I have this eror:
The '.' operator cannot be applied to operand of type 'method group'
(CS0023)
I know that there is a question like this, but I checked it and the problem with that was put System before the method.
I have this code
private int posCuriosidad = 0;
// Use this for initialization
void Start () {
Random();
}
public void Random(){
posCuriosidad = Random.Range(0,9);
}
but I don't know why I get the error.
That's because calling Random.X inside a method named Random will be mapped to try to invoke X on the method group of your method.
You clearly wanted to use the built-in Random type, not your own method.
Here's a couple of ways to do this:
Rename your method, "Random" is not a verb, "Randomize" is though but you should strive to make the purpose of the method clear through its name, so perhaps "RandomizePosition" would be better?
public void RandomizePosition()
{
posCuriosidad = Random.Range(0,9);
}
Explicitly refer to the built-in Random type:
UnityEngine.Random.Range(0,9);
Related
Im trying to load my model in my controller and tried this:
return Post::getAll();
got the error Non-static method Post::getAll() should not be called statically, assuming $this from incompatible context
The function in the model looks like this:
public function getAll()
{
return $posts = $this->all()->take(2)->get();
}
What's the correct way to load the model in a controller and then return it's contents?
You defined your method as non-static and you are trying to invoke it as static. That said...
1.if you want to invoke a static method, you should use the :: and define your method as static.
// Defining a static method in a Foo class.
public static function getAll() { /* code */ }
// Invoking that static method
Foo::getAll();
2.otherwise, if you want to invoke an instance method you should instance your class, use ->.
// Defining a non-static method in a Foo class.
public function getAll() { /* code */ }
// Invoking that non-static method.
$foo = new Foo();
$foo->getAll();
Note: In Laravel, almost all Eloquent methods return an instance of your model, allowing you to chain methods as shown below:
$foos = Foo::all()->take(10)->get();
In that code we are statically calling the all method via Facade. After that, all other methods are being called as instance methods.
Why not try adding Scope? Scope is a very good feature of Eloquent.
class User extends Eloquent {
public function scopePopular($query)
{
return $query->where('votes', '>', 100);
}
public function scopeWomen($query)
{
return $query->whereGender('W');
}
}
$users = User::popular()->women()->orderBy('created_at')->get();
Eloquent #scopes in Laravel Docs
TL;DR. You can get around this by expressing your queries as MyModel::query()->find(10); instead of MyModel::find(10);.
To the best of my knowledge, starting PhpStorm 2017.2 code inspection fails for methods such as MyModel::where(), MyModel::find(), etc (check this thread), and this could get quite annoying.
One (elegant) way to get around this is to explicitly call ::query() wherever it makes sense to. This will let you benefit from free auto-completion and a nice formatting/indentating for your queries.
Examples
BAD
Snippet where inspection complains about static method calls
// static call complaint
$myModel = MyModel::find(10);
// another poorly formatted query with code inspection complaints
$myFilteredModels = MyModel::where('is_foo', true)
->where('is_bar', false)
->get();
GOOD
Well formatted code with no complaints
// no complaint
$myModel = MyModel::query()->find(10);
// a nicely formatted and indented query with no complaints
$myFilteredModels = MyModel::query()
->where('is_foo', true)
->where('is_bar', false)
->get();
Just in case this helps someone, I was getting this error because I completely missed the stated fact that the scope prefix must not be used when calling a local scope. So if you defined a local scope in your model like this:
public function scopeRecentFirst($query)
{
return $query->orderBy('updated_at', 'desc');
}
You should call it like:
$CurrentUsers = \App\Models\Users::recentFirst()->get();
Note that the prefix scope is not present in the call.
Solution to the original question
You called a non-static method statically. To make a public function static in the model, would look like this:
public static function {
}
In General:
Post::get()
In this particular instance:
Post::take(2)->get()
One thing to be careful of, when defining relationships and scope, that I had an issue with that caused a 'non-static method should not be called statically' error is when they are named the same, for example:
public function category(){
return $this->belongsTo('App\Category');
}
public function scopeCategory(){
return $query->where('category', 1);
}
When I do the following, I get the non-static error:
Event::category()->get();
The issue, is that Laravel is using my relationship method called category, rather than my category scope (scopeCategory). This can be resolved by renaming the scope or the relationship. I chose to rename the relationship:
public function cat(){
return $this->belongsTo('App\Category', 'category_id');
}
Please observe that I defined the foreign key (category_id) because otherwise Laravel would have looked for cat_id instead, and it wouldn't have found it, as I had defined it as category_id in the database.
You can give like this
public static function getAll()
{
return $posts = $this->all()->take(2)->get();
}
And when you call statically inside your controller function also..
I've literally just arrived at the answer in my case.
I'm creating a system that has implemented a create method, so I was getting this actual error because I was accessing the overridden version not the one from Eloquent.
Hope that help?
Check if you do not have declared the method getAll() in the model. That causes the controller to think that you are calling a non-static method.
For use the syntax like return Post::getAll(); you should have a magic function __callStatic in your class where handle all static calls:
public static function __callStatic($method, $parameters)
{
return (new static)->$method(...$parameters);
}
I'm using a lambda expression in my C# script in my Unity project to call a function with a parameter when a DOTween callback is called.
It simply looks like this: animation.OnComplete(() => DestroyOnCompleted(children));
It works just fine, but I am note sure why a lambda expression is used in this case. I know it has something to do with delegates, but other than that, I'm not too sure; and I would like to explain it to my exam, if I get asked about it.
Could anyone enlighten me? :-)
Why not? ;)
I don't know that API too much but it seems like it is simply expecting something like
OnComplete(TweenCallback callback)
where TweenCallback from your usage basically seems to equal the c# built-in Action delegate and basically simply a parameter less void
public delegate void TweenCallback();
so whether you pass in this callback as a lambda like
animation.OnComplete(() => DestroyOnCompleted(children));
or anonymous method using the delegate operator like
animation.OnComplete(delegate { DestroyOnCompleted(children); });
or using a method
animation.OnComplete(OnCompletedAnimation);
...
private void OnCompletedAnimation()
{
DestroyOnCompleted(children);
}
is basically equivalent.
The main difference between the first two and the last one is: Where does children come from?
The lambda and delegate way allows you to pass in children from the current scope variables without having to store it in any field!
If you look at the documentation of DotTween, you see that row:
Now looking at the Source Code of DotTween, you can see the definition of TweenCallback:
public delegate void TweenCallback();
So the question now is, what is a delegate void in c#?
A delegate in c# is basically an object that "represent" a function.
But functions are not all the same, they can have parameters in input and return something (or return void).
To understand what kind of function does a delegate represent, try to just remove the keyword delegate.
For example, the TweenCallback without the keyboard delegate is:
public void TweenCaalback()
So the delegate represent a void function that has no parameters in input! (And it is Public).
What does it means represent a function?
It means that this is valid code:
void DoNothing()
{
}
TweenCallback x = DoNothing;
x();
So you can "assign functions" to a delegate that has the same function signature.
In this case, TweenCallback is a delegate void (), so you can assign to it a void() function.
What is a lambda?
A lambda is an expression of that style:
(string name, int age) => { return 3 };
you can read that as "string name and int age go in return 3"
That's a more concise way to describe that function:
int AnonymousFunction (string name, int age) {}
The main difference is that lambdas do not have any name. If you have not any parameter in input the lambda become like this:
() => {return 3;}
If you have only one statement inside the {} you are allowed to write it more shortly as
() => 3;
Final step
Is this valid code?
void DoNothing()
{
}
TweenCallback x = () => DoNothing();
Yes it is! Tween callback is expects a void () function.
() => DoNothing(); Is a lambda (un-named function) that takes nothing in input and calls some other function. It's the shorter version of () => {DoNothing();} that you have to think as void () {DoNothing();}
So when writing
animation.OnComplete(() => DestroyOnCompleted(children));
You are just passing a void () function to OnComplete Method, that makes sense because TweenCallback is a void () delegate.
Notes
As you can see, functions and lambdas expression can be converted implicitly to delegates. But you have to understand that they are all different things, and in more advanced coding scenarios that distinction is not just pure theory.
I created an extension method that lets me treat a List as DbSet for testing purposes (actually, I found this idea in another question here on stack overflow, and it's been fairly useful). Coded as follows:
public static DbSet<T> AsDbSet<T>(this List<T> sourceList) where T : class
{
var queryable = sourceList.AsQueryable();
var mockDbSet = new Mock<DbSet<T>>();
mockDbSet.As<IQueryable<T>>().Setup(m => m.Provider).Returns(queryable.Provider);
mockDbSet.As<IQueryable<T>>().Setup(m => m.Expression).Returns(queryable.Expression);
mockDbSet.As<IQueryable<T>>().Setup(m => m.ElementType).Returns(queryable.ElementType);
mockDbSet.As<IQueryable<T>>().Setup(m => m.GetEnumerator()).Returns(queryable.GetEnumerator());
mockDbSet.Setup(d => d.Add(It.IsAny<T>())).Callback<T>(sourceList.Add);
mockDbSet.Setup(d => d.Find(It.IsAny<object[]>())).Callback(sourceList.Find);
return mockDbSet.Object;
}
I had been using Add for awhile, and that works perfectly. However, when I try to add the callback for Find, I get a compiler error saying that it can't convert a method group to an action. Why is sourceList.Add an Action, but sourceList.Find is a method group?
I'll admit I'm not particularly familiar with C# delegates, so it's likely I'm missing something very obvious. Thanks in advance.
The reason Add works is because the List<T>.Add method group contains a single method which takes a single argument of type T and returns void. This method has the same signature as an Action<T> which is one of the overloads of the Callback method (the one with a single generic type parameter, Callback<T>), therefore the List<T>.Add method group can be converted to an Action<T>.
With Find, you are trying to call the Callback method (as opposed to Callback<T>) which expects an Action parameter (as opposed to Action<T>). The difference here is that an Action does not take any parameters, but an Action<T> takes a single parameter of type T. The List<T>.Find method group cannot be converted to an Action because all the Find methods (there is only one anyway) take input parameters.
The following will compile:
public static DbSet<T> AsDbSet<T>(this List<T> sourceList) where T : class
{
var mockDbSet = new Mock<DbSet<T>>();
mockDbSet.Setup(d => d.Find(It.IsAny<object[]>())).Callback<Predicate<T>>(t => sourceList.Find(t));
return mockDbSet.Object;
}
Note that I have called .Callback<Predicate<T>> because the List<T>.Find method expects and argument of type Predicate. Also note I have had to write t => sourceList.Find(t) instead of sourceList.Find because Find returns a value (which means it doesn't match the signature of Action<Predicate<T>>). By writing it as a lambda expression the return value will be thrown away.
Note that although this compiles it will not actually work because the DbSet.Find method actually takes an object[] for it's parameter, not a Predicate<T>, so you will likely have to do something like this:
public static DbSet<T> AsDbSet<T>(this List<T> sourceList) where T : class
{
var mockDbSet = new Mock<DbSet<T>>();
mockDbSet.Setup(d => d.Find(It.IsAny<object[]>())).Callback<object[]>(keyValues => sourceList.Find(keyValues.Contains));
return mockDbSet.Object;
}
This last point has more to do with how to use the Moq library that how to use method groups, delegates and lambdas - there is all sorts of syntactic sugar going on with this line which is hiding what is actually relevant to the compiler and what isn't.
I have class with void method and optional argument looking like this:
class A
{
public:
void method(int par1, bool par2 = false) { ... }
};
BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS(method, A::method, 1, 2)
class_<A>("A")
.def("method", &A::method, return_value_policy<reference_existing_object>(),method())
;
What is correct return_value_policy in this case? I've tried to avoid return policy completely however I've received following compile error then.
'boost::mpl::vector17<RT,most_derived<Target,ClassT>::type&,T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14> boost::python::detail::get_signature(RT (__cdecl ClassT::* )(T0,T1,T2,T3,T4,T5,T6,T7,T8,T9,T10,T11,T12,T13,T14) volatile const,Target *)' : expects 2 arguments - 1 provided
Any suggestion appreciated.
I've scrambled few things together. Bur I realized I do not need to use BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS but rather named arguments something like:
def("method", &A::method, (arg("par1"), arg("par2") = false))
Is it possible to overload operator = in c#?
when i call =, i just want to copy properties, rather than making the left hand reference to refer another instance.
The answer is no:
Note that the assignment operator itself (=) cannot be overloaded. An assignment always performs a simple bit-wise copy of a value into a variable.
And even if it was possible, I wouldn't recommend it. Nobody who reads the code is going to think that there's ANY possibility that the assignment operator's been overloaded. A method to copy the object will be much clearer.
You can't overload the = operator. Furthermore, what you are trying to do would entirely change the operator's semantics, so in other words is a bad idea.
If you want to provide copy semantics, provide a Clone() method.
Why not make a .CopyProperties(ByVal yourObject As YourObject) method in the object?
Are you using a built-in object?
We can Overload = operator but not directly.
using System;
class Over
{
private int a;
public Over(int a )
{
this.a = a;
}
public int A { get => a; }
public static implicit operator int(Over obj)
{
return obj.A;
}
}
class yo
{
public static void Main()
{
Over over = new Over(10);
int a = over;
}
}
Here when you call that operator overloading method , it is calling = operator itself to convert that to int. You cannot directly overload "=" but this way of code means the same.