Im trying to load my model in my controller and tried this:
return Post::getAll();
got the error Non-static method Post::getAll() should not be called statically, assuming $this from incompatible context
The function in the model looks like this:
public function getAll()
{
return $posts = $this->all()->take(2)->get();
}
What's the correct way to load the model in a controller and then return it's contents?
You defined your method as non-static and you are trying to invoke it as static. That said...
1.if you want to invoke a static method, you should use the :: and define your method as static.
// Defining a static method in a Foo class.
public static function getAll() { /* code */ }
// Invoking that static method
Foo::getAll();
2.otherwise, if you want to invoke an instance method you should instance your class, use ->.
// Defining a non-static method in a Foo class.
public function getAll() { /* code */ }
// Invoking that non-static method.
$foo = new Foo();
$foo->getAll();
Note: In Laravel, almost all Eloquent methods return an instance of your model, allowing you to chain methods as shown below:
$foos = Foo::all()->take(10)->get();
In that code we are statically calling the all method via Facade. After that, all other methods are being called as instance methods.
Why not try adding Scope? Scope is a very good feature of Eloquent.
class User extends Eloquent {
public function scopePopular($query)
{
return $query->where('votes', '>', 100);
}
public function scopeWomen($query)
{
return $query->whereGender('W');
}
}
$users = User::popular()->women()->orderBy('created_at')->get();
Eloquent #scopes in Laravel Docs
TL;DR. You can get around this by expressing your queries as MyModel::query()->find(10); instead of MyModel::find(10);.
To the best of my knowledge, starting PhpStorm 2017.2 code inspection fails for methods such as MyModel::where(), MyModel::find(), etc (check this thread), and this could get quite annoying.
One (elegant) way to get around this is to explicitly call ::query() wherever it makes sense to. This will let you benefit from free auto-completion and a nice formatting/indentating for your queries.
Examples
BAD
Snippet where inspection complains about static method calls
// static call complaint
$myModel = MyModel::find(10);
// another poorly formatted query with code inspection complaints
$myFilteredModels = MyModel::where('is_foo', true)
->where('is_bar', false)
->get();
GOOD
Well formatted code with no complaints
// no complaint
$myModel = MyModel::query()->find(10);
// a nicely formatted and indented query with no complaints
$myFilteredModels = MyModel::query()
->where('is_foo', true)
->where('is_bar', false)
->get();
Just in case this helps someone, I was getting this error because I completely missed the stated fact that the scope prefix must not be used when calling a local scope. So if you defined a local scope in your model like this:
public function scopeRecentFirst($query)
{
return $query->orderBy('updated_at', 'desc');
}
You should call it like:
$CurrentUsers = \App\Models\Users::recentFirst()->get();
Note that the prefix scope is not present in the call.
Solution to the original question
You called a non-static method statically. To make a public function static in the model, would look like this:
public static function {
}
In General:
Post::get()
In this particular instance:
Post::take(2)->get()
One thing to be careful of, when defining relationships and scope, that I had an issue with that caused a 'non-static method should not be called statically' error is when they are named the same, for example:
public function category(){
return $this->belongsTo('App\Category');
}
public function scopeCategory(){
return $query->where('category', 1);
}
When I do the following, I get the non-static error:
Event::category()->get();
The issue, is that Laravel is using my relationship method called category, rather than my category scope (scopeCategory). This can be resolved by renaming the scope or the relationship. I chose to rename the relationship:
public function cat(){
return $this->belongsTo('App\Category', 'category_id');
}
Please observe that I defined the foreign key (category_id) because otherwise Laravel would have looked for cat_id instead, and it wouldn't have found it, as I had defined it as category_id in the database.
You can give like this
public static function getAll()
{
return $posts = $this->all()->take(2)->get();
}
And when you call statically inside your controller function also..
I've literally just arrived at the answer in my case.
I'm creating a system that has implemented a create method, so I was getting this actual error because I was accessing the overridden version not the one from Eloquent.
Hope that help?
Check if you do not have declared the method getAll() in the model. That causes the controller to think that you are calling a non-static method.
For use the syntax like return Post::getAll(); you should have a magic function __callStatic in your class where handle all static calls:
public static function __callStatic($method, $parameters)
{
return (new static)->$method(...$parameters);
}
Related
This is my controller.php:
$courserecord = $this->front->get_data_wheree('tbl_course_offered.course_id',array('isactive'=>'1'));
This is my Model.php:
function get_data_wheree($table,$where)
{
return $this->db->group_by($table,$where)->result();
}
In my model.php I want to use DISTINCT OR GROUP_BY in the Query.
The group_by is not working properly.
Your model is not working because the result() method is a member of the class CI_DB_result but group_by() returns an instance of CI_DB_query_builder. In other words, you are trying to call a method that does not exist for the class being used.
The methods get() and get_where() are the only two Query Builder methods that return a CI_DB_result object. Put simply, you have to call get() or get_where() before you can use result() or any similar methods.
The other problem is that group_by() does not take a second argument of the type you provide. You're providing an array but it expects a boolean. You need to add another method to define a where condition.
Your model's method should look like the following.
I changed the name of the first argument to better describe its purpose.
function get_data_where($groupby, $where)
{
return $this->db
->group_by($groupby)
->where($where)
->get('tbl_course_offered')
->result();
}
I'm currently testing some simple AngelScript stuff, and noticed something I find a bit strange when it comes to how objects are initialized from classes.
Let's say I define a class like this:
class MyClass {
int i;
MyClass(int i) {
this.i = i;
}
}
I can create an object of this class by doing this:
MyClass obj = MyClass(5);
However it seems I can also create an object by doing this:
MyClass obj;
The problem here is that obj.i becomes a default value as it is undefined.
Additionally, adding a default constructor to my class and a print function call in each one reveals that when I do MyClass obj = MyClass(5); BOTH constructors are called, not just the one with the matching parameter. This seems risky to me, as it could initialize a lot of properties unnecessarily for this "ghost" instance.
I can avoid this double-initialization by using a handle, but this seems more like a work-around rather than a solution:
MyClass# obj = MyClass(5);
So my question sums up to:
Can I require a specific constructor to be called?
Can I prevent a default constructor from running?
What's the proper way to deal with required parameters when creating objects?
Mind that this is purely in the AngelScript script language, completely separate from the C++ code of the host application. The host is from 2010 and is not open-source, and my knowledge of their implementation is very limited, so if the issue lies there, I can't change it.
In order to declare class and send the value you choose to constructor try:
MyClass obj(5);
To prevent using default constructor create it and use:
.
MyClass()
{
abort("Trying to create uninitialized object of type that require init parameters");
}
or
{
exit(1);
}
or
{
assert(1>2,"Trying to create uninitialized object of type that require init parameters");
}
or
{
engine.Exit();
}
in case that any of those is working in you environment.
declaring the constructor as private seems not to work in AS, unlike other languages.
I have to put some status data into the context object. This has to be done in lot of places so I thought it would be nice to solve this with AOP.
The problem is that I don't know how to access the callers parameter and the return value of the called method in the same advice. Is this possible at all?
public BusinessObject methodA(Context ctx, Param p) {
Status s = service.serviceMethod(p);
if (s.hasErrors())
{
ctx.put("error_key", s.getErrors());
}
...
}
I am using FluentMongo and the MongoDBCSharpDriver. My code was working fine for a while, but after updating my MongoCSharpDriver, I now I keep getting this error when I try to query the database:
"Discriminators can only be registered for classes, not for interface MyLib.Services.IRepoData."
The interface IRepoData is just one that I use for all my objects saved to MongoDB. It just defines _id for everything. Here is the line that is breaking:
var item = Collection.AsQueryable().SingleOrDefault(a => a.Id == itemID);
Can anyone shed some light on this one? If I just use .SingleOrDefault() with no lambda then it works fine, its passing a lambda that breaks it.
EDIT
In case this helps...
var Collection = GetCollection<MyClass>();
private MongoCollection<T> GetCollection<T>() where T : class, new()
{
string typeName = typeof(T).Name;
var collection = db.GetCollection<T>(typeName, safeMode);
return collection;
}
Found it! I was calling GetCollection() from within another generic method, like this:
public T Save<T>(T item) where T : class, IRepoData, new()
{
GetCollection<T>().Save(item);
}
This caused GetCollection to see T as the interface instead of the actual instance class. GetCollection works fine anywhere else.
For anyone else with this problem, I just used a low level query like this instead... Collection.FindOneAs<T>(Query.EQ("Id", itemID.ToString()));
I could use some really good links that explain Generics and how to use them. But I also have a very specific question, relater to working on a current project.
Given this class constructor:
public class SecuredDomainViewModel<TDomainContext, TEntity> : DomainViewModel<TDomainContext, TEntity>
where TDomainContext : DomainContext, new()
where TEntity : Entity, new()
public SecuredDomainViewModel(TDomainContext domainContext, ProtectedItem protectedItem)
: base(domainContext)
{
this.protectedItem = protectedItem;
}
And its creation this way:
DomainViewModel d;
d = new SecuredDomainViewModel<MyContext, MyEntityType>(this.context, selectedProtectedItem);
Assuming I have 20 different EntityTypes within MyContext, is there any easier way to call the constructor without a large switch statement?
Also, since d is DomainViewModel and I later need to access methods from SecuredDomainViewModel, it seems I need to do this:
if (((SecuredDomainViewModel<MyContext, MyEntityType>)d).CanEditEntity)
But again "MyEntityType" could actually be one of 20 diffent types. Is there anyway to write these types of statements where MyEntityType is returned from some sort of Reflection?
Additional Info for Clarification:
I will investigate ConstructorInfo, but I think I may have incorrectly described what I'm looking to do.
Assume I have the DomainViewModel, d in my original posting.
This may have been constructed via three possible ways:
d = new SecuredDomainViewModel<MyContext, Order>(this.context, selectedProtectedItem);
d = new SecuredDomainViewModel<MyContext, Invoice>(this.context, selectedProtectedItem);
d = new SecuredDomainViewModel<MyContext, Consumer>(this.context, selectedProtectedItem);
Later, I need to access methods on the SecuredDomainViewModel, which currently must be called this way:
ex: if (((SecuredDomainViewModel<MyContext, Order)d).CanEditEntity)
ex: if (((SecuredDomainViewModel<MyContext, Invoice)d).CanEditEntity)
ex: if (((SecuredDomainViewModel<MyContext, Consumer)d).CanEditEntity)
Assuming I have N+ entity types in this context, what I was hoping to be able to do is
something like this with one call:
ex: if (((SecuredDomainViewModel<MyContext, CurrentEntityType)d).CanEditEntity)
Where CurrentEntityType was some sort of function or other type of call that returned Order, Invoice or Consumer based on the current item entity type.
Is that possible?
You can create a non-generic interface that has the CanEditEntity property on it, make SecuredDomainViewModel inherit off that, then call the property through the interface...
Also, the new() constructor allows you to call a constructor on a generic type that has no arguments (so you can just write new TEntity()), but if you want to call a constructor that has parameters one handy trick I use is to pass it in as a delegate:
public void Method<T>(Func<string, bool, T> ctor) {
// ...
T newobj = ctor("foo", true);
// ...
}
//called later...
Method((s, b) => new MyClass(s, b));
I can't help on the links, and likely not on the type either.
Constructor
If you have the Type, you can get the constructor:
ConstructorInfo construtor = typeof(MyEntityType).GetConstructor(new object[]{TDomainContext, ProtectedItem});
Type
I'm not really sure what you're looking for, but I can only see something like
if (((SecuredDomainViewModel<MyContext, entityType>)d).CanEditEntity)
{
entityType=typeof(Orders)
}
being what you want.