Hello I need some help with MongoDB:
My Document has the following property (generated by an Map with spring):
"filter":{"billingAccount_id":["multisim5"],"simulate":["true"]}
and i'm trying to find the document with the this code (generated by spring)
query.addCriteria(Criteria.where("filter").all(getMapWithValues()));
which results in
"filter" : { "$all" : [{ "billingAccount_id" : ["multisim5"] }] }
but i'm getting no result. What's to do here?
Thanks for help in advance
You're applying $all on an object (filter) instead of an array (filter.billingAccount_id). Change your request (and method getMapWithValues) to get something like :
{"filter.billingAccount_id" : { "$all" : ["multisim5"] }}
BUT $all is used to find array that contains, at least, all values provided in query. Since there's an unique element in $all param, $all is useless here, and the following query output the same result :
{"filter.billingAccount_id" : "multisim5"}
EDIT : if you want to query array with exact match ("multisim5" and nothin else), use the following :
{"filter.billingAccount_id" : { "$eq" : ["multisim5"] }}
Related
I have this data structure:
{
"_id" : ObjectId("582ecaa97be792282ca31bc4"),
"hero" : {
"5001" : {
"id" : 5001
"name" : "Rogue"
}
"5002" : {
"id" : 5002
"name" : "Mage"
}
"5003" : {
"id" : 5002
"name" : "Paladin"
}
}
}
I have the query.
db.getCollection('hero').find({"Hero":{"5001":{"id" : 5001}}})
It returns 0 results.
I could store the Heros separately, but I would like to know how to do this query first. What I would like to get out of this is all data under 5001 if I query with 5001 and so forth.
Thanks!
Edit: I found the answer by using dot notation, I already tried dot notation but i got it a bit wrong when trying it, I thought it was only for arrays. Here is what you would do if anyone else is looking.
db.Runes.find({ "hero.5001.id": 5001 },{"hero.5001":1})
First of all, All the fields are case sensitive so you cannot query a "hero" field with "Hero".
second if you are querying nested documents you should use the "dot notation"
https://docs.mongodb.com/manual/core/document/#dot-notation
so the proper way to your that document will be.
db.getCollection('hero').find({"hero.5001.id" : 5001})
it will return the entire document. So entire hero object with 5002 and 5003 key will also return as they belong to the same document. You can use projection to project only the required fields.
which can be done as below
db.getCollection('hero').find({"hero.5001.id": 5001},{"hero.5001" : 1})
Here are more information about Mongodb query and projection operators
https://docs.mongodb.com/v3.2/reference/operator/query/
Just try this
db.getCollection('hero').find({"hero.5001.id" : 5001})
I have a collection like this in my mongo database, let's say it's called taxonomic.
{
"_id" : ObjectId("5810e15a762a39b41912a131"),
"validName" : "Eros",
"idUser" : ObjectId("1")
}
{
"_id" : ObjectId("5810e15a762a39b41912a132"),
"validName" : "Eros",
"idUser" : ObjectId("2")
}
I've already created a compound index to be able to search for the two values I want, such as this.
db.taxonomic.createIndex({"idUser":1,"validName":1})
Now, I want to be able to search and get a return from it only when both of the parameters are found on the same document of the collections, here's my try:
db.taxonomic.find({$text:{$search:"Eros 2"}},{idUser:1,validName:1})
The problem with this method is that it will return any match of "Eros" OR "2", what I want is a return of the values when "Eros" AND "2" are matched in a document of the collection.
Thank you for any help!
I dont think you require a text Index for it if you only want specific string
db.taxonomic.find({"$or" : [{"validName" : "Eros"},{"validName" : "2"}]},{idUser:1,validName:1})
I am new to querying dbs and especially mongodb.If I run :
db.<customers>.find({"contact_name: Anny Hatte"})
I get:
{
"_id" : ObjectId("55f7076079cebe83d0b3cffd"),
"company_name" : "Gap",
"contact_name" : "Anny Hatte",
"email" : "ahatte#gmail.com"
}
I wish to get the value of the "_id" attribute from this query result. How do I achieve that?
Similarly, if I have another collection, named items, with the following data:
{
"_id" : ObjectId("55f7076079cebe83d0b3d009"),
"_customer" : ObjectId("55f7076079cebe83d0b3cfda"),
"school" : "St. Patrick's"
}
Here, the "_customer" field is the "_id" of the customer collection (the previous collection). I wish to get the "_id", the "_customer" and the "school" field values for the record where "_customer" of items-collection equals "_id" of customers-collection.
How do I go about this?
I wish to get the value of the "_id" attribute from this query result.
How do I achieve that?
The find() method returns a cursor to the results, which you can iterate and retrieve the documents in the result set. You can do this using forEach().
var cursor = db.customers.find({"contact_name: Anny Hatte"});
cursor.forEach(function(customer){
//access all the attributes of the document here
var id = customer._id;
})
You could make use of the aggregation pipeline's $lookup stage that has been introduced as part of 3.2, to look up and fetch the matching rows in some other related collection.
db.customers.aggregate([
{$match:{"contact_name":"Anny Hatte"}},
{$lookup:{
"from":"items",
"localField":"_id",
"foreignField":"_customer",
"as":"items"
}}
])
In case you are using a previous version of mongodb where the stage is not supported, then, you would need to fire an extra query to lookup the items collection, for each customer.
db.customers.find(
{"contact_name":"Anny Hatte"}).map(function(customer){
customer["items"] = [];
db.items.find({"_customer":customer._id}).forEach(function(item){
customer.items.push(item);
})
return customer;
})
Sample json object :
{ "_id" : ObjectId( "55887982498e2bef5a5f96db" ),
"a" : "x",
"q" : "null",
"p" : "",
"s" : "{\"f\":{\"b\":[\"I\"]},\"time\":\"fs\"}" }
need all documents where time = fs
My query :
{"s":{"time" : "fs"}}
above returns zero products but that is not true.
There are two problems here. First of all s is clearly a string so your query cannot work. You can use $regex as below but it won't be very efficient:
{s: {$regex: '"time"\:"fs"'}}
I would suggest converting s fields to proper documents. You can use JSON.parse to do it. Documents can be updated based on a current value using db.foo.find().snapshot().forEach. See this answer for details.
Second problem is your query is simply wrong. To match time field you should use dot notation:
{"s.time" : "fs"})
I'm trying to find records in MongoDB that are created outside a specific period. The query to search for records inside a specific period is pretty straightforward:
db.test.find({"Published":{'$gt':"2011-08-02", '$lt':"2011-08-06"}})
So naturally, I tried this for "outside" a specific range:
db.test.find({'$not':{"Published":{'$gt':"2011-08-02", '$lt':"2011-08-06"}}})
But this returns an empty result, while there are definately records published then.
What query should I use instead? Can anyone help me? I'm using raw mongo queries.
Thanks in advance
--- UPDATE ---
I found that the following query works, but it doesn't look like the perfect solution:
db.test.find(
{'$or': [
{"Published":{'$lt':"2011-02-02"}},
{"Published":{'$gt':"2011-08-06"}}
]}
)
Is there a cleaner way to do it?
You are putting the $not in the wrong place. Try this:
db.test.find({"Published":{ $not:{$gt:"2011-08-02", $lt:"2011-08-06"} } })
For details, see the MongoDB docs about the $notoperator.
Edit as because of the comment this solution would not work:
> db.dates.find()
{ "_id" : ObjectId("5492d46ef6226b581c80c0a2"), "a" : 1, "date" : "2011-08-04" }
{ "_id" : ObjectId("5492d4e2f6226b581c80c0a3"), "a" : 2, "date" : "2011-08-07" }
> db.dates.find({date:{$not:{$gt:"2011-08-02",$lt:"2011-08-06"}}})
{ "_id" : ObjectId("5492d4e2f6226b581c80c0a3"), "a" : 2, "date" : "2011-08-07" }