I have a bash script, in the end will find folders with modified timestamps greater than 5 days then pipe it to xargs to rm. This is working fine and to print the command I am using -t option for the xargs as well. But I need this output written to a log file.
so my command line is as follows :
find /tmp/test -type d -mtime +5 -print0 | xargs -t -0 -I {} /bin/rm -rf '{}'
I would like to get the output to know which all folders are deleted to a file named rmdirs.log
I tried redirecting it to a file but like below and it wont work;
find /tmp/test -type d -mtime +5 -print0 | xargs -t -0 -I {} /bin/rm -rf '{}' >> rmdirs.log
Any help would be much appreciated.
I created a test environment with touch. This properly deletes the directory and logs the ones deleted to rmdirs.log file.
touch -t 202201010000 tmp/test/old
touch tmp/test/new
find tmp/test -type d -mtime +5 -print | \
tee -a rmdirs.log | \
tr '\12' '\0' | \
xargs -0 -I {} /bin/rm -rf {}
Use teeto append (-a) to the rmdirs.log file.
Use tr to convert the newlines (\12) to null (\0) for safety.
Finally run xargs to remove the files.
Related
I am trying to create a script which looks for x days old files that have a specific string in it, it then removes it and logs the file it has changed.
My way is probably not the best way, but I am new to this so looking for some help. I have got to a stage where the script works but it does not log the file name it has worked on
Working script is
find /home/test -mtime +5 -type f ! -size 0 | xargs grep -E -l '(abc_Pswd_[1-9])' | xargs -n1 sed -i '/abc_Pswd_[1-9].*/d'
I am trying to get the file name from 2nd part of the script I have tried few things
find /home/test -mtime +7 -type f ! -size 0 | xargs grep -E -l '(abc.1x.[1-9] )' > /home/test/tst.log| xargs -n1 sed -i '/abc_Pswd_[1-9].*/d'
This works in terms of logging the result but it exits with the error "sed: no input files"
Lets say I hit foo.html with find, i would like to pipe the contents back into foo.html
find . -iregex '.*\(html\|htm\)' -printf '%P\0' | \
xargs -0 sed -Ee "s:(http|https)\://(www.|)${domain}[?/]::g" \
> # to what? {\} ???
Right now it does not know what or where its
Pass the -i flag to sed, then it will modify the input file in place.
find . -iregex '.*html?' -printf '%P\0' | xargs -0 sed -i -Ee "s:(http|https)\://(www.|)${domain}[?/]::g"
I am writing a script that will saech for php files that contain a phrase and I would like that phrase replaced with a new one below is my little script but it is not working it searches ok but does not work with the search and replace section
find . -type f -name "*.php" -exec grep -H "define('DB_HOST', 'localhost');" {} \; | xargs sed -i "define('DB_HOST', 'localhost');/define('DB_HOST', '10.0.0.1');/g"
can someone explain to me what i am doing wrong
many thanks
Joe
did you forget the 's/' at the beggining of the sed expression? As in
sed 's/expression1/expression2/g'
You seem to have
sed 'espression1/expression2/g'
Edit
Another thing: You don't need to use xarg here. You can use multiple -exec flags - and it will to each only if all the previous succeeded:
find . -name '*.php' -exec grep 'whatever' {} \; -exec sed -i 's/whatever/you want/g' {} \;
This will work:
find . -type f -name "*.php" -exec grep -l "define('DB_HOST', 'localhost');" {} \; | xargs sed -i "s/define('DB_HOST', 'localhost');/define('DB_HOST', '10.0.0.1');/g"
Corrections
Missing s/ in sed search and replace command
use grep -l instead of grep -H
On my FTP server, I look for files delivered in the past day and remove in-place header & trailer records.
find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \;
This works well.
I want to automate this in a script. But how can I send myself an email notification is no files are found? I am thinking of doing something like:
find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \;
EXIT=`echo $?`
case $EXIT in
0) ...do stuff...
*) mail....exit
esac;;
There has to a better way, right?
I'm pretty sure that you could take whatever command you need to do the search, and pipe a wc -l on to the end of it. Then use an if statement to check for zero. So using your example above.
NUMLINES=`find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \ | wc -l`
if [ "$NUMLINES" -eq 0 ] ; then
foo
fi
Or something like that. I didn't check if that syntax is correct though. But i'm sure you get my drift
I have a bunch of image files that were incorrectly named 'something#x2.png' and they need to be 'something#2x.png'. They're spread across multiple directories like so:
/images
something#x2.png
/icons
icon#x2.png
/backgrounds
background#x2.png
How can I use grep + sed to find/replace as needed?
Ruby(1.9+)
$ ruby -e 'Dir["**/*#x2.png"].each{|x| File.rename( x, x.sub(/#x2/,"#2x") ) }'
Look at qmv and rename
find -iname '*.png' -print0 | xargs -0 qmv -d
will launch your default editor and allow you to interactively edit the names
rename s/#x2/#2x/ *.png
Slashes look linuxy/unixoid to me. Do you have find and rename?
find -name "*#x2*" -execdir rename 's/#x2/#2x/' {} +
rename is worth installing, comes in some perl-package.
With bash 2.x/3.x
#!/bin/bash
while IFS= read -r -d $'\0' file; do
echo mv "$file" "${file/#x2/#2x}"
done < <(find images/ -type f -name "something*#x2*.png" -print0)
With bash 4.x
#!/bin/bash
shopt -s globstar
for file in images/**; do
[[ "$file" == something*#x2*.png ]] && echo mv "$file" "${file/#x2/#2x}"
done
Note:
In each case I left in an echo so you can do a dry-run, remove the echo if the output is sufficient