I have a table Orders, it has the following columns:
OrderID, ClientID, BankNumber, Adres, Name;
I want to write a query that gives me this result: distinct clientid name and adres on one row with all the belonging orders and corespondating bankaccount numbers on one row: This is my example.
ClientID Adres Name order1 Banknumber Order2 Banknumber order3 Banknumber
First you cannot query something and come up with a results set with infinite number of columns, but you could combine orders and show them in 1 column.
if you are on SQL Azure or SQL2017 you can also use STRING_AGG like this:
select customer.Id, customer.Name, orderSummary.orderData
(select STRING_AGG(orderID+'-'+banknumber+', ') as orderData from orders where customerId = customer.Id) orderSummary
from Customers as customer
You can look at this post for more answers
How to concatenate text from multiple rows into a single text string in SQL server?
And Subquery from Microsoft:
https://technet.microsoft.com/en-us/library/ms189575(v=sql.105).aspx
here is a working sample.
Hope it works for you.
You need to build the Order1, order2, order3...and BankNumber1,BankNumber2...dynamically. I have hard coded in my example
drop table #t1
create table #t1(OrderID Int, ClientID int, BankNumber varchar(50), [Address] varchar(50), Name varchar(50))
insert into #t1
select 1,11,'111','xyz1','xyz'
union all
select 2,22,'112','xyz2','xyzz'
union all
select 3,33,'113','xyz3','xyzzz'
union all
select 100,11,'111','xyz1','xyz'
union all
select 200,22,'112','xyz2','xyzz'
union all
select 300,33,'113','xyz3','xyzzz'
;with cte as
(
select OrderID,ClientID,BankNumber,Address,Name,ROW_NUMBER()over (partition by clientid order by orderid asc) RN
from #t1
)
select ClientID
,max([Order 1]) Order1
,max([Order 2]) Order2
,max([BankNumber 1]) BankNumber1
,max([BankNumber 2]) BankNumber2
from
(
select ClientID,Address,Name,OrderID,BankNumber,'Order '+cast(rn as varchar(10)) OrderSeq
,'BankNumber '+cast(rn as varchar(10)) BankNumberSeq
from cte
) as ST
pivot(max(OrderID) for OrderSeq in ([Order 1],[Order 2])) as pt1
pivot(max(BankNumber) for BankNumberSeq in ([BankNumber 1],[BankNumber 2])) as pt2
group by ClientID
Related
I didn't find my case on the Internet. Tell me how i can delete duplicates if the values are in different columns.
I have a table with a lot of values, for example:
|Id1|Id2|
|89417980|89417978|
|89417980|89417979|
|89417978|89417980|
|89417979|89417980|
I need to exclude duplicates and leave in the answer only:
|Id1|Id2|
|89417980|89417978|
|89417980|89417979|
min/max does not work here, as the values may be different.
I tried to union/join tables on a table/exclude results with temporary tables, but in the end I come to the beginning.
Assuming id1 and id2 are primary keys columns you could try this
DECLARE #tbl table (id1 int, id2 int )
INSERT INTO #tbl
SELECT 89417980, 89417978
UNION SELECT 89417980, 89417979
UNION SELECT 89417978, 89417980
UNION SELECT 89417979, 89417980
SELECT * FROM #tbl
;WITH CTE AS (--Get comparable value as "cs"
SELECT
IIF(id1 > id2, CHECKSUM(id1, id2), CHECKSUM(id2,id1)) as cs
, id1
, id2
, ROW_NUMBER() OVER (order by id1, id2) as rn
FROM #tbl
)
, CTE2 AS ( --Get rows to keep
SELECT MAX (rn) as rn
FROM CTE
GROUP BY cs
HAVING COUNT(*) > 1
)
DELETE tbl -- Delete all except the rows to keep
FROM #tbl tbl
WHERE NOT EXISTS(SELECT 1
FROM CTE2
JOIN CTE ON CTE.rn = CTE2.rn
WHERE CTE.id1 = tbl.id1
AND CTE.id2 = tbl.id2
)
SELECT * FROM #tbl
I need to write a T-SQL group by query for a table with multiple dates and seq columns:
DROP TABLE #temp
CREATE TABLE #temp(
id char(1),
dt DateTime,
seq int)
Insert into #temp values('A','2015-03-31 10:00:00',1)
Insert into #temp values('A','2015-08-31 10:00:00',2)
Insert into #temp values('A','2015-03-31 10:00:00',5)
Insert into #temp values('B','2015-09-01 10:00:00',1)
Insert into #temp values('B','2015-09-01 10:00:00',2)
I want the results to contains only the items A,B with their latest date and the corresponding seq number, like:
id MaxDate CorrespondentSeq
A 2015-08-31 10:00:00.000 2
B 2015-09-01 10:00:00.000 2
I am trying with (the obviously wrong!):
select id, max(dt) as MaxDate, max(seq) as CorrespondentSeq
from #temp
group by id
which returns:
id MaxDate CorrespondentSeq
A 2015-08-31 10:00:00.000 5 <-- 5 is wrong
B 2015-09-01 10:00:00.000 2
How can I achieve that?
EDIT
The dt datetime column has duplicated values (exactly same date!)
I am using SQL Server 2005
You can use a ranking subselect to get only the highest ranked entries for an id:
select id, dt, seq
from (
select id, dt, seq, rank() over (partition by id order by dt desc, seq desc) as r
from #temp
) ranked
where r=1;
SELECT ID, DT, SEQ
FROM (
SELECT ID, DT, SEQ, Row_Number()
OVER (PARTITION BY id ORDER BY dt DESC, seq DESC) AS row_number
FROM temp
) cte
WHERE row_number = 1;
Demo : http://www.sqlfiddle.com/#!3/3e3d5/5
With trial and errors maybe I have found a solution, but I'm not completely sure this is correct:
select A.id, B.dt, max(B.seq)
from (select id, max(dt) as maxDt
from #temp
group by id) as A
inner join #temp as B on A.id = B.id AND A.maxDt = B.dt
group by A.id, B.dt
Select id, dt, seq
From #temp t
where dt = (Select Max(dt) from #temp
Where id = t.Id)
If there are duplicate rows, then you also need to specify what the query processor should use to determine which of the duplicates to return. Say you want the lowest value of seq,
Then you could write:
Select id, dt, seq
From #temp t
where dt = (Select Max(dt) from #temp
Where id = t.Id)
and seq = (Select Min(Seq) from #temp
where id = t.Id
and dt = t.dt)
I have two tables (one for quarter one, one for quarter two), each of which contains employees who have bonus in that quarter. Every employee has a unique id in the company.
I want to get all employees who has bonus in either q1 or q2. No duplicate employee is needed. Both Id, and Amount are required.
Below is my solution, I want to find out if there is a better solution.
declare #q1 table (
EmployeeID int identity(1,1) primary key not null,
amount int
)
declare #q2 table (
EmployeeID int identity(1,1) primary key not null,
amount int
)
insert into #q1
(amount)
select 1
insert into #q1
(amount)
select 2
select * from #q1
insert into #q2
(amount)
select 1
insert into #q2
(amount)
select 11
insert into #q2
(amount)
select 22
select * from #q2
My Solution:
;with both as
(
select EmployeeID
from #q1
union
select EmployeeID
from #q2
)
select a.EmployeeID, a.amount
from #q1 as a
where a.EmployeeID in (select EmployeeID from both)
union all
select b.EmployeeID, b.amount
from #q2 as b
where b.EmployeeID in (select EmployeeID from both) and b.EmployeeID NOT in (select EmployeeID from #q1)
Result:
EmployeeID, Amount
1 1
2 2
3 22
SELECT EmployeeID, Name, SUM(amount) AS TotalBonus
FROM
(SELECT EmployeeID, Name, amount
from #q1
UNION ALL
SELECT EmployeeID, Name, amount
from #q2) AS all
GROUP BY EmployeeID, Name
The subselect UNIONS both tables together. The GROUP BY gives you one row per employee and the SUM means that if someone got lucky in both qs then you get the total. I'm guessing that's the right thing for you.
try this one:
SELECT EmployeeID
FROM EmployeeList
WHERE EmployeeID IN
(SELECT EmployeeID From QuarterOne
UNION
SELECT EmployeeID From QuarterTwo)
OR by using JOIN
SELECT EmployeeID
FROM EmployeeList a INNER JOIN QuarterTwo b
ON a.EmployeeID = b.EmployeeID
INNER JOIN QuarterTwo c
ON a.EmployeeID = c.EmployeeID
This will return all EmployeeID that has record in either quarter.
Try:
SELECT DISTINCT q1.EmployeeID --- Same as q2.EmployeeID thanks to the join
, q1.EmployeeName -- Not defined in OP source.
FROM #q1 AS q1
CROSS JOIN #q2 AS q2
WHERE q1.amount IS NOT NULL
OR q2.amount IS NOT NULL
Table name: Table1
id name
1 1-aaa-14 milan road
2 23-abcde-lsd road
3 2-mnbvcx-welcoome street
I want the result like this:
Id name name1 name2
1 1 aaa 14 milan road
2 23 abcde lsd road
3 2 mnbvcx welcoome street
This function ought to give you what you need.
--Drop Function Dbo.Part
Create Function Dbo.Part
(#Value Varchar(8000)
,#Part Int
,#Sep Char(1)='-'
)Returns Varchar(8000)
As Begin
Declare #Start Int
Declare #Finish Int
Set #Start=1
Set #Finish=CharIndex(#Sep,#Value,#Start)
While (#Part>1 And #Finish>0)Begin
Set #Start=#Finish+1
Set #Finish=CharIndex(#Sep,#Value,#Start)
Set #Part=#Part-1
End
If #Part>1 Set #Start=Len(#Value)+1 -- Not found
If #Finish=0 Set #Finish=Len(#Value)+1 -- Last token on line
Return SubString(#Value,#Start,#Finish-#Start)
End
Usage:
Select ID
,Dbo.Part(Name,1,Default)As Name
,Dbo.Part(Name,2,Default)As Name1
,Dbo.Part(Name,3,Default)As Name2
From Dbo.Table1
It's rather compute-intensive, so if Table1 is very long you ought to write the results to another table, which you could refresh from time to time (perhaps once a day, at night).
Better yet, you could create a trigger, which automatically updates Table2 whenever a change is made to Table1. Assuming that column ID is primary key:
Create Table Dbo.Table2(
ID Int Constraint PK_Table2 Primary Key,
Name Varchar(8000),
Name1 Varchar(8000),
Name2 Varchar(8000))
Create Trigger Trigger_Table1 on Dbo.Table1 After Insert,Update,Delete
As Begin
If (Select Count(*)From Deleted)>0
Delete From Dbo.Table2 Where ID=(Select ID From Deleted)
If (Select Count(*)From Inserted)>0
Insert Dbo.Table2(ID, Name, Name1, Name2)
Select ID
,Dbo.Part(Name,1,Default)
,Dbo.Part(Name,2,Default)
,Dbo.Part(Name,3,Default)
From Inserted
End
Now, do your data manipulation (Insert, Update, Delete) on Table1, but do your Select statements on Table2 instead.
The below solution uses a recursive CTE for splitting the strings, and PIVOT for displaying the parts in their own columns.
WITH Table1 (id, name) AS (
SELECT 1, '1-aaa-14 milan road' UNION ALL
SELECT 2, '23-abcde-lsd road' UNION ALL
SELECT 3, '2-mnbvcx-welcoome street'
),
cutpositions AS (
SELECT
id, name,
rownum = 1,
startpos = 1,
nextdash = CHARINDEX('-', name + '-')
FROM Table1
UNION ALL
SELECT
id, name,
rownum + 1,
nextdash + 1,
CHARINDEX('-', name + '-', nextdash + 1)
FROM cutpositions c
WHERE nextdash < LEN(name)
)
SELECT
id,
[1] AS name,
[2] AS name1,
[3] AS name2
/* add more columns here */
FROM (
SELECT
id, rownum,
part = SUBSTRING(name, startpos, nextdash - startpos)
FROM cutpositions
) s
PIVOT ( MAX(part) FOR rownum IN ([1], [2], [3] /* extend the list here */) ) x
Without additional modifications this query can split names consisting of up to 100 parts (that's the default maximum recursion depth, which can be changed), but can only display no more than 3 of them. You can easily extend it to however many parts you want it to display, just follow the instructions in the comments.
select T.id,
substring(T.Name, 1, D1.Pos-1) as Name,
substring(T.Name, D1.Pos+1, D2.Pos-D1.Pos-1) as Name1,
substring(T.Name, D2.Pos+1, len(T.name)) as Name2
from Table1 as T
cross apply (select charindex('-', T.Name, 1)) as D1(Pos)
cross apply (select charindex('-', T.Name, D1.Pos+1)) as D2(Pos)
Testing performance of suggested solutions
Setup:
create table Table1
(
id int identity primary key,
Name varchar(50)
)
go
insert into Table1
select '1-aaa-14 milan road' union all
select '23-abcde-lsd road' union all
select '2-mnbvcx-welcoome street'
go 10000
Result:
if you always will have 2 dashes, you can do the following by using PARSENAME
--testing table
CREATE TABLE #test(id INT, NAME VARCHAR(1000))
INSERT #test VALUES(1, '1-aaa-14 milan road')
INSERT #test VALUES(2, '23-abcde-lsd road')
INSERT #test VALUES(3, '2-mnbvcx-welcoome street')
SELECT id,PARSENAME(name,3) AS name,
PARSENAME(name,2) AS name1,
PARSENAME(name,1)AS name2
FROM (
SELECT id,REPLACE(NAME,'-','.') NAME
FROM #test)x
if you have dots in the name column you have to first replace them and then replace them back to dots in the end
example, by using a tilde to substitute the dot
INSERT #test VALUES(3, '5-mnbvcx-welcoome street.')
SELECT id,REPLACE(PARSENAME(name,3),'~','.') AS name,
REPLACE(PARSENAME(name,2),'~','.') AS name1,
REPLACE(PARSENAME(name,1),'~','.') AS name2
FROM (
SELECT id,REPLACE(REPLACE(NAME,'.','~'),'-','.') NAME
FROM #test)x
I am trying to find duplicate rows in my DB, like this:
SELECT email, COUNT(emailid) AS NumOccurrences
FROM users
GROUP BY emailid HAVING ( COUNT(emailid) > 1 )
This returns the emailid and the number of matches found. Now what I want do is compare the ID column to another table I have and set a column there with the count.
The other table has a column named duplicates, which should contain the amount of duplicates from the select. So let's say we have 3 rows with the same emailid. The duplicates column has a "3" in all 3 rows. What I want is a "2" in the first 2 and nothing or 0 in the last of the 3 matching ID rows.
Is this possible?
Update:
I managed to have a temporary table now, which looks like this:
mailid | rowcount | AmountOfDups
643921 | 1 | 3
643921 | 2 | 3
643921 | 3 | 3
Now, how could I decide that only the first 2 should be updated (by mailid) in the other table? The other table has mailid as well.
SELECT ...
ROW_NUMBER() OVER (PARTITION BY email ORDER BY emailid DESC) AS RN
FROM ...
...is a great starting point for such a problem. Never underestimate the power of ROW_NUMBER()!
Using Sql Server 2005+ you could try something like (full example)
DECLARE #Table TABLE(
ID INT IDENTITY(1,1),
Email VARCHAR(20)
)
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'c'
INSERT INTO #Table (Email) SELECT 'a'
INSERT INTO #Table (Email) SELECT 'b'
INSERT INTO #Table (Email) SELECT 'a'
; WITH Duplicates AS (
SELECT Email,
COUNT(ID) TotalDuplicates
FROM #Table
GROUP BY Email
HAVING COUNT(ID) > 1
)
, Counts AS (
SELECT t.ID,
ROW_NUMBER() OVER(PARTITION BY t.Email ORDER BY t.ID) EmailID,
d.TotalDuplicates
FROM #Table t INNER JOIN
Duplicates d ON t.Email = d.Email
)
SELECT ID,
CASE
WHEN EmailID = TotalDuplicates
THEN 0
ELSE TotalDuplicates - 1
END Dups
FROM Counts