I have created a GUI with 5 Textboxes. I call them $textboxHost1 - 5.
Now I have an array in which I'm gonna save up to 5 values and then write each value according to the order into the textboxes. The first value in the array should be written into the first $textboxHost1 box.
To do that, I would like to make a for loop and have written this code
#$hostnameneingabe: Array, in which the values are saved.
$hostnameneingabeCount = $hostnameneingabe.Count
for($i = 0; $i -le $hostnameneingabeCount; $i++) {
#code here
}
Now, I'm looking for a way to go down the order, so that the first $textboxHost1 comes firstly and so on.
To be accurate, the variable $textboxHost should be incrementally increased in the loop and the values at the position $i in the array should be written into that textbox.
sth like
for($i = 0; $i -le $hostnameneingabeCount; $i++) {
$textboxHost$i =
}
I suppose you would be liking something like this?
$textboxHosts = Get-Variable | ? {$_.Name -match "textBoxHost[0-9]" -and $_.Value -ne $null} | sort Name
After this you can process that var with eg. a foreach:
foreach ($textboxHost in $textboxHosts) {<# Do some stuff #>}
You have to use an array, because otherwise you can't loop through them:
$textboxHost = #(0..4)
#Textbox 0
$textboxHost[0] = New-Object System.Windows.Forms.TextBox
$textboxHost[0].Text = "test"
#Textbox 1
$textboxHost[1] = New-Object System.Windows.Forms.TextBox
$textboxHost[1].Text = "test"
foreach ($textbox in $textboxHost){
#Do whatever you want with the textbox
$textbox =
}
When I used (Get-WmiObject win32_physicalmedia).serialnumber the output was in hex. Example: 31323334353637383930. Then then I used the code below
$pass=""
$t=(Get-WmiObject win32_physicalmedia).serialnumber
$t -split '(.{2})' |%{ if ($_ -ne "") { $pass+=[CHAR]([CONVERT]::toint16("$_",16)) }}
write host $pass
The output was: 1234567890. The problem is that 1234567890 is not the serial number -- the real serial number is 2143658709. I need a script to swap the number $input "1234567890" to $output "214365768709".
this presumes your SN string is an even number of characters, and that the real number simply reverses the character pairs.
$InString = '1234567890'
$OutString = ''
foreach ($Index in 0..($InString.Length / 2))
{
$CurPos = $Index * 2
$OutString += $InString[$CurPos + 1] + $InString[$CurPos]
}
$OutString
output = 2143658709
I think this is called "middle endian" format, where every two bytes are reversed: middle-endian
Coming from a post here: WMI Win32_PhysicalMedia SMART ID in Vista and 7 Permissions
I am new to powershell scripts and not sure how to achieve the below:
$finalArray = #()
$tempArray0 = 'A'
$tempArray1 = 'B'
$tempArray2 = 'C'
FOR (i=0; i -eq 5; i++) {$finalArray += $tempArray[i]}
$finalArray
Output Should be:
A
B
C
If the variable name is itself variable, you'll have to use the Get-Variable cmdlet to retrieve its value:
$finalArray = #()
$tempArray0 = 'A'
$tempArray1 = 'B'
$tempArray2 = 'C'
for($i=0; $i -le 2; $i++) {
$finalArray += (Get-Variable "temparray$i" -ValueOnly)
}
$finalArray
If you want to create variables with variable names, use the New-Variable cmdlet:
$Values = 'A','B','C'
for($i = 0; $i -lt $Values.Count; $i++){
New-Variable -Name "tempvalue$i" -Value $Values[$i]
}
which would result in:
PS C:\> $tempvalue1
B
Although the above will solve the example you've presented, I can think of very few cases where you wouldn't be better of using a [hashtable] instead of variable variable names - they're usually an over-complication, and you'll end up with unnecessary code anyways because you need to calculate the variable names at least twice (during creation and again when reading the value).
From the comments, it sounds like you're trying to generate input for a password generator. This can be simplified grossly, without resorting to variable variable names:
# Create a hashtable and generate the characters
$CharArrays = #{
Letters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray()
Numbers = 0..9
}
# Generate some letters for the password
$PasswordChars = $CharArrays['Letters'] |Get-Random -Count 10
# Generate a few digits
$PasswordChars += $CharArrays['Numbers'] |Get-Random -Count 4
# Shuffle them around a bit
$PasswordChars = $PasswordChars |Sort-Object {Get-Random}
# Create your password
$Password = $PasswordChars -join ''
I have the following PowerShell script that creates a random string of 15 digits, for use as an Active Directory password.
The trouble is, this works great most of the time, but on some occasions it doesn't use a number or symbol. I just get 15 letters. This is then not usable as an Active Directory password, as it must have at least one number or symbol in it.
$punc = 46..46
$digits = 48..57
$letters = 65..90 + 97..122
$YouShallNotPass = get-random -count 15 `
-input ($punc + $digits + $letters) |
% -begin { $aa = $null } `
-process {$aa += [char]$_} `
-end {$aa}
Write-Host "Password is $YouShallNotPass"
How would I amend the script to always have at least one random number or symbol in it?
Thank you.
You could invoke the Get-Random cmdlet three times, each time with a different input parameter (punc, digit and letters), concat the result strings and shuffle them using another Get-Random invoke:
(Get-Random -Count 15 -InputObject ([char[]]$yourPassword)) -join ''
However, why do you want to reinvent the wheel? Consider using the following GeneratePassword function:
[Reflection.Assembly]::LoadWithPartialName("System.Web")
[System.Web.Security.Membership]::GeneratePassword(15,2)
And to ensure, it contains at least one random number (you already specify the number of symbols):
do {
$pwd = [System.Web.Security.Membership]::GeneratePassword(15,2)
} until ($pwd -match '\d')
As suggested by jisaak, there is no 100% guaranty that the Membership.GeneratePassword Method generates a password that meets the AD complexity requirements.
That's why I reinvented the wheel:
Function Create-String([Int]$Size = 8, [Char[]]$CharSets = "ULNS", [Char[]]$Exclude) {
$Chars = #(); $TokenSet = #()
If (!$TokenSets) {$Global:TokenSets = #{
U = [Char[]]'ABCDEFGHIJKLMNOPQRSTUVWXYZ' #Upper case
L = [Char[]]'abcdefghijklmnopqrstuvwxyz' #Lower case
N = [Char[]]'0123456789' #Numerals
S = [Char[]]'!"#$%&''()*+,-./:;<=>?#[\]^_`{|}~' #Symbols
}}
$CharSets | ForEach {
$Tokens = $TokenSets."$_" | ForEach {If ($Exclude -cNotContains $_) {$_}}
If ($Tokens) {
$TokensSet += $Tokens
If ($_ -cle [Char]"Z") {$Chars += $Tokens | Get-Random} #Character sets defined in upper case are mandatory
}
}
While ($Chars.Count -lt $Size) {$Chars += $TokensSet | Get-Random}
($Chars | Sort-Object {Get-Random}) -Join "" #Mix the (mandatory) characters and output string
}; Set-Alias Create-Password Create-String -Description "Generate a random string (password)"
Usage:
The Size parameter defines the length of the password.
The CharSets parameter defines the complexity where the character U,
L, N and S stands for Uppercase, Lowercase, Numerals and Symbols.
If supplied in lowercase (u, l, n or s) the returned string
might contain any of character in the concerned character set, If
supplied in uppercase (U, L, N or S) the returned string will
contain at least one of the characters in the concerned character
set.
The Exclude parameter lets you exclude specific characters that might e.g.
lead to confusion like an alphanumeric O and a numeric 0 (zero).
Examples:
To create a password with a length of 8 characters that might contain any uppercase characters, lowercase characters and numbers:
Create-Password 8 uln
To create a password with a length of 12 characters that that contains at least one uppercase character, one lowercase character, one number and one symbol and does not contain the characters OLIoli01:
Create-Password 12 ULNS "OLIoli01"
For the latest New-Password version: use:
Install-Script -Name PowerSnippets.New-Password
Command to Generate Random passwords by using existing funciton:
[system.web.security.membership]::GeneratePassword(x,y)
x = Length of the password
y = Complexity
General Error:
Unable to find type [system.web.security.membership]. Make sure that the assembly that contains this type is loaded.
Solution:
Run the below command:
Add-Type -AssemblyName System.web;
Another solution:
function New-Password() {
param(
[int] $Length = 10,
[bool] $Upper = $true,
[bool] $Lower = $true,
[bool] $Numeric = $true,
[string] $Special
)
$upperChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
$lowerChars = "abcdefghijklmnopqrstuvwxyz"
$numericChars = "0123456789"
$all = ""
if ($Upper) { $all = "$all$upperChars" }
if ($Lower) { $all = "$all$lowerChars" }
if ($Numeric) { $all = "$all$numericChars" }
if ($Special -and ($special.Length -gt 0)) { $all = "$all$Special" }
$password = ""
for ($i = 0; $i -lt $Length; $i++) {
Write-Host "password: [$password]"
$password = $password + $all[$(Get-Random -Minimum 0 -Maximum $all.Length)]
}
$valid = $true
if ($Upper -and ($password.IndexOfAny($upperChars.ToCharArray()) -eq -1)) { $valid = $false }
if ($Lower -and ($password.IndexOfAny($lowerChars.ToCharArray()) -eq -1)) { $valid = $false }
if ($Numeric -and ($password.IndexOfAny($numericChars.ToCharArray()) -eq -1)) { $valid = $false }
if ($Special -and $Special.Length -gt 1 -and ($password.IndexOfAny($Special.ToCharArray()) -eq -1)) { $valid = $false }
if (-not $valid) {
$password = New-Password `
-Length $Length `
-Upper $Upper `
-Lower $Lower `
-Numeric $Numeric `
-Special $Special
}
return $password
}
Flexible enough to set length, turn on/of upper, lower, and numeric, and set the list of specials.
My take on generating passwords in PowerShell, based on what I've found here and in the Internets:
#Requires -Version 4.0
[CmdletBinding(PositionalBinding=$false)]
param (
[Parameter(
Mandatory = $false,
HelpMessage = "Minimum password length"
)]
[ValidateRange(1,[int]::MaxValue)]
[int]$MinimumLength = 24,
[Parameter(
Mandatory = $false,
HelpMessage = "Maximum password length"
)]
[ValidateRange(1,[int]::MaxValue)]
[int]$MaximumLength = 42,
[Parameter(
Mandatory = $false,
HelpMessage = "Characters which can be used in the password"
)]
[ValidateNotNullOrEmpty()]
[string]$Characters = '1234567890qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM##%*-_+:,.'
)
(1..(Get-Random -Minimum $MinimumLength -Maximum $MaximumLength) `
| %{ `
$Characters.GetEnumerator() | Get-Random `
}) -join ''
I preferred this over using System.Web, not to introduce dependencies, which could change with .Net / .Net Core versions.
My variation also allows random password length (in specified range), is fairly concise (apart from the parameters section, which is quite verbose, to enforce some validations and provide defaults) and allows character repetitions (as opposite to the code in the question, which never repeats the same character).
I understand, that this does not guarantee a digit in the password. This however can be addressed in different ways. E.g. as was suggested, to repeat the generation until the password matches the requirements (contains a digit). My take would be:
Generate a random password.
If it does not contain a digit (or always):
Use a random function to get 1 random digit.
Add it to the random password.
Randomize the order of the result (so the digit is not necessarily always at the end).
Assuming, that the above script would be named "Get-RandomPassword.ps1", it could look like this:
$pass = .\Get-RandomPassword.ps1
$pass += (0..9 | Get-Random)
$pass = (($pass.GetEnumerator() | Get-Random -Count $pass.Length) -join '')
Write-Output $pass
This can be generalized, to enforce using any character category:
$sets = #('abcdefghijklmnopqrstuvwxyz', 'ABCDEFGHIJKLMNOPQRSTUVWXYZ', '0123456789', '()-_=+[{]};:''",<.>/?`~')
$pass = .\Get-RandomPassword.ps1 -Characters ($sets -join '')
foreach ($set in $sets) {
$pass += ($set.GetEnumerator() | Get-Random)
}
$pass = (($pass.GetEnumerator() | Get-Random -Count $pass.Length) -join '')
Write-Output $pass
I wrote a secure password generator function in PowerShell, maybe this will be useful to someone.
Similar to the accepted answer, this script also uses Get-Random (twice), and also regular expression matching to ensure the output is secure.
The difference in this script is that the password length can also be randomised.
(To hard set a password length, just set the MinimumPasswordLength and MaximumPasswordLength values to the the same length.)
It also allows an easy to edit character set, and also has a regex to ensure a decent password has been generated with all of the following characteristics:
(?=.*\d) must contain at least one numerical character
(?=.*[a-z]) must contain at least one lowercase character
(?=.*[A-Z]) must contain at least one uppercase character
(?=.*\W) must contain at least one non-word character
The answer to your question about always including a number in your generated output can be solved by checking the output with a regex match (just use the parts of the regex that you need, based on the explanations above), the example here checks for uppercase, lowercase, and numerical:
$Regex = "(?=.*\d)(?=.*[a-z])(?=.*[A-Z])"
do {
$Password = ([string]($AllowedPasswordCharacters |
Get-Random -Count $PasswordLength) -replace ' ')
} until ($Password -cmatch $Regex)
$Password
Here is the full script:
Function GeneratePassword
{
cls
$MinimumPasswordLength = 12
$MaximumPasswordLength = 16
$PasswordLength = Get-Random -InputObject ($MinimumPasswordLength..$MaximumPasswordLength)
$AllowedPasswordCharacters = [char[]]'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!?##£$%^&'
$Regex = "(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*\W)"
do {
$Password = ([string]($AllowedPasswordCharacters |
Get-Random -Count $PasswordLength) -replace ' ')
} until ($Password -cmatch $Regex)
$Password
}
GeneratePassword
I had the same issue here is the snippet I used to create my alphanumerical password its simple all I have done is used ASCII regex replace to make it nice.
Function Password-Generator ([int]$Length)
{
# Generate passwords just call password-generator(lenght of password)
$Assembly = Add-Type -AssemblyName System.Web
$RandomComplexPassword = [System.Web.Security.Membership]::GeneratePassword($Length,2)
$AlphaNumericalPassword = $RandomComplexPassword -replace '[^\x30-\x39\x41-\x5A\x61-\x7A]+'
Write-Output $AlphaNumericalPassword
}
I've created this. You can choose how many Pwd to create
$howoften = Read-Host "How many would you like to create: "
$i = 0
do{
(-join(1..42 | ForEach {((65..90)+(97..122)+(".") | % {[char]$_})+(0..9)+(".") | Get-Random}))
$i++
} until ($i -match $howoften)
To change the length of the pwd simply edit the "42" in line 4
(-join(1..**42** | ForEach ...
I am new to Powershell, first time using it.
I have declared an array and use array value but using below code, I am not able to retrieve the array value...Any idea what I am missing here?
Just FYI.. I am executing script in ADOBE ILLUSTRATOR and for testing I am using 3 here in condition (for loop)... will use $array later
$array = "a.jpg","b.jpg","c.jpg";
for ($i=1; $i-le=3; $i++)
{
$.writeln("This is line number " + $array[$i]);
var targetFileName = $array[$i]+'.png';
$.writeln(targetFileName);
}
I tried $array[$i].toString() as well but still not getting values... I am getting 0
Any help is appreciated and thanks in advance to all for your help
for ($i=1; $i-le=3; $i++)
The condition in the above line doesn't have a valid comparison operator. Change that to
for ($i=1; $i -le 3; $i++)
if you want the loop to terminate after 3 cycles.
$.writeln("This is line number " + $array[$i]);
var targetFileName = $array[$i]+'.png';
$.writeln(targetFileName);
This is not valid PowerShell. Looks more like JavaScript to me. In PowerShell it should probably look like this:
Write-Output "This is line number $i"
$targetFileName = $array[$i] + '.png'
Write-Output $targetFileName
or shorter
"This is line number $i"
$array[$i] + '.png'
Note that PowerShell arrays are zero-based, so the last iteration ($array[3]) will return $null instead of an element from the array. If you want to iterate over the elements of the array you should change your loop to this:
for ($i=0; $i -lt $array.Length; $i++) {
"This is line number $($i+1)"
$array[$i] + '.png'
}
or (better) pipe your array into a foreach loop:
$i = 0
$array | % {
"This is line number " + ++$i
$_ + '.png'
}