I have a small code as shows below, I want to add previous and next button when pictures popup.
https://www.jqueryscript.net/gallery/Simple-Clean-jQuery-Vertical-Product-Gallery.html
Related
I start learning Swift and try to fulfill using one image picker change button image when users trigger one of three buttons.
I watch online resource and understand how to use one image picker for changing one button image
But now I have three buttons, and each of them should have the ability to use image picker and change their own button image.
My solution for this is every time when the button is clicked and image picker is called, I set the UIImage outside the function equal to the info image
At meanwhile, knowing that image picker has triggered because the button was pushed down, I put a line for set-button-image with that UIImage in the button (IBAction function).
Below is my source code. Somehow the way I wrote will not update the button's image correctly.
Let me know if any information is missing or confused. Any advice or knowledge will be helpful, thanks.
sourceCode1
sourceCode2
main page
after clicking the add button the library shows
after select image, the button image shows all white
after clicking the white part, the image somehow shows
If I click another button, the button change like the first button???
I have created 2 activity. In first avtivity has a button which if I click it start second activity. And I set in AndroidManifest.xml file android:parentActivityName=".MainActivity" for second activity.Now on second activity has back button icon which if I click it will back to first activity. The problem is if I click it slides to the right side.How can I slide it to the left for open first activity?
You have to create anim xml files for entry and exit animation and use overridePendingTransition to perform animation.
See this link Android Left to Right slide animation
I've got a standard slide box setup :
<ion-slide-box >
<ion-slide >
< some text and a button with ng-click="go('/a-new-html-page')">
</ion-slide >
<ion-slide >
< some more text and another button with ng-click="go('/another-new-html-page')>
</ion-slide >
</ion-slide-box >
When I use my app, I slide to the second box and click the button to be sent to another-new-html-page. This is an options page with a list of check box options.The things I tick here will be shown back in list on the second the second slide box on my starting page - so I tick one or more options and click the back button...
.. and that where I get stuck. I have returned to back to the main screen of my app but at the FIRST slide box. You have to slide along to the second box to see those changes which of course is not very user friendly.
Is there a way to return back to the FIRST slide box if i hit back from the "a-new-html-page" and the SECOND slide box if I hit back from the "another-new-html-page"
I'm very new to Ionic and probably making all kinds of "school boy" errors so any help would be greatly appreciated!
I have 1st FB popup showing a small image and some data. I want to be able to click on the image and load/reload bigger version of the same image, with back button to go back to first FB popup ... im a simple programmer and need simple solution pls
I am trying to call new Requests Dialog from an iframe facebook application by clicking a button located at the bottom of a page (you need to scroll to get there).
This is what happens when you click the button:
Temporary dialog with a progress bar is displayed in the middle of visible screen
Page is getting automatically scrolled to the top
Actual dialog appears in place of that temp loading dialog at the bottom of the page, so it is not visible
Is there a way to make it either not scroll to the top automatically or at least display the final dialog at the top as well so it can be seen?
it's a bug: http://bugs.developers.facebook.net/show_bug.cgi?id=15440