Her is the class I use automatically capitalize true, false, ...
export class StUpdater {
private _lines: number;
private _strings: Array<string>;
constructor() {
this._lines = 0;
this._strings = ['true', 'false', 'exit', 'continue', 'return'];
}
Update(Cntx: boolean = false) {
let editor = window.activeTextEditor;
if (!editor || (editor.document.languageId != 'st')) {
window.showErrorMessage('No editor!')
return;
}
let doc = editor.document;
if (Cntx == false) {
if (this._lines >= doc.lineCount) {
this._lines = doc.lineCount;
return;
}
this._lines = doc.lineCount;
let AutoFormat = workspace.getConfiguration('st').get('autoFormat');
if (!AutoFormat) {
return;
}
}
let edit = new WorkspaceEdit();
for (let line = 0; line < doc.lineCount; line++) {
const element = doc.lineAt(line);
for (let i = 0; i < this._strings.length; i++) {
let str = this._strings[i];
let last_char = 0;
while (element.text.indexOf(str, last_char) >= 0) {
let char = element.text.indexOf(str, last_char);
last_char = char + str.length;
edit.replace(
doc.uri,
new Range(
new Position(line, char),
new Position(line, last_char)
),
str.toUpperCase()
);
}
}
}
return workspace.applyEdit(edit);
}
public dispose() {
}
}
This code works fine, but I do not want to replace it inside the string or comment. How do I do that? I cannot find preg version of replace and even if I do, in one line I do not know if it is comment or not if it is multiple line comment.
If I understand you correctly you want capitalize only certain elements (identifiers probably), but not words in comments or strings, correct? That requires to identify lexical elements in the text, which is a mapping of a range of letters to a lexical type. This is usually done by a lexer. It's not difficult to write one by hand which walks over the characters on top of your current processing and find those ranges that can be manipulated.
Related
In lit/lit-html/lit-element, a standard component is the TemplateResult (usually HTMLTemplateResult), created like:
function renderMe(msg) {
return html`<div>Hello ${msg}!</div>`;
}
and of course the power and efficiency of the library is that subsequent calls will reuse the same <div> Element and only replace the changed fragments.
For testing the renderMe() function above, however, it would be helpful to be able to see the return value as a standard string, like:
assert.equal(RENDER_AS_STRING(renderMe('kimiko')), '<div>Hello kimiko!</div>');
and fix any bugs in the function before testing how it renders into the browser itself.
Is there a function like RENDER_AS_STRING either in lit itself or in a testing library? I have searched and not found one.
The result of execution contains html strings and values that alternate:
We can combine them in the same order:
function renderMe(msg) {
return html`<div>Hello ${msg}!</div>`;
}
const getRenderString = (data) => {
const {strings, values} = data;
const v = [...values, ''] // + last emtpty part
return strings.reduce((acc,s, i) => acc + s + v[i], '')
}
console.log(getRenderString(renderMe('SO')))
You can test it in the playground
And the recursive version
import {html, css, LitElement} from 'lit';
function renderMe(msg) {
return html`<p>Hello ${msg}!</p>`;
}
function renderBlock(msg) {
return html`<div>${renderMe(msg)}</div>`;
}
const getRenderString = (data) => {
const {strings, values} = data;
const v = [...values, ''].map(e => typeof e === 'object' ? getRenderString(e) : e )
return strings.reduce((acc,s, i) => acc + s + v[i], '')
}
document.getElementById('output').textContent = getRenderString(renderBlock('SO'))
#Daniil Loban's answer works great if the arguments are strings, but if they might themselves be TemplateResults or arrays of TemplateResults (which are all allowed by spec), it needs a more complex answer:
export function template_as_string(data) {
const {strings, values} = data;
const value_list = [...values, '']; // + last empty part
let output = '';
for (let i = 0; i < strings.length; i++) {
let v = value_list[i];
if (v._$litType$ !== undefined) {
v = template_as_string(v); // embedded Template
} else if (v instanceof Array) {
// array of strings or templates.
let new_v = '';
for (const inner_v of [...v]) {
new_v += template_as_string(inner_v);
}
v = new_v;
}
output += strings[i] + v;
}
return output;
}
I want to replace n occurrence of a substring in a string.
myString = "I have a mobile. I have a cat.";
How I can replace the second have of myString
hope this simple function helps. You can also extract the function contents if you don't wish a function. It's just two lines with some
Dart magic
void main() {
String myString = 'I have a mobile. I have a cat.';
String searchFor='have';
int replaceOn = 2;
String replaceText = 'newhave';
String result = customReplace(myString,searchFor,replaceOn,replaceText);
print(result);
}
String customReplace(String text,String searchText, int replaceOn, String replaceText){
Match result = searchText.allMatches(text).elementAt(replaceOn - 1);
return text.replaceRange(result.start,result.end,replaceText);
}
Something like that should work:
String replaceNthOccurrence(String input, int n, String from, String to) {
var index = -1;
while (--n >= 0) {
index = input.indexOf(from, ++index);
if (index == -1) {
break;
}
}
if (index != -1) {
var result = input.replaceFirst(from, to, index);
return result;
}
return input;
}
void main() {
var myString = "I have a mobile. I have a cat.";
var replacedString = replaceNthOccurrence(myString, 2, "have", "had");
print(replacedString); // prints "I have a mobile. I had a cat."
}
This would be a better solution to undertake as it check the fallbacks also. Let me list down all the scenarios:
If position is 0 then it will replace all occurrence.
If position is correct then it will replace at same location.
If position is wrong then it will send back input string.
If substring does not exist in input then it will send back input string.
void main() {
String input = "I have a mobile. I have a cat.";
print(replacenth(input, 'have', 'need', 1));
}
/// Computes the nth string replace.
String replacenth(String input, String substr, String replstr,int position) {
if(input.contains(substr))
{
var splittedStr = input.split(substr);
if(splittedStr.length == 0)
return input;
String finalStr = "";
for(int i = 0; i < splittedStr.length; i++)
{
finalStr += splittedStr[i];
if(i == (position - 1))
finalStr += replstr;
else if(i < (splittedStr.length - 1))
finalStr += substr;
}
return finalStr;
}
return input;
}
let's try with this
void main() {
var myString = "I have a mobile. I have a cat.I have a cat";
print(replaceInNthOccurrence(myString, "have", "test", 1));
}
String replaceInNthOccurrence(
String stringToChange, String searchingWord, String replacingWord, int n) {
if(n==1){
return stringToChange.replaceFirst(searchingWord, replacingWord);
}
final String separator = "#######";
String splittingString =
stringToChange.replaceAll(searchingWord, separator + searchingWord);
var splitArray = splittingString.split(separator);
print(splitArray);
String result = "";
for (int i = 0; i < splitArray.length; i++) {
if (i % n == 0) {
splitArray[i] = splitArray[i].replaceAll(searchingWord, replacingWord);
}
result += splitArray[i];
}
return result;
}
here the regex
void main() {
var myString = "I have a mobile. I have a cat. I have a cat. I have a cat.";
final newString =
myString.replaceAllMapped(new RegExp(r'^(.*?(have.*?){3})have'), (match) {
return '${match.group(1)}';
});
print(newString.replaceAll(" "," had "));
}
Demo link
Here it is one more variant which allows to replace any occurrence in subject string.
void main() {
const subject = 'I have a dog. I have a cat. I have a bird.';
final result = replaceStringByOccurrence(subject, 'have', '*have no*', 0);
print(result);
}
/// Looks for `occurrence` of `search` in `subject` and replace it with `replace`.
///
/// The occurrence index is started from 0.
String replaceStringByOccurrence(
String subject, String search, String replace, int occurence) {
if (occurence.isNegative) {
throw ArgumentError.value(occurence, 'occurrence', 'Cannot be negative');
}
final regex = RegExp(r'have');
final matches = regex.allMatches(subject);
if (occurence >= matches.length) {
throw IndexError(occurence, matches, 'occurrence',
'Cannot be more than count of matches');
}
int index = -1;
return subject.replaceAllMapped(regex, (match) {
index += 1;
return index == occurence ? replace : match.group(0)!;
});
}
Tested on dartpad.
I have a string like <p>[var # example] <h1>Title</h1>[visual compose]</p>I want to filter out all the substrings which are inside square brackets, including the square brackets.
Do you mean you want to remove them?
You can do it with RegExp, but I would use a parser when html is involved.
One solution is this:
https://dartpad.dartlang.org/a92f2181191e23ee587d57fb55246c1f
String filterShortcodes(String input,
{String opening = '[', String closing = ']'}) {
assert(opening.runes.length == 1);
assert(closing.runes.length == 1);
final openingRune = opening.runes.first;
final closingRune = closing.runes.first;
bool filter = false;
final buf = StringBuffer();
for (final rune in input.runes) {
if (filter == false && rune == openingRune) {
filter = true;
} else if (filter == true && rune == closingRune) {
filter = false;
} else if (!filter) {
buf.write(String.fromCharCode(rune));
}
}
return buf.toString();
}
void main() {
var input = '<p>[var # example] <h1>Title</h1>[visual compose]</p>';
print(filterShortcodes(input)); // <p> <h1>Title</h1></p>
}
String removeTextBetweenSquareBrackets(String input) {
return input.replaceAll(new RegExp(r'\[.*?\]'), "");
}
void main() {
print(removeTextBetweenSquareBrackets('<p>[var # example] <h1>Title</h1>[visual compose]</p>'));
}
I want to highlight several keywords in a set of PDF files. Firstly, we have to identify the single words and match them with my keywords. I found an example:
class MyLocationTextExtractionStrategy : LocationTextExtractionStrategy
{
//Hold each coordinate
public List<RectAndText> myPoints = new List<RectAndText>();
List<string> topicTerms;
public MyLocationTextExtractionStrategy(List<string> topicTerms)
{
this.topicTerms = topicTerms;
}
//Automatically called for each chunk of text in the PDF
public override void RenderText(TextRenderInfo renderInfo)
{
base.RenderText(renderInfo);
//Get the bounding box for the chunk of text
var bottomLeft = renderInfo.GetDescentLine().GetStartPoint();
var topRight = renderInfo.GetAscentLine().GetEndPoint();
//Create a rectangle from it
var rect = new iTextSharp.text.Rectangle(
bottomLeft[Vector.I1],
bottomLeft[Vector.I2],
topRight[Vector.I1],
topRight[Vector.I2]
);
//Add this to our main collection
//filter the meaingless words
string text = renderInfo.GetText();
this.myPoints.Add(new RectAndText(rect, renderInfo.GetText()));
However, I found so many words are broken. For example, "stop" will be "st" and "op". Are there any other method to identify a single word and its position?
When you want to collect single words and their coordination, the better way is to override the existing LocationTextExtractionStrategy. Here is my code:
public virtual String GetResultantText(ITextChunkFilter chunkFilter){
if (DUMP_STATE) {
DumpState();
}
List<TextChunk> filteredTextChunks = filterTextChunks(locationalResult, chunkFilter);
filteredTextChunks.Sort();
List<RectAndText> tmpList = new List<RectAndText>();
StringBuilder sb = new StringBuilder();
TextChunk lastChunk = null;
foreach (TextChunk chunk in filteredTextChunks) {
if (lastChunk == null){
sb.Append(chunk.Text);
var startLocation = chunk.StartLocation;
var endLocation = chunk.EndLocation;
var rect = new iTextSharp.text.Rectangle(startLocation[0], startLocation[1], endLocation[0], endLocation[1]);
tmpList.Add(new RectAndText(rect, chunk.Text));
} else {
if (chunk.SameLine(lastChunk)){
// we only insert a blank space if the trailing character of the previous string wasn't a space, and the leading character of the current string isn't a space
if (IsChunkAtWordBoundary(chunk, lastChunk) && !StartsWithSpace(chunk.Text) && !EndsWithSpace(lastChunk.Text))
{
sb.Append(' ');
if (tmpList.Count > 0)
{
mergeAndStoreChunk(tmpList);
tmpList.Clear();
}
}
sb.Append(chunk.Text);
var startLocation = chunk.StartLocation;
var endLocation = chunk.EndLocation;
var rect = new iTextSharp.text.Rectangle(startLocation[0], startLocation[1], endLocation[0], endLocation[1]);
////var topRight = renderInfo.GetAscentLine().GetEndPoint();
tmpList.Add(new RectAndText(rect,chunk.Text));
} else {
sb.Append('\n');
sb.Append(chunk.Text);
}
}
lastChunk = chunk;
}
return sb.ToString();
}
private void mergeAndStoreChunk(List<RectAndText> tmpList)
{
RectAndText mergedChunk = tmpList[0];
int tmpListCount = tmpList.Count();
for (int i = 1; i < tmpListCount; i++)
{
RectAndText nowChunk = tmpList[i];
mergedChunk.Rect.Right = nowChunk.Rect.Right;
mergedChunk.Text += nowChunk.Text;
}
this.myPoints.Add(mergedChunk);
}
myPoints is a list, which will return all we want.
I am having an issue with a script. I used the following script from Google Developers Website in order to do a simple merge mail. See https://developers.google.com/apps-script/articles/mail_merge
I modified a bit the script so to prevent email duplicates. However, even if the script seems to work as it marks 'EMAIL_SENT' in each row every time an email is sent. It does not pay attention if the mail as already been marked and still send the mail.
I believe there is an error at line 16 "var emailSent = rowData[6];"
I would really appreciate if someone could help me. Whoever you are thanks in advance.
Here is the modified script :
var EMAIL_SENT = "EMAIL_SENT";
function sendEmails() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var dataSheet = ss.getSheets()[0];
var dataRange = dataSheet.getRange(2, 1, dataSheet.getMaxRows() - 1, 7);
var templateSheet = ss.getSheets()[1];
var emailTemplate = templateSheet.getRange("A2").getValue();
var objects = getRowsData(dataSheet, dataRange);
for (var i = 0; i < objects.length; ++i) {
var Resume = DriveApp.getFilesByName('Resume.pdf') var Portfolio = DriveApp.getFilesByName('Portfolio.pdf') var rowData = objects[i];
var emailText = fillInTemplateFromObject(emailTemplate, rowData);
var emailSubject = "Architectural Internship";
var emailSent = rowData[6];
if (emailSent != EMAIL_SENT) {
MailApp.sendEmail(rowData.emailAddress, emailSubject, emailText, {
attachments: [Resume.next(), Portfolio.next()]
});
dataSheet.getRange(2 + i, 7).setValue(EMAIL_SENT);
SpreadsheetApp.flush();
}
}
}
function fillInTemplateFromObject(template, data) {
var email = template;
var templateVars = template.match(/\${\"[^\"]+\"}/g);
for (var i = 0; i < templateVars.length; ++i) {
var variableData = data[normalizeHeader(templateVars[i])];
email = email.replace(templateVars[i], variableData || "");
}
return email;
}
function getRowsData(sheet, range, columnHeadersRowIndex) {
columnHeadersRowIndex = columnHeadersRowIndex || range.getRowIndex() - 1;
var numColumns = range.getEndColumn() - range.getColumn() + 1;
var headersRange = sheet.getRange(columnHeadersRowIndex, range.getColumn(), 1, numColumns);
var headers = headersRange.getValues()[0];
return getObjects(range.getValues(), normalizeHeaders(headers));
}
function getObjects(data, keys) {
var objects = [];
for (var i = 0; i < data.length; ++i) {
var object = {};
var hasData = false;
for (var j = 0; j < data[i].length; ++j) {
var cellData = data[i][j];
if (isCellEmpty(cellData)) {
continue;
}
object[keys[j]] = cellData;
hasData = true;
}
if (hasData) {
objects.push(object);
}
}
return objects;
}
function normalizeHeaders(headers) {
var keys = [];
for (var i = 0; i < headers.length; ++i) {
var key = normalizeHeader(headers[i]);
if (key.length > 0) {
keys.push(key);
}
}
return keys;
}
function normalizeHeader(header) {
var key = "";
var upperCase = false;
for (var i = 0; i < header.length; ++i) {
var letter = header[i];
if (letter == " " && key.length > 0) {
upperCase = true;
continue;
}
if (!isAlnum(letter)) {
continue;
}
if (key.length == 0 && isDigit(letter)) {
continue;
}
if (upperCase) {
upperCase = false;
key += letter.toUpperCase();
} else {
key += letter.toLowerCase();
}
}
return key;
}
// Returns true if the cell where cellData was read from is empty. // Arguments: // - cellData: string function isCellEmpty(cellData) {
return typeof(cellData) == "string" && cellData == "";
}
// Returns true if the character char is alphabetical, false otherwise. function isAlnum(char) { return char >= 'A' && char <= 'Z' || char >= 'a' && char <= 'z' || isDigit(char); }
// Returns true if the character char is a digit, false otherwise. function isDigit(char) { return char >= '0' && char <= '9'; }
Your code is really hard to read and the functions that return 2 or more objects make it even harder...you are using variable names that are also a bit confusing.... but that is probably a personal pov :-)
Anyway, I think I've found the issue: when you write var rowData = objects[i];
This "object" is actually the result of the getRowData function but if you look at this function, you'll see that it returns 2 objects, the first one being itself the result of another function (getObjects) ...
You are checking the value is the 6th element of the array which is actually an object and compare it to a string. The equality will never be true.
I didn't go further in the analyse since I found it really confusing ( as I already said) but at least you have a first element to check .
I would suggest you rewrite this code in a more simple way and use more appropriate variable names to help you while debugging.
I would recommend logging both values before executing to make sure they are the same. I would also guess that the email_sent and EMAIL_SENT are different data types. Can also try forcing the value to string for comparison.
To clarify:
logger.Log(emailSent);
logger.Log(EMAIL_SENT);
if (emailSent.toString() != EMAIL_SENT.toString())
{...
Error is in this line of code -
var dataRange = sheet.getRange(startRow, 1, numRows, 2)
It's considering only 2 columns in the range. Changed 2 to 3 and it worked fine.