I am getting input like s1,s2,s3,s4.i am writing it to file.
Tried below way :
$ServerList = Get-Content "D:\ServerName.txt"
Clear-Content -Path "D:\ServerName.txt"
[IO.File]::ReadAllText($ServerList) -replace ',',"`r`n" | Out-File "D:\ServerName.txt"
But it is not writing anything.
It should replace comma with newline to bring each server in new line.
Please let me know where i am doing wrong.
This oneliner is working for me:
(Get-Content "Path\test.txt") -replace ',',"`r`n" | Out-File "Path\test.txt"
Related
I'm pretty sure this is can be done easily but i couldn't find the answer.
Suppose i have a text file with a bunch of lines in it.
Contents of the text file below
dbuser=admin
dbpassword=
So in Powershell I want to find the string "dbpassword=" and add the text "password" right after the =.
Solutions I've searched for have -replace but i don't want to replace the line, just want to add "password" to it.
Can anyone share what the Powershell code may be?
This assumes that everything after the = character becomes 'password'.
Get-Content -Path '.\bunchoflines.txt' |
ForEach-Object { $_ -match '^dbpassword=' ? 'dbpassword=password' : $_ }
Not sure why you care if it's replaced, but you could just output that line followed by the password instead. Assuming you want to update the file I'd use Set-Content to write it and a switch statement to read the file.
$inputfile = '\path\to\inputfile.txt'
Set-Content -Path $inputfile -value $(
switch -Regex -File $inputfile {
'^dbpassword=' {"$($_)password"}
default {$_}
}
)
Thanks all for your contributions, I ended up finding this solution.
$config = Get-Content path\to\file\somefile.txt
$password = abcdef
$config -replace "dbpassword=.*",("dbpassword="+$password) |
Set-Content path\to\file\somefile.txt
I'm actually trying to build some code to identify rights on shared folders in every single server I've got in my enterprise.
For now, I've already listed every single server and exported it in a .txt file, did a loop on this .txt to export in an other .txt file all shared folders.
All this is working fine but the path is like : c:\...\...\folder$.
To be able to use this I need to do a loop to replace c:\ d:\ etc. with \\servername\c$\.
I've tried using [system.io.file]::ReadAllText and WriteAllText, it's working fine for one letter but didn't find a way to do a loop on it.
I've tried
get-content ... -replace "c:\","\\$ServerName\c$\" ` -replace "d:\" ...
but got an error about regular expression not valid, so trying with [regex]::Escape but didn't work as expected neither...
Powershell
$contenu = [System.IO.File]::ReadAllText("$path\$SharedFolders.txt").Replace("C:\","\\$SharedFolders\c$\")
[System.IO.File]::WriteAllText("$path\$SharedFolders.txt", $contenu)
Powershell
(Get-Content "$path\$SharedFolders.txt") | foreach {
$_ -replace "C:\","\\$SharedFolders\C$\" `
-replace "D:\","\\$SharedFolders\D$\" `
[...] | Set-Content "$path\$sharedfolders.txt"}
And i'd like to have something like that :
Powershell
('a'..'z').ForEach({ (Get-Content "$path\$SharedFolders.txt" -Raw).replace("$_`:\","\\$SharedFolders\$_$") })
But I'm too newbie in Powershell to make it work proprely
You need PSv6 to use 'a'..'z'
The -replace operator is RegEx based, you need to escape a literal backslash with another one in the pattern.
following #Lee_Daileys hint build a RegEx with valid Drive letters
$OFS = '|'
$RE = ('('+(Get-Psdrive -PSProvider filesystem).where({$_.Displayroot -notmatch '^\\'}).name)+'):\\'
$OFS = $Null
"`$RE = '{0}'" -f $RE
'Loop to replace c:\, d:\ … z:\ with \\servername\c$\' -replace $RE,"\\servername\`${1}$\"
Sample output on my PC
$RE = '(A|C|D):\\'
Loop to replace \\servername\c$\, \\servername\d$\ … z:\ with \\servername\c$\
Reading the file with the -raw parameter doesn't require a loop, but wil do all changes at once.
$OFS = '|'
$RE = ('('+(Get-Psdrive -PSProvider filesystem).where({$_.Displayroot -notmatch '^\\'}).name)+'):\\'
$OFS = $Null
$File = "$path\$SharedFolders.txt"
(Get-Content $File -raw) -replace $RE,"\\servername\`${1}$\" |
Set-Content $File
Well thanks for your help, I just manage to make it works like that :
$lecteur=[int][char]'A'
1..26 | % {
$LR=[char]$lecteur
$contenu =[System.IO.File]::ReadAllText("$path\$SharedFolders.txt").Replace("${LR}:\","\\$SharedFolders\$LR$\")
[System.IO.File]::WriteAllText("$path\$SharedFolders.txt", $contenu)
$lecteur++
}
Hope it'll help some people ;)
I know that I can use:
gc c:\FileWithEmptyLines.txt | where {$_ -ne ""} > c:\FileWithNoEmptyLines.txt
to remove empty lines. But How I can remove them with '-replace' ?
I found a nice one liner here >> http://www.pixelchef.net/remove-empty-lines-file-powershell. Just tested it out with several blanks lines including newlines only as well as lines with just spaces, just tabs, and combinations.
(gc file.txt) | ? {$_.trim() -ne "" } | set-content file.txt
See the original for some notes about the code. Nice :)
This piece of code from Randy Skretka is working fine for me, but I had the problem, that I still had a newline at the end of the file.
(gc file.txt) | ? {$_.trim() -ne "" } | set-content file.txt
So I added finally this:
$content = [System.IO.File]::ReadAllText("file.txt")
$content = $content.Trim()
[System.IO.File]::WriteAllText("file.txt", $content)
You can use -match instead -eq if you also want to exclude files that only contain whitespace characters:
#(gc c:\FileWithEmptyLines.txt) -match '\S' | out-file c:\FileWithNoEmptyLines
Not specifically using -replace, but you get the same effect parsing the content using -notmatch and regex.
(get-content 'c:\FileWithEmptyLines.txt') -notmatch '^\s*$' > c:\FileWithNoEmptyLines.txt
To resolve this with RegEx, you need to use the multiline flag (?m):
((Get-Content file.txt -Raw) -replace "(?m)^\s*`r`n",'').trim() | Set-Content file.txt
If you actually want to filter blank lines from a file then you may try this:
(gc $source_file).Trim() | ? {$_.Length -gt 0}
You can't do replacing, you have to replace SOMETHING with SOMETHING, and you neither have both.
This will remove empty lines or lines with only whitespace characters (tabs/spaces).
[IO.File]::ReadAllText("FileWithEmptyLines.txt") -replace '\s+\r\n+', "`r`n" | Out-File "c:\FileWithNoEmptyLines.txt"
(Get-Content c:\FileWithEmptyLines.txt) |
Foreach { $_ -Replace "Old content", " New content" } |
Set-Content c:\FileWithEmptyLines.txt;
file
PS /home/edward/Desktop> Get-Content ./copy.txt
[Desktop Entry]
Name=calibre
Exec=~/Apps/calibre/calibre
Icon=~/Apps/calibre/resources/content-server/calibre.png
Type=Application*
Start by get the content from file and trim the white spaces if any found in each line of the text document. That becomes the object passed to the where-object to go through the array looking at each member of the array with string length greater then 0. That object is passed to replace the content of the file you started with. It would probably be better to make a new file...
Last thing to do is reads back the newly made file's content and see your awesomeness.
(Get-Content ./copy.txt).Trim() | Where-Object{$_.length -gt 0} | Set-Content ./copy.txt
Get-Content ./copy.txt
This removes trailing whitespace and blank lines from file.txt
PS C:\Users\> (gc file.txt) | Foreach {$_.TrimEnd()} | where {$_ -ne ""} | Set-Content file.txt
Get-Content returns immutable array of rows. You can covert this to mutable array and delete neccessary lines by index.Particular indexex you can get with match. After that you can write result to new file with Set-Content. With this approach you can avoid empty lines that powershell replace tool leaves when you try to replace smthing with "". Note that I dont guarantee perfect perfomance. Im not a professional powershell developer))
$fileLines = Get-Content $filePath
$neccessaryLine = Select-String -Path $filePath -Pattern 'something'
if (-Not $neccessaryLine) { exit }
$neccessaryLineIndex = $neccessaryLine.LineNumber - 1
$updatedFileContent = [System.Collections.ArrayList]::new($fileLines)
$updatedFileContent.RemoveAt($neccessaryLineIndex)
$updatedHostsFileContent.RemoveAt($domainInfoLineIndex - 1)
$updatedHostsFileContent | Set-Content $hostsFilePath
Set-Content -Path "File.txt" -Value (get-content -Path "File.txt" | Select-String -Pattern '^\s*$' -NotMatch)
This works for me, originally got the line from here and added Joel's suggested '^\s*$': Using PowerShell to remove lines from a text file if it contains a string
What would be the command to remove everything after a string (\test.something).
I have information in a text file, but after the string there is like a 1000 lines of text that I don't want. how can I remove everything after and including the string.
This is what I have - not working. Thank you so much.
$file = get-item "C:\Temp\test.txt"
(Get-Content $file) | ForEach {$_.TrimEnd("\test.something\")} | Set-Content $file
Why remove everything after? Just keep everything up to it (I'm going to use two lines for readability but you can easily combine into single command):
$text = ( Get-Content test.txt | Out-String ).Trim()
#Note V3 can just use Get-Content test.txt -raw
$text.Substring(0,$text.IndexOf('\test.something\')) | Set-Content file2.txt
Also, you may not need the Trim but you were using TrimEnd so added in case you want to add it later. )
Using -replace
(Get-Content $file -Raw) -replace '(?s)\\test\.something\\.+' | Set-Content $file
In Powershell Script, how do I convert a | (pipe) delimited CSV file to a , (comma) delimited CSV file?
When we use the following command in Windows Powershell Encoding 'UTF8' -NoType to convert from | (pipe delimiter) to , (comma delimiter), the file is converted with , delimited but the string was surrounded by " " (double quotes). Like given below:
Source file data:
ABC|1234|CDE|567|
Converted file data:
"ABC","1234","CDE","567",
I want to generate the following:
ABC,1234,CDE,567,
What command can I use to convert the delimiter from | to ,?
I would use:
(Get-Content -Path $file).Replace('|',',') | Set-Content -Path $file
You must escape the pipe, so:
(get-content "d:\makej\test.txt" ) -replace "\|","," | set-content "d:\makej\test.csv"
Seems easy enough:
(get-content $file) -replace '|',',' | set-content $file
In general, you should use the commands Import-Csv and Export-Csv which properly handle delimiters embedded in the field values, such as Field,1|Field2. The Get-Content based solutions would turn this into 3(!) fields Field,1,Field2, while the output actually should be quoted like "Field,1",Field2 or "Field,1","Field2".
Import-Csv input.csv -Delimiter '|' | Export-Csv output.csv -Delimiter ','
This always quotes fields in "output.csv". Since PowerShell (Core) 7+, the new Export-Csv parameters -UseQuotes and -QuoteFields allow us to control the quoting of the output file.
E. g. to quote only if necessary (when a field value contains the delimiter or quotation marks):
Import-Csv input.csv -Delimiter '|' | Export-Csv output.csv -Delimiter ',' -UseQuotes AsNeeded
Be careful with -UseQuotes Never, because it can render the output file unreadable, if a field value contains embedded delimiter or quotation marks.
Here is a function to convert to unquoted CSV for PowerShell 5.x (possibly supports older versions as well). This is like -UseQuotes Never, so make sure your data doesn't contain the delimiter. Additionally you may omit the header by passing the -NoHeader switch.
Function ConvertTo-CsvUnquoted {
[CmdletBinding()]
param (
[Parameter(Mandatory, ValueFromPipeline)] $InputObject,
[string] $Delimiter = ',',
[switch] $NoHeader
)
process {
if( -not $NoHeader ) {
$_.PSObject.Properties.Name -join $Delimiter
$NoHeader = $true
}
$_.PSObject.Properties.Value -join $Delimiter
}
}
Usage example:
Import-Csv input.csv | ConvertTo-CsvUnquoted -Delimiter '|' | Set-Content output.csv
Sorry this may need some tweaking on your part, but it does the job. Note that this also changes the file type from .txt to .csv which I dont think you wanted.
$path = "<Path>"
$outPath = $path -replace ".txt",".csv"
Get-Content -path $path |
ForEach-Object {$_ -replace "|","," } |
Out-File -filepath $outPath
I view the suggested answers as a little risky, because you are getting the entire contents of the existing file into memory, and therefore won't scale well, and risks using a lot of memory. My suggestion would be to use the string replace as the previous posts suggested, but to use streams instead for both reading and writing. That way you only need memory for each line in the file rather than the entire thing.
Have a look here at one of my other answers here:
https://stackoverflow.com/a/32337282/380016
And in my sample code you'd just change the string replace to:
$s = $line -replace '|', ','
And also adjust your input and output filenames accordingly.