Select single object from an Object Group - powershell

Question

How do I fix this:
There are 2 objects in this group,
one contains a name under 'Move-In (Name)', one doesn't:
$rest.Group | select * | Where-Object {$_.SERV_UNIT -eq '2704'}
Account_no : 12345
SERV_UNIT : 2704
FINALREAD :
Move-In (Name) : OWNER / CURRENT TENANT
Move-In (Home Phone #) :
Move-In (Business Phone #) :
Move-In (Email) :
Account_no : 12345
SERV_UNIT : 2704
FINALREAD :
CHANNEL_ID :
Move-In (Name) :
Move-In (Home Phone #) :
Move-In (Business Phone #) :
Move-In (Email) :
I want to select only the one with a move in name.
However, with the code I've written, because they're apart of the same group, I will not pick up either:
$rest = $allinfo | Group-Object account_no | Where-Object { $_.Group.FINALREAD -contains '' -and $_.Group.'Move-In (Name)' -notcontains ''} | Select * -Unique
$rest now equals nothing. I want it to have one result, the first one with 'Owner' as the Move-in name.
To get the correct result I have to do this:
$rest = $allinfo | Group-Object account_no | Where-Object { $_.Group.FINALREAD -contains ''} | Select * -Unique
$newRest = #()
foreach ($row in $rest.group) {
if ($row.'Move-In (Name)' -notcontains '')
{
$newRest += $row
}
}
Is it possible to do that all within this one line?
$rest = $allinfo | Group-Object account_no | Where-Object { $_.Group.FINALREAD -contains '' -and $_.Group.'Move-In (Name)' -notcontains ''} | Select * -Unique
If not, it's alright, I have an answer.
Thanks for help

Answer 1

Maybe you can remove the records you don't need (empty Move-In) first, then group by account and list the account-groups that contains one or more blank FINALREAD-values
$rest = $allinfo | Where-Object { $_.Group.'Move-In (Name)' } | Group-Object account_no | Where-Object { $_.Group.FINALREAD -contains '' }