Here is the surface plot in concerned.
I want to change the x,y,z in the floating annotation (the black box) to the name of the coordinate. For example, if my x axis is named width, i wish the floating annotation telling like width:0.12345. How can i do that?
The picture is from this tutorial of plotly: https://plot.ly/python/3d-parametric-plots/
Related
How to change in Paraview, the co-ordinate axes from default to left-handed co-ordinates from This to This
I am reading in a vtk file written in legacy format for rectilinear grid
Thanks for the help
ParaView does not support left-handed coordinates. The best you can do is convert your left handed coordinates to right-handed coordinates to make them displayed correctly. The easiest way to do so is probably to use the Transform filter and scale by -1 along one axis.
Unfortunately, you cannot change the labels of the orientation axes (in the lower right corner) to be labeled as left-handed. However, if you are using the Axes Grid, you can changes the labels of that to indicate left-handed coordinates.
I calculate the rectangular bounding box coordinates for objects in my matlab code ([xmin ymin width height]). But the coordinates might not be precise. Then, I want to draw the box on the image and modify that by dragging the box and/or adjusting the borders. I tried to use imrect and imcrop, but those functions do not draw the draggable/adjustable rectangle on image, based on predefined coordinates. Is there any way to do that?
Thanks in advance for your time.
Take a look at imrect. It works much like the imcrop rectangle but you can set an initial position and get the current position by calling getPosition.
I would like to change the view of a 3D plot in matlab such that the y-axis points upward and the z-axis points to left. For example, consider the following plot:
Here the x-axis points forward, the y-axis points to the right and the z-axis points upward.
I would like to have the y-axis points upward and the z-axis points to the left instead. I tried to rotate the plot (using the figure window toolbar rotate button) but I could not get it to work. (It should just be a simple 90 degrees rotation about the x-axis)
Code to generate the plot:
membrane
view(100,50)
xlabel('x-axis');
ylabel('y-axis');
zlabel('z-axis');
grid on
Try using view. I don't have MATLAB available so I can't test it, but I think it can do what you want.
Example from the documentation:
Set the view along the y-axis, with the x-axis extending horizontally
and the z-axis extending vertically in the figure.
view([0 0]);
EDIT:
Try using three inputs to the view function. I can't experiment myself, but you should be able to do it if you choose the right values here.
From documentation:
view([x,y,z]) sets the view direction to the Cartesian coordinates x,
y, and z. The magnitude of (x,y,z) is ignored.
EDIT 2:
Check out camroll. I think camroll(90) (possibly in combination with view) will work.
From documentation:
camroll(dtheta) rotates the camera around the camera viewing axis by
the amounts specified in dtheta (in degrees). The viewing axis is the
line passing through the camera position and the camera target.
This was posted a while ago, but in case someone else is looking for ways to set y-axis as the vertical one here is a possible fix.
Manually: In the command window type cameratoolbar('show') which will open an interactive toolbar in your plot from which you could change the view. One of the options is to set a principle axis to x, y, or z.
Or in you script you could use cameratoolbar('SetCoordSys',coordsys) command which sets the principal axis of the camera motion. coordsys can be: x, y, z, or none.
http://uk.mathworks.com/help/matlab/ref/cameratoolbar.html
Simple rounded corner rectangle code in Matlab can be written as follows.
rectangle('Position',[0,-1.37/2,3.75,1.37],...
'Curvature',[1],...
'LineWidth',1,'LineStyle','-')
daspect([1,1,1])
How to get the x and y coordinates arrays of this figure?
To get the axes units boundaries, do:
axisUnits = axis(axesHandle) % axesHandle could be gca
axisUnits will be an four elements array, with the following syntax: [xlowlim xhighlim ylowlim yhighlim], it will also contain the zlow and zhigh for 3-D plots.
But I think that is not what you need to know. Checking the matlab documentation for the rectangle properties, we find:
Position four-element vector [x,y,width,height]
Location and size of rectangle. Specifies the location and size of the
rectangle in the data units of the axes. The point defined by x, y
specifies one corner of the rectangle, and width and height define the
size in units along the x- and y-axes respectively.
It is also documented on the rectangle documentation:
rectangle('Position',[x,y,w,h]) draws the rectangle from the point x,y
and having a width of w and a height of h. Specify values in axes data
units.
See if this illustrate what you want. You have an x axis that goes from −100 to 100 and y axis that goes from 5 to 15. Suppose you want to put a rectangle from −30 to −20 in x and 8 to 10 in y.
rectangle('Position',[-30,8,10,2]);
As explained by the comments there appears to be no direct way to query the figure created by rectangle and extract x/y coordinates. On the other hand, I can think of two simple strategies to arrive at coordinates that will closely reproduce the curve generated with rectangle:
(1) Save the figure as an image (say .png) and process the image to extract points corresponding to the curve. Some degree of massaging is necessary but this is relatively straightforward if blunt and I expect the code to be somewhat slow at execution compared to getting data from an axes object.
(2) Write your own code to draw a rectangle with curved edges. While recreating precisely what matlab draws may not be so simple, you may be satisfied with your own version.
Whether you choose one of these approaches boils down to (a) what speed of execution you consider acceptable (b) how closely you need to replicate what rectangle draws on screen (c) whether you have image processing routines, say for reading an image file.
Edit
If you have the image processing toolbox you can arrive at a set of points representing the rectangle as follows:
h=rectangle('Position',[0,-1.37/2,3.75,1.37],...
'Curvature',[1],...
'LineWidth',1,'LineStyle','-')
daspect([1,1,1])
axis off
saveas(gca,'test.png');
im = imread('test.png');
im = rgb2gray(im);
figure, imshow(im)
Note that you will still need to apply a threshold to pick the relevant points from the image and then transform the coordinate system and rearrange the points in order to display properly as a connected set. You'll probably also want to tinker with resolution of the initial image file or apply image processing functions to get a smooth curve.
I am creating scatter graph, I need to change the x and y positions in scatter graph. Graph always starts with (0,0) positions but i need to show the starting points (7000, 800). Is there any way to change the x and y positions in scatter graph in core plot.
After showing the graph need to draw the line manually and get those values to search the properties.
Please help me.
Thanks in advance.
to set the point where the co-ordinates meet you have to set the orthogonal co-ordinate decimal
x.orthogonalCoordinateDecimal = CPTDecimalFromString(#"800");
y.orthogonalCoordinateDecimal = CPTDecimalFromString(#"740000");
and for setting the range of values to be plotted set the visibleRange for both the axes
These are features of the "plot space" in Core Plot. It defines the coordinate mapping between the plot area (basically the rectangle that contains all plot drawing) in data coordinates and the view in drawing coordinates. The xRange and yRange control the x and y range of the plot space, respectively.
The plot space converts coordinates in both directions—from data to view when drawing and from view to data when (for example) responding to touch events on a plot. See the plot space docs for a list of the available coordinate conversion methods.