powershell get-distributiongroupmember - powershell

Question

I am trying to get all members of a distribution group in office365 that are in two groups one. The first group "Precon" filters users that are in a specific group. The next group "Office" gets the office distribution group that the memebers are in. The end goal is that I would like to get the office location for each member in the precon group.
I have tried a couple of things but dont know if I have the correct syntax or if what I was trying even works the way I think it does.
So far this is what I have
$Session = New-PSSession -ConfigurationName Microsoft.Exchange -ConnectionUri https://outlook.office365.com/powershell-liveid/ -Credential $cred -Authentication Basic -AllowRedirection
Import-PSSession $Session -DisableNameChecking
$groupmembers = foreach($g in Get-DistributionGroup -Filter {name -like "Precon"}) {
Get-DistributionGroupMember -Identity $g.SamAccountName | select Name
}
$office = foreach($o in Get-DistributionGroup -Filter {name -like "*Office"})
{
Get-DistributionGroupMember -Identity $o.SamAccountName | select Name
}
$match = $groupmembers | ForEach {
if ($_ -imatch $office){
Write-Output $_ "matches"
}
}
$match
Any help would be appreciated.

Answer 1

What is the output?
For the last block of code I'd look at:
$match = $groupmembers | where $office -contains $_
$match

Answer 2

I found a method that works
$precon = #()
foreach($i in Get-DistributionGroup -Filter {Name -like '*Precon'}) {
$precon += ( Get-DistributionGroupMember -Identity $i.samAccountName | foreach {$_.Name} )
}
$office = #{}
foreach($i in Get-DistributionGroup -Filter {Name -like '*Office'}) {
$office[$i.name] += ( Get-DistributionGroupMember -Identity $i.samAccountName | foreach {$_.Name} )
}
$uber = #()
foreach ($key in $office.Keys) {
$preconOffice = $office[$key] | Where { $precon -Contains $_ }
foreach ($name in $preconOffice) { $uber += ( New-Object -TypeName PSObject -Prop (#{'Office' = $key ;'Name' = $name}) ) }
}
$uber