I have created 2 activity. In first avtivity has a button which if I click it start second activity. And I set in AndroidManifest.xml file android:parentActivityName=".MainActivity" for second activity.Now on second activity has back button icon which if I click it will back to first activity. The problem is if I click it slides to the right side.How can I slide it to the left for open first activity?
You have to create anim xml files for entry and exit animation and use overridePendingTransition to perform animation.
See this link Android Left to Right slide animation
Related
There are 2 buttons - Button A and Button B.
Button B is situated on top of Button A.
Button B has it's Button Component removed.
I want the user to be able to click on Button A even though Button B obscures it.
How can I achieve this?
Not sure What is your question but if you want to click start button while air button is above it. you should disable the option on button called Interactable and also uncheck the toggle in image component of that button called Raycast Target. and that will do it.
Of course Button B button will block the one underneath it. Because Image component and Text and/or other Image component that button has blocks raycast to the button underneath of it.
You can do one of the following:
Remove your Button B button, because if it's not doing anything and actually interferes with a behavior you want then why have it in the first place? Think about it
Uncheck Raycast Target in your Button B button's Image component
Disable Image component of Button B button altogether
Thinking about first item on the list will benefit you greatly.
If you want a solution then use second or third option on the list, but bare in mind that unchecking Raycast Target or disabling Image component of your "Air" button still leaves an Image and/or Text as a child of aforementioned button that CAN and WILL block raycast to your Button A button.
I have a small code as shows below, I want to add previous and next button when pictures popup.
https://www.jqueryscript.net/gallery/Simple-Clean-jQuery-Vertical-Product-Gallery.html
I'm trying to make a Cocoa app with buttons that run simple command line scripts.
I can't seem to figure out how to add the action to my button.
I've read some docs that suggest holding down option and dragging the button into controller code but I think they are out of date. Can someone suggest how to get there from this screenshot?
You need to first select your button, then hold the control ⌃ button on your keyboard and then drag that across to your view controller. That will then give you the option of what to name your method etc.
Actually I had the same problem and the root cause was just the drag method. From the descriptions I had assumed that I need to press CTL and then drag while having the left mouse button pressed. This did not work at all (in my environment). Then I noticed that "it works" with the right mouse button. But the result was not correct. (E.g. I could not get "Action"). Finally I found: I have to use the right mouse button only for dragging without holding CTL. Then I got the correct result.
I've got a standard slide box setup :
<ion-slide-box >
<ion-slide >
< some text and a button with ng-click="go('/a-new-html-page')">
</ion-slide >
<ion-slide >
< some more text and another button with ng-click="go('/another-new-html-page')>
</ion-slide >
</ion-slide-box >
When I use my app, I slide to the second box and click the button to be sent to another-new-html-page. This is an options page with a list of check box options.The things I tick here will be shown back in list on the second the second slide box on my starting page - so I tick one or more options and click the back button...
.. and that where I get stuck. I have returned to back to the main screen of my app but at the FIRST slide box. You have to slide along to the second box to see those changes which of course is not very user friendly.
Is there a way to return back to the FIRST slide box if i hit back from the "a-new-html-page" and the SECOND slide box if I hit back from the "another-new-html-page"
I'm very new to Ionic and probably making all kinds of "school boy" errors so any help would be greatly appreciated!
I create a UITableView and show it on Edit mode, In edit mode a (-) sign was showing on left side of each row, when pressing this button a Delete button come's from the right side and by pressing this delete button the row was deleted.
I want to remove (-) button from left side and I want to show delete button always on the right side.
In short I want a delete button on right side which delete my row just like we delete row in edit mode. But do not want the (-) button on left side.
AFAIK,this can only be achieved through a custom UITableViewCell and it is also easy.
Here is a link from the cocoa with love site and
Here is one from icodeblog
Hope this helps.