Get all AD Users and their group memberships (recursively) using Powershell - powershell

Question

I have a script from a previously answered question, but don't have enough reputation to comment. I tried to run that script and came across this error message:
Export-CSV : Cannot append CSV content to the following file: C:\users.csv. The appended object does not have a property that corresponds to the following column: User;Group. To continue with mismatched properties, add the -Force parameter, and then retry the command.
How can I debug this script to resolve this issue?
Function Get-ADGroupsRecursive{
Param([String[]]$Groups)
Begin{
$Results = #()
}
Process{
ForEach($Group in $Groups){
$Results+=$Group
ForEach($Object in (Get-ADGroupMember $Group|?{$_.objectClass -eq "Group"})){
$Results += Get-ADGroupsRecursive $Object
}
}
}
End{
$Results | Select -Unique
}}
import-module activedirectory
$users = get-aduser -Filter {Name -Like "*"} -Searchbase "OU=Sample Accounts,DC=domain,DC=com" -Properties MemberOf | Where-Object { $_.Enabled -eq 'True' }
$targetFile = "C:\users.csv"
rm $targetFile
Add-Content $targetFile "User;Group"
foreach ($user in $users)
{
$Groups = $User.MemberOf
$Groups += $Groups | %{Get-ADGroupsRecursive $_}
$Groups | %{New-Object PSObject -Property #{User=$User;Group=$_}}|Export-CSV $targetfile -notype -append
}

Answer 1

try this function
function Get-InChainGroups
{
param (
[parameter(mandatory = $true)]
$user,
$domain)
$user1 = (get-aduser -filter { name -eq $user } -server $domain).distinguishedname
Write-verbose "checking $user"
$ldap = "(&(objectcategory=group)(groupType:1.2.840.113556.1.4.803:=2147483648)(member:1.2.840.113556.1.4.1941:=$user1))"
try { Get-ADobject -LDAPFilter $ldap -server $domain | select #{ n = 'Identity'; e = { $user } }, Name, #{ n = 'DN'; e = { $_.distinguishedname } } | ft -a }
catch { "Exception occurred" }
}