I have a table that has a column date and value, what I need is to sum a value showing just one date column.
Ex:
I have this:
date value
2018-01-01 150
2018-01-23 140
what I need:
date sum(value)
2018-01 290
Simple solution to get sums per month:
SELECT to_char(date, 'YYYY-MM') AS mon, sum(value) AS sum_value
FROM tbl
GROUP BY 1;
For large tables it's cheaper to group on date_trunc('month', date) instead.
Related:
Concatenate multiple result rows of one column into one, group by another column
Group and count events per time intervals, plus running total
How to get the date and time from timestamp in PostgreSQL select query?
Related
I have problem select data between two dates if the only start_date is available.
The example I want to see is what discount_nr was active between 2020-07-01 and 2020-07-15 or only one day 2020-07-14. I tried different solutions, date range, generate series, and so on, but was still not able to get it to work.
Table only have start dates, no end dates
Example:
discount_nr, start_date
1, 2020-06-30
2, 2020-07-03
3, 2020-07-10
4, 2020-07-15
You can get the end dates by looking at the start date of the next row. This is done with lead. lead(start_date) over(order by start_date asc) will get you the start_date of the next row. If we take 1 day from that we'll get the inclusive end date.
Rather than separate start/end columns, a single daterange column is easier to work with. You can use that as a CTE or create a view.
create view discount_durations as
select
id,
daterange(
start_date,
lead(start_date) over(order by start_date asc)
) as duration
from discounts
Now querying it is easy using range operators. #> to check if the range contains a date.
select *
from discount_durations
where duration #> '2020-07-14'::date
And use && to see if they have any overlap.
select *
from discount_durations
where duration && daterange('2020-07-01', '2020-07-15');
Demonstration
I have a working query that allows me to sum value field each day.
SELECT sum(value) as sum_value, to_char(time::date,'DD-MM-YY') as day
FROM "measures"
GROUP BY "day"
ORDER BY "day" asc
Is it possible to do the same query, but instead of grouping by day, grouping it by 2 days,or a specific duration ( days only, not hours)
You can use timescaledb extension time_bucket() function as #Mike Organek commented or use native PosgreSQL data transformation like:
SELECT
sum(value) as sum_value,
to_char(time::date,'DD-MM-YY') as day,
floor(extract(epoch from "time")/(60*60*24*2)) as time_bucket
FROM "measures"
GROUP BY "time_bucket"
ORDER BY "day" asc;
In above query we extract unixtime from datetime column, divide it to grouping period in seconds (60*60*24*2 - mean 2 days or 48 hours) and round it fro use into group by statement
I have a table Logs with fields
Amount,date
I need to get the sum of amount and months grouped by each day
I need to migrate my sqlite code to postgresql but i find the code migration kind of hard.The sqlite code is as follows
SELECT SUM(amount),transaction_date FROM log WHERE user_id = 1 AND strftime('%Y', transaction_date) = '2019' GROUP BY strftime('%d', transaction_date);
What i need to is date and total amount grouped by day for the year 2019
You need extract() function instead of strftime() to get the year and cast transaction_date to date only if it is timestamp, if it is of data type date remove the casting ::date:
SELECT
SUM(amount),
transaction_date::date
FROM log WHERE user_id = 1 AND extract(year from transaction_date) = 2019
GROUP BY transaction_date::date
I have a table with a row for each sale of a product. These rows include a date. I want to know the number of products sold for each distinct day in a range (user specifies the begin and end dates.) There is a distinct row for each sale, so on days where several products were sold, several rows with this date exist. I want to count the number of these rows, with the same date. How might this be done efficiently in postgresql?
Example
2015-01-02: 0
2015-01-03: 7
2015-01-04: 2
Assuming the date column is stored as a datetime, something like this should get you in the right direction:
SELECT date_trunc('day', TIMESTAMP sales.date) as day, COUNT(*)
FROM sales
WHERE day >= start and <= end
GROUP BY day;
where start and end are filled in by the user.
More documentation for postgres's date features found here:
http://www.postgresql.org/docs/9.4/static/functions-datetime.html
If they are not datetime, you can use the to_date function with the appropriate format string to convert to datetime and the use the solution above:
SELECT date_trunc('day', to_date('2015-01-02', 'YYYY-MM-DD'));
http://www.postgresql.org/docs/9.4/static/functions-formatting.html
How to get the total count for particular date by selecting different dates.
For Example:
Record contains from '2014-04-01' to till date. Each date contains multiple records with different IST time.
How to get the total count from each date?
depending on your table structure and result you want, Query should look somewhat like this
SELECT DATE(date_column), COUNT(*)
FROM tablename
WHERE date_column IN (your_date_list)
GROUP BY date(date_column);
Have a look at the following sql (I have not tested)
SELECT date_column, COUNT(*)
FROM tablename
WHERE date_column BETWEEN date_column AND current_date
GROUP BY to_date(date_column::text,'YYYY-MM-DD')