I want to find the specified field with the interface which extends JpaSpecificationExecutor.but i have not idea.
for example,i just need to find id,nickname in the user entity,what shall I do?
#Service
public class UserService {
public Page<User> findAll(User user, Pageable pageable) {
List<Predicate> predicates = new ArrayList<>();
if (user != null) {
//some condition
}
query.where(predicates.toArray(new Predicate[predicates.size()]));
return query.getRestriction();
}
}
#Repository
public interface UserRepository extends JpaRepository<User, Long>, JpaSpecificationExecutor<User> {
}
#Data
#Entity
#Table(name = "sys_user")
public class Note implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(nullable = false, unique = true)
private String email;
#Column(nullable = false)
private String password;
#Column(nullable = false)
private String nickname;
}
Here is answer on your question: https://www.baeldung.com/spring-data-jpa-projections .
Related
I have a spring boot application where I need to update a migratedCustomer db table based on userId and phoneNumber.
Since I have to use for loop in the service layer for every update, it is creating a
new transaction and performance is hampered.
how could I make sure only one transaction is created and hence to improve the performance. code is like below
#Entity
#Table(name = "MigratedCustomer")
public class MigratedCustomer {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String userId;
private String phoneNumber;
#Temporal(TemporalType.TIMESTAMP)
private Date createdTimestamp;
private int batchNumber;
private String comment;
}
public class MigratedCustomerService {
#Autowired
private UserRepository userRepository;
public void updateMsisdn(List<MigratedCustomer> savedCustomers) {
for (MigratedCustomer savedCustomer : savedCustomers) {
userRepository.updateStatus(savedCustomer.getUserId(),
savedCustomer.getPhoneNumber());
}
}
}
public interface MsisdnRepository extends JpaRepository<Msisdn, Long> {
#Modifying
#Query(value = "UPDATE Msisdn SET status=INACTIVE where userId=:userId and phoneNumber=:phoneNumber",
nativeQuery = true)
void updateStatus(#Param("userId") String userId, #Param("phoneNumber") String phoneNumber);
}
I want to get a list of users by username, with enabled status and has phone number. I managed to get it working till I add the phone number parameter.
here is my code:
//crud repo
List<Users> findAllByUserNameContainsAndEnabledIsAndMobileNotNull(String userName, String enabled);
// controller
public Set<User> searchByName(#PathVariable String username) throws Exception {
Set<User> result = new HashSet<>();
result.addAll(userRepository.findAllByUserNameContainsAndEnabledIsAndMobileNotNull(username, "Y"));
return result;
}
// user class
public class User{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(precision = 18, scale = 0)
private BigDecimal id;
#Column(name = "Enabled", columnDefinition = "char(1) default 'Y'")
private String enabled;
private String username;
private String mobile;
// getters setters..
What is your phone number parameter called? You said it was working until that. The names have to match.
Here is all supported keywords in the method names:
https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods.query-creation
I have started new project and everything works as expected, so the problem is not in method name. Here is code I've tested:
Entity
#Entity
#Data
#NoArgsConstructor
#AllArgsConstructor
public class User {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(precision = 18, scale = 0)
private BigDecimal id;
#Column(name = "Enabled", columnDefinition = "char(1) default 'Y'")
private String enabled;
private String userName;
private String mobile;
public User(String enabled, String userName, String mobile) {
this.enabled = enabled;
this.userName = userName;
this.mobile = mobile;
}
}
Repositiory
public interface UserRepository extends CrudRepository<User, BigDecimal> {
List<User> findAllByUserNameContainsAndEnabledIsAndMobileNotNull(String userName, String enabled);
}
Test
#SpringBootTest
#ExtendWith(SpringExtension.class)
#ActiveProfiles("test")
class UserRepositoryTest {
#Autowired
private UserRepository userRepository;
#Test
void test_findAllByUserNameContainsAndEnabledIsAndMobileNotNull() {
User user1 = new User("Y", "user1", "mobile");
User user2 = new User("Y", "user2", null);
userRepository.save(user1);
userRepository.save(user2);
List<User> all = userRepository.findAllByUserNameContainsAndEnabledIsAndMobileNotNull("user", "Y");
System.out.println("all = " + all);
}
}
And only one record in the output:
all = [User(id=1, enabled=Y, userName=user1, mobile=mobile)]
I have to implementes Auditing in my aplication.. i inserting this data correctly
but i want to save all atributter from my Entity ,
Exemple, name, epigrafe, .. and olthers.
I implemented the mothod but dosent work, just dont save the atributte..
lets see..
#Entity
#EntityListeners(AuditingEntityListener.class)
#Table(name = "logradouros_historico", schema = "aud")
public class LogradourosHistorico {
#Id
#GeneratedValue
private Long id;
#ManyToOne(cascade = CascadeType.ALL)
#JoinColumn(name = "id_logradouro")
private Logradouros logradouro;
#CreatedBy
private String modificadoPor;
#CreatedDate
#Temporal(TemporalType.TIMESTAMP)
private Date modifiedDate = new Date();
#Enumerated(EnumType.STRING)
private Acoes acao;
#Column(name = "nome")
private String nome; //nome do logradouro
public LogradourosHistorico() {
super();
}
public LogradourosHistorico(Logradouros logradouro, String modificadoPor,
Acoes acao) {
super();
this.logradouro = logradouro;
this.modificadoPor = modificadoPor;
this.acao = acao;
}
//getters and setters
my class entityListner
public class LogradourosEntityListener {
#PostPersist
public void prePersist(Logradouros target) {
perform(target, Acoes.INSERTED);
}
#PreUpdate
public void preUpdate(Logradouros target) {
perform(target, Acoes.UPDATED);
}
#PreRemove
public void preRemove(Logradouros target) {
perform(target, Acoes.DELETED);
}
#Transactional()
private void perform(Logradouros target, Acoes acao) {
target.getNome();
EntityManager entityManager = BeanUtil.getBean(EntityManager.class);
entityManager.persist(new LogradourosHistorico(target, acao));
}
}
my class Logradouros
#Entity
#EntityListeners(LogradourosEntityListener.class)
#Table(name = "logradouros", schema = "glb", uniqueConstraints= #UniqueConstraint(columnNames={"id_entidade", "idLogradouro"}))
public class Logradouros extends Auditable<String> implements Serializable {
private static final long serialVersionUID = 3703309412387185484L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private int idLogradouro;
#Column(name = "cep_geral")
private String cepGeral;
#Column(name = "epigrafe")
private String epigrafe;
#NotNull
#Column(name = "nome")
private String nome;
#Column(name = "nome_exibicao")
private String nomeExibicao;
#JoinColumn(name = "id_entidade")
#ManyToOne(/*cascade = CascadeType.ALL*/)
private Entidades entidade;
#NotNull
#JoinColumn(name = "id_municipio")
#ManyToOne(/*cascade = CascadeType.ALL*/)
private Municipios municipio;
// gettrs and settrs
so what i did wrong because i cant get the nome of entity Logradouros
I have two entities in Spring Data JPA:
User--->* TaxPayment
The goal is to get the all the taxpayments related to user_id:
User.java
public class User extends AbstractAuditingEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
..........
}
TaxPayment.jva
public class TaxPayment implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#NotNull
#Column(name = "payment_date", nullable = false)
private LocalDate paymentDate;
#NotNull
#Column(name = "amount", precision=10, scale=2, nullable = false)
private BigDecimal amount;
#Column(name = "reference")
private String reference;
#ManyToOne
private User user;
public Long getId() {
return id;
}..
}
I dont wan't to have oneTOMany Annotation from User.java and the column mapped in the Taxpayment as user_id.
Specification class as follows:
final class TaxPaymentSpecification {
private TaxPaymentSpecification(){
}
static Specification<TaxPayment> hasUser(Long userId){
return new Specification<TaxPayment>() {
#Override
public Predicate toPredicate(Root<TaxPayment> arg0, CriteriaQuery<?> arg1,
CriteriaBuilder arg2) {
// TODO Auto-generated method stub
Root<TaxPayment> root = arg0;
Subquery<Long> subqry = arg1.subquery(Long.class);
Root<User> user = subqry.from(User.class);
final Join<User,TaxPayment> taxpays = root.join("user");
subqry.select(taxpays.<Long> get("user_id"));
subqry.where(arg2.equal(user.<Long> get("id"),userId));
return arg2.in(arg0.get("user_id")).value(subqry);
}
};
}
}
Is specification is correct or wrong as per my goal to get all the TaxPayment related to user_id?
There is no need to use subquery if you already know the userId, which will be the value of user_id in TaxPayment table:
#Override
public Predicate toPredicate(Root<TaxPayment> arg0, CriteriaQuery<?> arg1,
CriteriaBuilder arg2) {
return arg2.equal(arg0.get("user_id"), userId);
}
I need 3 entities: User, Contract (which are a many to many relation) and a middle entity: UserContract (this is needed to store some fields).
What I want to know is the correct way to define the relationships between these entities in JPA/EJB 3.0 so that the operations (persist, delete, etc) are OK.
For example, I want to create a User and its contracts and persist them in a easy way.
Currently what I have is this:
In User.java:
#OneToMany(mappedBy = "user", fetch = FetchType.LAZY)
private List<UserContract> userContract;
In Contract.java:
#OneToMany(mappedBy = "contract", fetch = FetchType.LAZY)
private Collection<UserContract> userContract;
And my UserContract.java:
#Entity
public class UserContract {
#EmbeddedId
private UserContractPK userContractPK;
#ManyToOne(optional = false)
private User user;
#ManyToOne(optional = false)
private Contract contract;
And my UserContractPK:
#Embeddable
public class UserContractPK implements Serializable {
#Column(nullable = false)
private long idContract;
#Column(nullable = false)
private String email;
Is this the best way to achieve my goals?
Everything looks right. My advice is to use #MappedSuperclass on top of #EmbeddedId:
#MappedSuperclass
public abstract class ModelBaseRelationship implements Serializable {
#Embeddable
public static class Id implements Serializable {
public Long entityId1;
public Long entityId2;
#Column(name = "ENTITY1_ID")
public Long getEntityId1() {
return entityId1;
}
#Column(name = "ENTITY2_ID")
public Long getEntityId2() {
return entityId2;
}
public Id() {
}
public Id(Long entityId1, Long entityId2) {
this.entityId1 = entityId1;
this.entityId2 = entityId2;
}
}
protected Id id = new Id();
#EmbeddedId
public Id getId() {
return id;
}
protected void setId(Id theId) {
id = theId;
}
}
I omitted obvious constructors/setters for readability. Then you can define UserContract as
#Entity
#AttributeOverrides( {
#AttributeOverride(name = "entityId1", column = #Column(name = "user_id")),
#AttributeOverride(name = "entityId2", column = #Column(name = "contract_id"))
})
public class UserContract extends ModelBaseRelationship {
That way you can share primary key implementation for other many-to-many join entities like UserContract.