list with case class scala - scala

Question

I have the following issue I have the following list as input
val input:List[Item]=List(FRDVE,12
SDED,13
prog-d,11
PROG-D,15
a-prog-d,17)
with
case class Item(Name:String,Number:Int)
The aim is to find only first line where name contains either prog-d or PROG-D
so for this case the expected output is:
val output="prog-d"
I wrote the following code :
def getName(input:List[Item]):Option[String]={
val matchLine=input.filter(Name.contains("prog-d"))
matchLine match {
case head::tail => Some(matchLine.head.split(",")(0))
case isEmpty => None
}
}
so here I am getting an error saying that the Name doesn't exist and I don't know how to put different possibilities in the contains : here it should basically be : Name.contains("prog-d" ||"PROG-D")
Any recommendations please
Thanks a lot

Answer 1

You can use collectFirst:
input.collectFirst { case Item(s, _) if s.equalsIgnoreCase("prog-d") => s }
This avoids both map and filter, so that only the minimal necessary amount of entries is inspected.
Full code:
case class Item(name: String, number: Int)
val input: List[Item] = List(
Item("FRDVE", 12),
Item("SDED", 13),
Item("prog-d", 11),
Item("PROG-D", 15),
Item("a-prog-d", 17),
)
val output = input.collectFirst {
case Item(s, _) if s.equalsIgnoreCase("prog-d") => s
}
println(output)

Answer 2

You can also use find where this function returns the option of first elements whichever matches your condition (stops iterating on remaining elements).
case class Item(Name:String,Number:Int)
val input = List(Item("FRDVE",12), Item("SDED",13), Item("prog-d",11), Item("PROG-D",15), Item("a-prog-d",17))
input.find(_.Name.equalsIgnoreCase("prog-d")) match {
case Some(item) => item.Name
case None => "" //your default string
}

Answer 3

you can use item.Name == "prog-d" || item.Name == "PROG-D" or item.Name.equalsIgnoreCase("prog-d")
scala> val input = List(Item("FRDVE",12), Item("SDED",13), Item("prog-d",11), Item("PROG-D",15), Item("a-prog-d",17))
input: List[Item] = List(Item(FRDVE,12), Item(SDED,13), Item(prog-d,11), Item(PROG-D,15), Item(a-prog-d,17))
scala> input.filter(item => item.Name.equalsIgnoreCase("prog-d")).map(_.Name)
res1: List[String] = List(prog-d, PROG-D)
If you want the first match, do headOption and play with it based on what data you want.
scala> val output = input.filter(item => item.Name.equalsIgnoreCase("prog-d")).headOption
output: Option[Item] = Some(Item(prog-d,11))
scala> val outputName = input.filter(item => item.Name.equalsIgnoreCase("prog-d")).headOption.map(_.Name)
outputName: Option[String] = Some(prog-d)
NOTE: (.head is not safe to use because List().head will explode when list is empty)
scala> List.empty[Item].head
java.util.NoSuchElementException: head of empty list
at scala.collection.immutable.Nil$.head(List.scala:428)
at scala.collection.immutable.Nil$.head(List.scala:425)
... 28 elided