How to achieve 1 column 2 rows to 2 columns 1 row on DB2 please?
eg :
select value from <tablename> WHERE name='VAR' ORDER BY effectivedate DESC FETCH FIRST 2 ROWS ONLY;
which gives
VAR
----
12
57
But I want to get
VAR1,VAR2
-----------
12 ,57
Thanks very much!
Typically, the best way to "pivot" rows to columns is to aggregate over CASE statements.
For example
SELECT MAX(CASE WHEN RN = 1 THEN value END) AS VAR1
, MAX(CASE WHEN RN = 2 THEN value END) AS VAR2
, MAX(CASE WHEN RN = 3 THEN value END) AS VAR3
, MAX(CASE WHEN RN = 4 THEN value END) AS VAR4
FROM (
SELECT *, ROW_NUMBER() OVER(ORDER BY effectivedate DESC) AS RN
FROM a_table T
)
will return this
VAR1 VAR2 VAR3 VAR4
---- ---- ---- ----
12 57 1 NULL
using the table and data in my other answer
which would return
Use substring and aliases
SELECT
SUBSTR(VAR, 1,LOCATE(' ',VAR)-1) as VAR1
, SUBSTR(VAR, LOCATE(' ',VAR)+1) as VAR2
FROM YOURTABLE;
Basically breaking on space, if you have fixed length you can use without locate.
There are many ways to do this. If you are on Db2 LUW 11.1 or above, this will work
SELECT * FROM TABLE(VALUES
( ( select value from a_table WHERE name='VAR' ORDER BY effectivedate DESC FETCH FIRST 1 ROW ONLY)
, ( select value from a_table WHERE name='VAR' ORDER BY effectivedate DESC OFFSET 1 ROW FETCH NEXT 1 ROW ONLY )
)) AS t(VAR1, VAR2)
and with this table and data
create TABLE a_table( value int, name char(3), effectivedate date);
INSERT INTO a_table values (12,'VAR','2018-01-10'),(57,'VAR', '2018-01-09'),(1,'VAR','2018-01-08');
will return this result
VAR1 VAR2
---- ----
12 57
Related
I will give you example of table that I have:
Supplier | Value
sup1 | 4
sup2 | 1
sup1 | 0
sup1 | 3
sup2 | 5
I need a result that will do average by supplier, but if there is value 0 for a supplier, do not average, but return 0 instead
It should look like this:
Supplier | Value
sup1 | 0
sup2 | 3
This is a little trick but it should work :
SELECT Supplier,
CASE WHEN MIN(ABS(Value)) = 0 THEN 0 ELSE AVG(Value) END
FROM TableTest
GROUP BY Supplier
EDIT : Using the ABS() function let you avoid having problems with negative values
DECLARE #TAB TABLE (SUPPLIER VARCHAR(50),VALUE INTEGER)
INSERT INTO #TAB
SELECT 'sup1',4
UNION ALL
SELECT 'sup2',1
UNION ALL
SELECT 'sup1',0
UNION ALL
SELECT 'sup1',3
UNION ALL
SELECT 'sup2',5
SELECT * FROM #TAB
SELECT T1.SUPPLIER,CASE WHEN EXISTS(SELECT 1 FROM #TAB T WHERE T.SUPPLIER = T1.SUPPLIER AND T.VALUE = 0) THEN 0 ELSE AVG(T1.VALUE) END AS VALUE
FROM #TAB T1
GROUP BY T1.SUPPLIER
Result
SUPPLIER VALUE
sup1 0
sup2 3
Using the following query is one of the way to do.
First I push the supplier which has the Value = 0, then based on the result, I will do the remaining calculation and finally using UNION to get the expected result:
DECLARE #ZeroValue TABLE (Supplier VARCHAR (20));
INSERT INTO #ZeroValue (Supplier)
SELECT Supplier FROM TestTable WHERE Value = 0
SELECT Supplier, 0 AS Value FROM #ZeroValue
UNION
SELECT T.Supplier, AVG(T.Value) AS Value
FROM TestTable T
JOIN #ZeroValue Z ON Z.Supplier != T.Supplier
GROUP BY T.Supplier
Schema used for the sample:
CREATE TABLE TestTable (Supplier VARCHAR (20), Value INT);
INSERT INTO TestTable (Supplier, Value) VALUES
('sup1', 4), ('sup2', 1), ('sup1', 0), ('sup1', 3), ('sup2', 5);
Please find the working demo on db<>fiddle
I am working on peoplesoft. I have a requirement where I have to update the column value in a sequence ordered based on some ID.
For eg.
CA24100001648- 1
CA24100001648- 2
CA24100001664- 1
CA24100001664- 2
CA24100001664- 3
CA24100001664- 4
CA24100001664- 5
CA24100001664- 6
But, I am getting '1' as the value for all the rows on updating.
Here is my query, can anyone please help out on this.
UPDATE PS_UC_CA_CONT_STG C
SET C.CONTRACT_LINE_NUM2 = ( SELECT row_number() over(PARTITION BY D.CONTRACT_NUM
order by D.CONTRACT_NUM)
FROM PS_UC_CA_HDR_STG D
WHERE C.CONTRACT_NUM=D.CONTRACT_NUM );
Thanksenter image description here
update emp a
set comm =
(with cnt as ( select deptno,empno,row_number() over (partition by deptno order by deptno) rn from emp)
select c.rn from cnt c where c.empno=a.empno)
I'm a little struggled with finding a clean way to do this. Assume that I have the following records in my table named Records:
|Name| |InsertDate| |Size|
john 30.06.2015 1
john 10.01.2016 10
john 12.01.2016 100
john 05.03.2016 1000
doe 01.01.2016 1
How do I get the records for year of 2016 and month is equal to or less than 3 grouped by month(even that month does not exists e.g. month 2 in this case) with cumulative sum of Size including that month? I want to get the result as the following:
|Name| |Month| |Size|
john 1 111
john 2 111
john 3 1111
doe 1 1
As other commenters have already stated, you simply need a table with dates in that you can join from to give you the dates that your source table does not have records for:
-- Build the source data table.
declare #t table(Name nvarchar(10)
,InsertDate date
,Size int
);
insert into #t values
('john','20150630',1 )
,('john','20160110',10 )
,('john','20160112',100 )
,('john','20160305',1000)
,('doe' ,'20160101',1 );
-- Specify the year you want to search for by storing the first day here.
declare #year date = '20160101';
-- This derived table builds a set of dates that you can join from.
-- LEFT JOINing from here is what gives you rows for months without records in your source data.
with Dates
as
(
select #year as MonthStart
,dateadd(day,-1,dateadd(month,1,#year)) as MonthEnd
union all
select dateadd(month,1,MonthStart)
,dateadd(day,-1,dateadd(month,2,MonthStart))
from Dates
where dateadd(month,1,MonthStart) < dateadd(yyyy,1,#year)
)
select t.Name
,d.MonthStart
,sum(t.Size) as Size
from Dates d
left join #t t
on(t.InsertDate <= d.MonthEnd)
where d.MonthStart <= '20160301' -- Without knowing what your logic is for specifying values only up to March, I have left this part for you to automate.
group by t.Name
,d.MonthStart
order by t.Name
,d.MonthStart;
If you have a static date reference table in your database, you don't need to do the derived table creation and can just do:
select d.DateValue
,<Other columns>
from DatesReferenceTable d
left join <Other Tables> o
on(d.DateValue = o.AnyDateColumn)
etc
Here's another approach that utilizes a tally table (aka numbers table) to create the date table. Note my comments.
-- Build the source data table.
declare #t table(Name nvarchar(10), InsertDate date, Size int);
insert into #t values
('john','20150630',1 )
,('john','20160110',10 )
,('john','20160112',100 )
,('john','20160305',1000)
,('doe' ,'20160101',1 );
-- A year is fine, don't need a date data type
declare #year smallint = 2016;
WITH -- dummy rows for a tally table:
E AS (SELECT E FROM (VALUES (1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) t(e)),
dateRange(totalDays, mn, mx) AS -- Get the range and number of months to create
(
SELECT DATEDIFF(MONTH, MIN(InsertDate), MAX(InsertDate)), MIN(InsertDate), MAX(InsertDate)
FROM #t
),
iTally(N) AS -- Tally Oh! Create an inline Tally (aka numbers) table starting with 0
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1))-1
FROM E a CROSS JOIN E b CROSS JOIN E c CROSS JOIN E d
),
RunningTotal AS -- perform a running total by year/month for each person (Name)
(
SELECT
yr = YEAR(DATEADD(MONTH, n, mn)),
mo = MONTH(DATEADD(MONTH, n, mn)),
Name,
Size = SUM(Size) OVER
(PARTITION BY Name ORDER BY YEAR(DATEADD(MONTH, n, mn)), MONTH(DATEADD(MONTH, n, mn)))
FROM iTally
CROSS JOIN dateRange
LEFT JOIN #t ON MONTH(InsertDate) = MONTH(DATEADD(MONTH, n, mn))
WHERE N <= totalDays
) -- Final output will only return rows where the year matches #year:
SELECT
name = ISNULL(name, LAG(Name, 1) OVER (ORDER BY yr, mo)),
yr, mo,
size = ISNULL(Size, LAG(Size, 1) OVER (ORDER BY yr, mo))
FROM RunningTotal
WHERE yr = #year
GROUP BY yr, mo, name, size;
Results:
name yr mo size
---------- ----------- ----------- -----------
doe 2016 1 1
john 2016 1 111
john 2016 2 111
john 2016 3 1111
I want max startdate but there is a NULL data, it will be null.
Sample data is as follows:
DECLARE #Tbl TABLE (Id INT, StartDate DATETIME)
INSERT INTO #Tbl
VALUES (1, NULL),
(1, '2016.07.30'),
(1, '2016.07.05'),
(1, '2016.07.05'),
(2, '2016.07.07'),
(2, '2016.07.05'),
(3, '2016.07.05'),
(3, NULL)
My Query:
SELECT Id, MAX(StartDate) AS StartDate
FROM #Tbl
GROUP BY Id
Output:
Id StartDate
----------- ----------
1 2016-07-30
2 2016-07-07
3 2016-07-05
Desired Output:
Id StartDate
----------- ----------
1 NULL
2 2016-07-07
3 NULL
To solve this problem we can use a count function that behave different in two cases:
when we use count(*) then all rows are count (also with null value)
when we use count(someFieldName) then only rows with not null value are count
You can see this different behaviour on this example using sample data from the question
select Id, count(*) as count_all, count(StartDate) as count_StartDate
from #Tbl
group by Id;
On the output we can see this
Id count_all count_StartDate
1 4 3
2 2 2
3 2 1
We can use this different behaviour to solve problem from question by this query
select Id, case when count(*) = count(StartDate)
then max(StartDate)
else null
end as StartDate
from #Tbl
group by Id
On the output we can see the desired result
Id StartDate
1 NULL
2 2016-07-07 00:00:00.000
3 NULL
Found the result.
SELECT Id, CASE
WHEN MAX(COALESCE(StartDate, '2099.01.01')) = '2099.01.01' THEN NULL
ELSE MAX(StartDate) END AS StartDate
FROM #Tbl
GROUP BY Id
Assume we have a table and we want to do a sum of the Expend column so that the summation only adds up values of the same Week_Name.
SN Week_Name Exp Sum
-- --------- --- ---
1 Week 1 10 0
2 Week 1 20 0
3 Week 1 30 60
4 Week 2 40 0
5 Week 2 50 90
6 Week 3 10 0
I will assume we will need to `Order By' Week_Name, then compare the previous Week_Name(previous row) with the current row Week_name(Current row).
If both are the same, put zero in the SUM column.
If not the same, add all expenditure, where Week_Name = Week_Name(Previous row) and place in the Sum column. The final output should look like the table above.
Any help on how to achieve this in T-SQL is highly appreciated.
Okay, I was eventually able to resolve this issue, praise Jesus! If you want the exact table I gave above, you can use GilM's response below, it is perfect. If you want your table to have running Cumulatives, i.e. Rows 3 shoud have 60, Row 5, should have 150, Row 6 160 etc. Then, you can use my code below:
USE CAPdb
IF OBJECT_ID ('dbo.[tablebp]') IS NOT NULL
DROP TABLE [tablebp]
GO
CREATE TABLE [tablebp] (
tablebpcCol1 int PRIMARY KEY
,tabledatekey datetime
,tableweekname varchar(50)
,expenditure1 numeric
,expenditure_Cummulative numeric
)
INSERT INTO [tablebp](tablebpcCol1,tabledatekey,tableweekname,expenditure1,expenditure_Cummulative)
SELECT b.s_tablekey,d.PK_Date,d.Week_Name,
SUM(b.s_expenditure1) AS s_expenditure1,
SUM(b.s_expenditure1) + COALESCE((SELECT SUM(s_expenditure1)
FROM source_table bs JOIN dbo.Time dd ON bs.[DATE Key] = dd.[PK_Date]
WHERE dd.PK_Date < d.PK_Date),0)
FROM source_table b
INNER JOIN dbo.Time d ON b.[Date key] = d.PK_Date
GROUP BY d.[PK_Date],d.Week_Name,b.s_tablekey,b.s_expenditure1
ORDER BY d.[PK_Date]
;WITH CTE AS (
SELECT tableweekname
,Max(expenditure_Cummulative) AS Week_expenditure_Cummulative
,MAX(tablebpcCol1) AS MaxSN
FROM [tablebp]
GROUP BY tableweekname
)
SELECT [tablebp].*
,CASE WHEN [tablebp].tablebpcCol1 = CTE.MaxSN THEN Week_expenditure_Cummulative
ELSE 0 END AS [RunWeeklySum]
FROM [tablebp]
JOIN CTE on CTE.tableweekname = [tablebp].tableweekname
I'm not sure why your SN=6 line is 0 rather than 10. Do you really not want the sum for the last Week? If having the last week total is okay, then you might want something like:
;WITH CTE AS (
SELECT Week_Name,SUM([Expend.]) as SumExpend
,MAX(SN) AS MaxSN
FROM T
GROUP BY Week_Name
)
SELECT T.*,CASE WHEN T.SN = CTE.MaxSN THEN SumExpend
ELSE 0 END AS [Sum]
FROM T
JOIN CTE on CTE.Week_Name = T.Week_Name
Based on the requst in the comment wanting a running total in SUM you could try this:
;WITH CTE AS (
SELECT Week_Name, MAX(SN) AS MaxSN
FROM T
GROUP BY Week_Name
)
SELECT T.SN, T.Week_Name,T.Exp,
CASE WHEN T.SN = CTE.MaxSN THEN
(SELECT SUM(EXP) FROM T T2
WHERE T2.SN <= T.SN) ELSE 0 END AS [SUM]
FROM T
JOIN CTE ON CTE.Week_Name = T.Week_Name
ORDER BY SN