I am trying to delete with a select and I tried to follow the instructions in the others post.
Now, my query doesn't return an error but it won't stop running.
I have almost 120k lines in the table cours, 120k lines in the table liste_des_cours_has_cours and 30 lines in liste_des_cours
delete from cours where Id_cours in
(
select cours.Id_cours from (select * from cours) as courssub1
where Id_cours not in
(
select cours.Id_cours from (select * from cours) as courssub2
join (liste_des_cours_has_cours, liste_des_cours)
on courssub2.Id_cours = liste_des_cours_has_cours.Id_cours and liste_des_cours_has_cours.Id_liste_des_cours = liste_des_cours.Id_liste_des_cours
)
);
You can try something like
delete c
from liste_des_cours_has_cours a inner join liste_des_cours b
on a.Id_liste_des_cours = b.Id_liste_des_cours
right join cours c
on c.Id_cours = a.Id_cours
where a.Id_cours is null;
Check here Demo
Related
I have History table and transaction table.....and reference table...
If status in reference table is CLOSE then take those record verify in History table if not there insert from transaction table..... wiring query like this .... checking better one... please advice.. this query can be used for huge data ?
INSERT INTO LIB1.HIST_TBL
( SELECT R.ACCT, R.STATUS, R.DATE FROM
LIB2.HIST_TBL R JOIN LIB1.REF_TBL C
ON R.ACCT = C.ACCT WHERE C.STATUS = '5'
AND R.ACCT NOT IN
(SELECT ACTNO FROM LIB1.HIST_TBL)) ;
If you're on a current release of DB2 for i, take a look at the MERGE statement
MERGE INTO hist_tbl H
USING (SELECT * FROM ref_tbl R
WHERE r.status = 'S')
ON h.actno = r.actno
WHEN NOT MATCHED THEN
INSERT (actno,histcol2, histcol3) VALUES (r.actno,r.refcol2,r.refcol3)
--if needed
WHEN MATCHED
UPDATE SET (actno,histcol2, histcol3) = (r.actno,r.refcol2,r.refcol3)
Hi i am new to oracle_sqldeveloper can you please give me the answer how to know the table structure and relationships of a database.
You can try
DESC <table_name>
Try this:
select table_name, column_name, data_type
from all_tab_columns
where table_name = <TABLE_NAME_HERE>
and owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
If you have comments on your table then to get columns' comments:
select tc.table_name, tc.column_name, tc.data_type, cc.comments
from all_col_comments cc, all_tab_columns tc
where tc.table_name = <TABLE_NAME_HERE>
and tc.owner = <OWNER_OF_TABLE_HERE>
and tc.table_name = cc.table_name
and tc.column_name = cc.column_name
and tc.owner = cc.owner
If you are logged in under owner of the table you can write this:
select table_name, column_name, data_type
from user_tab_columns
where table_name = <TABLE_NAME_HERE>
or to get columns with comments
select tc.table_name, tc.column_name, tc.data_type, cc.comments
from user_col_comments cc, user_tab_columns tc
where tc.table_name = '<TABLE_NAME_HERE>'
and tc.owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
and tc.table_name = cc.table_name
and tc.column_name = cc.column_name
To get relationships between tables user this query:
select uc1.table_name
, uc1.constraint_name
, cc1.column_name
, uc2.table_name r_table_name
, uc2.constraint_name r_constraint_name
, cc2.column_name r_column_name
from all_constraints uc1
, all_constraints uc2
, all_cons_columns cc1
, all_cons_columns cc2
where 1 = 1
and uc2.constraint_type = 'R'
and uc1.constraint_name = uc2.r_constraint_name
and cc1.table_name = uc1.table_name
and cc1.constraint_name = uc1.constraint_name
and cc2.table_name = uc1.table_name
and cc2.constraint_name = uc1.constraint_name
and uc1.owner = '<YOUR_USER_HERE_IN_CAPITAL_LETTERS>'
and uc2.owner = uc1.owner
and cc1.owner = uc1.owner
and cc2.owner = uc1.owner
order by 1
/
Columns with the "R_" prefix mean that they are foreign data (they represent foreign keys). As you can see, I used the tables with the "ALL_" prefix, to use similar tables with the "USER_" prefix, get rid of the "OWNER" section.
To know more about oracle data dictionary read this
1) type your table name.
2) right click on table name & click Open Declaration.
When I run the selects below, I do not get Field3 in the result set, why?
Select
a.Field1,
a.Field2,
a.Field3,
sum(IsNull(a.Field4, 0)) AS SomeAlias1,
a.SomeField5,
a.SomeField6,
a.SomeField7
From SomeTable a
INNER JOIN SomeView1 v on v.au = a.au
inner join (select Username, House from Users userBuildings where UserName = #UserName) as userHouses on userHouses.au = a.au
WHERE
(((where claus logic here....
Group BY a.Field1,
a.Field2,
a.SomeAlias1,
a.Field3,
a.Field4,
a.Field5,
a.Field6,
a.Fielf7
)
Select
transBudget.Field1,
transBudget.Field2,
transDiscount.Field4,
... some other fields...
IsNull(transDiscount.Actual, 0) - IsNull(transBudget.Actual, 0) AS Variance
from (Select * from Transactdions Where TransDesc = 'Budget') AS transBudget
FULL OUTER JOIN
(Select * from Transactions Where TransDesc = 'Discount') AS transDiscount
ON transBudget.Market = transDiscount.Market AND transBudget.SubMarket = transDiscount.SubMarket
I see every field except Field3 for some reason and it's beyond me how the heck this can happen.
In the second part of your query, you are missing field 3.
Select
transBudget.Field1,
transBudget.Field2,
transDiscount.Field4,
... some other fields...
IsNull(transDiscount.Actual, 0)
You appear to have two separate SQL queries there. The first one contains Field3, but the second one does not.
There are two inserts in my trigger which is fired by an update. My Vendor_Hist table has a field called thID which is the primary key in Task_History table. thID gets its' value from mySeq.nextval.
INSERT INTO TASK_HISTORY
( thID, phId, LABOR, VERSION )
( select mySeq.NEXTVAL, mySeq2.CurrVal, LABOR, tmpVersion
from tasks t
where t.project_id = :new.project_ID );
select mySeq.currval into tmpTHID from dual; -- problem here!
INSERT INTO VENDOR_HIST
( vhID, thID, Amount, Position, version )
( select mySeq3.NEXTVAL, tmpTHID,
Amount, Position, tmpVersion
from vendors v2, tasks t2
where v2.myID = t2.myID
and t2.project_id = :new.project_ID );
Now, my problem is the tmpTHID always the latest value of mySeq.nextVal. So, if thID in task_history is 1,2,3, I get three inserts into vendor_hist table with 3,3,3. It has to be 1,2,3. I also tried
INSERT INTO TASK_HISTORY
( thID, phId, LABOR, VERSION )
( select mySeq.NEXTVAL, mySe2.CurrVal, LABOR, tmpVersion
from tasks t
where t.project_id = :new.project_ID ) returning thID into :tmpTHID;
but then I get a "warning compiled with errors" message when I execute the trigger. How do I make sure that the thID in first insert is also the same in my second insert?
Hope it makes sense.
for i in (select * from tasks t
where t.project_id = :new.project_id)
loop
insert into task_history
( thID, phId, LABOR, VERSION )
values
(mySeq.NEXTVAL, mySeq2.CurrVal, i.LABOR, i.tmpVersion);
for each j in (select * from vendors v
where i.myId = v.myId)
loop
insert into vendor_history
( vhID, thID, Amount, Position, version )
values
(mySeq3.NEXTVAL, mySeq.CURRVAL, j.Amount, j.Position, j.tmpVersion)
end loop;
end loop;
I'm assuming the columns inserted in the second insert are from the VENDORS table; if not, the referencing cursor (i or j) should be used as appropriate.
Instead of the currVal, it works with the following subselect.
( select min(thID) from task_history t3
where t3.project_id = t2.project_id
and t3.myID = t2.myID
and t3.version = tmpVersion ),
I need to delete some rows from table where indexes are equal indexes in table variable
declare #m_table as table
(
number NUMERIC(18,0)
)
...
inserting some rows into #m_table
...
DELETE ct FROM [dbo].[customer_task] ct
inner join project_customer pc on pc.id_customer = #m_table.number
inner join customer_user cu on cu.id_project_customer = pc.id
WHERE ct.id_csr_user = cu.id AND ct.id_status = 1;
but this code generates an error: Must declare the scalar variable "#m_table" How to solve that ?
You probably have a 'GO' (a batch separator) in those '...'
Variable declarations do not span batches.
The error means that SQL is expecting you to treat #m_table like a standard table, rather than a scalar (int, bit, etc.) variable. Perhaps something like this will work?
DELETE ct FROM [dbo].[customer_task] ct
WHERE ct.id_csr_user IN (
SELECT cu.id FROM customer_user cu
INNER JOIN project_customer pc ON pc.id = cu.id_project_customer
WHERE pc.id_customer IN (SELECT number FROM #m_table.number)
) AND ct.id_status = 1;