Sed's regex to eliminate a very specific string - sed

Question

Disclaimer:
I have found several examples in this site that address questions/problems similar to mine, though I was unfortunately not able to figure out the modifications that would need to be introduced to fit my needs.
The "Problem":
I have a list of servers (VMs) that have it's UUID embedded as part of the name. I need to get rid of that in order to obtain the "pure/clean" server name. Now, the problem is precisely that: I need to get rid of the UUID (which has a very specific and constant format, more details on this below) and ONLY that, nothing else.
The UUID - as you might already know or have noticed - has a specific and constant format which consists of the following parts:
It starts with a dash (-).
Which is followed by a subset of 8 alphanumeric characters (letters are always lowercase).
Which is followed by a dash (-).
Which is followed by a subset of 4 alphanumeric characters (letters are always lowercase).
Which is followed by a dash (-).
Which is followed by a subset of 4 alphanumeric characters (letters are always lowercase).
Which is followed by a dash (-).
Which is followed by a subset of 4 alphanumeric characters (letters are always lowercase).
Which is followed by a dash (-).
Which is followed by a subset of 12 alphanumeric characters (letters are always lowercase).
Samples of results achieved using "my" """"code"""":
In this case the result is the expected one:
echo PRODSERVER0022-872151c8-1a75-43fb-9b63-e77652931d3f | sed 's/-[a-z0-9]*//g'
PRODSERVER0022
In this case the result is the expected one too:
echo PRODSERVER0022-872151c8-1a75-43fb-9b63-e77652931d3f_OLD | sed 's/-[a-z0-9]*//g'
PRODSERVER0022_OLD
Expected result: PRODSERVER0022-OLD
echo PRODSERVER0022-872151c8-1a75-43fb-9b63-e77652931d3f-OLD | sed 's/-[a-z0-9]*//g'
PRODSERVER0022
Expected result: PRODSERVER00-22
echo PRODSERVER00-22-872151c8-1a75-43fb-9b63-e77652931d3f-old | sed 's/-[a-z0-9]*//g'
PRODSERVER00
I know that, within the sed universe, a . means "any character", while a * means "any number of the preceding character". However, what I would need in this case, as I see it at least, is a way to tell sed to do the replacement only if this specific sequence is present (8 alphanumeric characters [any, but specifically 8, not more, not less]; followed by a dash, then followed by 4 alphanumeric characters [any, but specifically 4, not more, not less], etc..). So, the question would be: Is there a regex construction (or a combination [through piping I guess] of several of them, if it has to be the case) that can achieve the expected results in this case?
Note that: Even though servers may have additional dashes (-) as part of their names, the resulting sub-strings will never consist of 8 characters, neither of 4. They might, however, end up having 12 characters, which, even though would initially match up with the last sub-string in the UUID, it will not be at the end of the string, so we have that to discriminate between these two 12-chars substrings (and also it will not be a problem if there is indeed a regex combination that can get rid of the UUID as a whole).

Answer 1

Try this to match the UUID.
-[a-f0-9]{8}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{12}
Embed it in the sed command line in the usual way. As Benjamin W. has said, we need to use extended regular expressiongs.
sed -E 's/-[a-f0-9]{8}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{12}//g'