerator(name="universe_id_seq", sequenceName="universe_id_seq", allocationSize=1)
#Column( name = "id_universe" )
protected int idUniverse;
#Column
protected String name;
#Column
protected String content;
#OneToMany(mappedBy = "universe")
protected List<InitialSituation> initialSituations;
public List<InitialSituation> getInitialSituations() {
return initialSituations;
}
public void setInitialSituations(List<InitialSituation> initialSituations) {
this.initialSituations = initialSituations;
}
#Override
public String toString(){
return this.getName();
}
}
The select, in the rendered HTML, has correct values and labels. But the binding between selectOneMenu and value="#{initialSituationController.initialSituation.universe}" is not working.
Nevertheless, InitialSituation has a Universe initiated, I verified.
Why the binding is not working ? Thank you !
NB : I can't use another tag that
Related
I want to find the specified field with the interface which extends JpaSpecificationExecutor.but i have not idea.
for example,i just need to find id,nickname in the user entity,what shall I do?
#Service
public class UserService {
public Page<User> findAll(User user, Pageable pageable) {
List<Predicate> predicates = new ArrayList<>();
if (user != null) {
//some condition
}
query.where(predicates.toArray(new Predicate[predicates.size()]));
return query.getRestriction();
}
}
#Repository
public interface UserRepository extends JpaRepository<User, Long>, JpaSpecificationExecutor<User> {
}
#Data
#Entity
#Table(name = "sys_user")
public class Note implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(nullable = false, unique = true)
private String email;
#Column(nullable = false)
private String password;
#Column(nullable = false)
private String nickname;
}
Here is answer on your question: https://www.baeldung.com/spring-data-jpa-projections .
I have to implementes Auditing in my aplication.. i inserting this data correctly
but i want to save all atributter from my Entity ,
Exemple, name, epigrafe, .. and olthers.
I implemented the mothod but dosent work, just dont save the atributte..
lets see..
#Entity
#EntityListeners(AuditingEntityListener.class)
#Table(name = "logradouros_historico", schema = "aud")
public class LogradourosHistorico {
#Id
#GeneratedValue
private Long id;
#ManyToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "id_logradouro")
private Logradouros logradouro;
#CreatedBy
private String modificadoPor;
#CreatedDate
#Temporal(TemporalType.TIMESTAMP)
private Date modifiedDate = new Date();
#Enumerated(EnumType.STRING)
private Acoes acao;
#Column(name = "nome")
private String nome; //nome do logradouro
public LogradourosHistorico() {
super();
}
public LogradourosHistorico(Logradouros logradouro, String modificadoPor,
Acoes acao) {
super();
this.logradouro = logradouro;
this.modificadoPor = modificadoPor;
this.acao = acao;
}
//getters and setters
my class entityListner
public class LogradourosEntityListener {
#PostPersist
public void prePersist(Logradouros target) {
perform(target, Acoes.INSERTED);
}
#PreUpdate
public void preUpdate(Logradouros target) {
perform(target, Acoes.UPDATED);
}
#PreRemove
public void preRemove(Logradouros target) {
perform(target, Acoes.DELETED);
}
#Transactional()
private void perform(Logradouros target, Acoes acao) {
target.getNome();
EntityManager entityManager = BeanUtil.getBean(EntityManager.class);
entityManager.persist(new LogradourosHistorico(target, acao));
}
}
my class Logradouros
#Entity
#EntityListeners(LogradourosEntityListener.class)
#Table(name = "logradouros", schema = "glb", uniqueConstraints= #UniqueConstraint(columnNames={"id_entidade", "idLogradouro"}))
public class Logradouros extends Auditable<String> implements Serializable {
private static final long serialVersionUID = 3703309412387185484L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int idLogradouro;
#Column(name = "cep_geral")
private String cepGeral;
#Column(name = "epigrafe")
private String epigrafe;
#NotNull
#Column(name = "nome")
private String nome;
#Column(name = "nome_exibicao")
private String nomeExibicao;
#JoinColumn(name = "id_entidade")
#ManyToOne(/*cascade = CascadeType.ALL*/)
private Entidades entidade;
#NotNull
#JoinColumn(name = "id_municipio")
#ManyToOne(/*cascade = CascadeType.ALL*/)
private Municipios municipio;
// gettrs and settrs
so what i did wrong because i cant get the nome of entity Logradouros
I keep getting the following error with my Entity mappings.
Caused by: org.hibernate.AnnotationException: mappedBy reference an unknown target entity property: edu.indstate.ics.transcript.web.dao.entity.Swrhxml.swbhxml in edu.indstate.ics.transcript.web.dao.entity.Swbhxml.swrhxmls
I am not sure what I am doing wrong. Could use some insight and help on what I am missing here.
My Entity classes are as follows:
#Entity
#Table(name = "SWBHXML" )
public class Swbhxml implements DatabaseObject, Serializable {
private List<Swrhxml> swrhxmls;
private static final long serialVersionUID = 1L;
private Long swbhxmlTransId;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "SWBHXML_TRANS_ID", nullable = false)
public Long getSwbhxmlTransId() {
return swbhxmlTransId;
}
public void setSwbhxmlTransId(Long swbhxmlTransId) {
this.swbhxmlTransId = swbhxmlTransId;
}
#OneToMany(mappedBy = "swbhxml", cascade = CascadeType.ALL)
public List<Swrhxml> getSwrhxmls() {
return swrhxmls;
}
public void setSwrhxmls(List<Swrhxml> swrhxmls) {
this.swrhxmls = swrhxmls;
}
}
#Entity
#Table(name = "SWRHXML" )
public class Swrhxml implements DatabaseObject, Serializable {
private Swbhxml swbhxml;
private static final long serialVersionUID = 1L;
private Long SwrhxmlTransId;
private String SwrhxmlHxpsCode;
private Date SwrhxmlTimeStamp;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumn(name="SWBHXML_TRANS_ID")
public Swbhxml getSwrhxml() {
return swbhxml;
}
public void setSwrhxml(Swbhxml swbhxml) {
this.swbhxml = swbhxml;
}
#Column(name = "SWRHXML_HXPS_CODE", length = 15)
public String getSwrhxmlHxpsCode() {
return SwrhxmlHxpsCode;
}
public void setSwrhxmlHxpsCode(String SwrhxmlHxpsCode) {
this.SwrhxmlHxpsCode = SwrhxmlHxpsCode;
}
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "SWRHXML_TIMESTAMP", nullable = false)
#Temporal(TemporalType.TIMESTAMP)
public Date getSwrhxmlTimeStamp() {
return SwrhxmlTimeStamp;
}
public void setSwrhxmlTimeStamp(Date SwrhxmlTimeStamp) {
this.SwrhxmlTimeStamp = SwrhxmlTimeStamp;
}
}
You use
`mappedBy = "swbhxml"`
^
|___ b here
, but the annotated association is
Swbhxml getSwrhxml()
^
|___ r here
Your getter and setter are named incorrectly. And frankly, with such cryptic and close entity names, you'll probably have many such bugs.
I have some problems with #Embeddable in JAVA JPA.
I have an entity class named "Author":
#Entity
#Table(name = "author")
#XmlRootElement
#NamedQueries({
#NamedQuery(name = "Author.findAll", query = "SELECT a FROM Author a"),
...})
public class Author implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Basic(optional = false)
#Column(name = "aID")
private Integer aID;
#Column(name = "aName")
private String aName;
#Column(name = "aSurname")
private String aSurname;
#Column(name = "aPhone")
private Integer aPhone;
#Embedded
#AttributeOverrides({
#AttributeOverride(name="city",column=#Column(name="Address")),
#AttributeOverride(name="street",column=#Column(table="Address")),
#AttributeOverride(name="number",column=#Column(table="Address"))
}) private Address address;
// set and get methods.
}
Also I have an Embeddable class named "Address":
#Embeddable
#Table(name = "Address")
#XmlRootElement
public class Address implements Serializable
{
private static final long serialVersionUID=1L;
#Column(name="city")
private String city;
#Column(name="street")
private String street;
#Column(name="number")
private int number;
// get and set methods.
}
In my main class I want to insert this values to the database. (I use mySQL) But I am getting an error on this line: em.getTransaction.commit();
public class CreateAuthor extends javax.swing.JFrame {
private static final String PERSISTENCE_UNIT_NAME = "Project";
private static EntityManagerFactory emf;
public void CreateAuthor() {
initComponents();
}
private void ekleButtonActionPerformed(java.awt.event.ActionEvent evt) {
emf = Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
EntityManager em = emf.createEntityManager();
em.getTransaction().begin();
Author author = new Author();
author.setAID(3);
author.setAName("Sheldon");
author.setASurname("Smith");
author.setAPhone(768987);
Address adr = new Address();
adr.setCity("Paris");
adr.setStreet("cinar");
adr.setNumber(12);
author.setAddress(adr);
em.persist(author);
em.getTransaction().commit(); /// error occured
em.close();
}
}
On my database side, I have Author table (aID(pk),aName,aSurname,aPhone)
Address Table (city,street,number)
Do you have any idea why an error is occured?
The goal of Embeddable is to have fields of an object (Address) stored in the same table as the entity's table (Author -> author).
If you want to save them in another table, than Address should be an entity on its own, and there should be a OneToOne or ManyToOne association between Author and Address. The mapping, as is, don't make any sense.
I need 3 entities: User, Contract (which are a many to many relation) and a middle entity: UserContract (this is needed to store some fields).
What I want to know is the correct way to define the relationships between these entities in JPA/EJB 3.0 so that the operations (persist, delete, etc) are OK.
For example, I want to create a User and its contracts and persist them in a easy way.
Currently what I have is this:
In User.java:
#OneToMany(mappedBy = "user", fetch = FetchType.LAZY)
private List<UserContract> userContract;
In Contract.java:
#OneToMany(mappedBy = "contract", fetch = FetchType.LAZY)
private Collection<UserContract> userContract;
And my UserContract.java:
#Entity
public class UserContract {
#EmbeddedId
private UserContractPK userContractPK;
#ManyToOne(optional = false)
private User user;
#ManyToOne(optional = false)
private Contract contract;
And my UserContractPK:
#Embeddable
public class UserContractPK implements Serializable {
#Column(nullable = false)
private long idContract;
#Column(nullable = false)
private String email;
Is this the best way to achieve my goals?
Everything looks right. My advice is to use #MappedSuperclass on top of #EmbeddedId:
#MappedSuperclass
public abstract class ModelBaseRelationship implements Serializable {
#Embeddable
public static class Id implements Serializable {
public Long entityId1;
public Long entityId2;
#Column(name = "ENTITY1_ID")
public Long getEntityId1() {
return entityId1;
}
#Column(name = "ENTITY2_ID")
public Long getEntityId2() {
return entityId2;
}
public Id() {
}
public Id(Long entityId1, Long entityId2) {
this.entityId1 = entityId1;
this.entityId2 = entityId2;
}
}
protected Id id = new Id();
#EmbeddedId
public Id getId() {
return id;
}
protected void setId(Id theId) {
id = theId;
}
}
I omitted obvious constructors/setters for readability. Then you can define UserContract as
#Entity
#AttributeOverrides( {
#AttributeOverride(name = "entityId1", column = #Column(name = "user_id")),
#AttributeOverride(name = "entityId2", column = #Column(name = "contract_id"))
})
public class UserContract extends ModelBaseRelationship {
That way you can share primary key implementation for other many-to-many join entities like UserContract.