Rather new to Mongodb/Mongoose/Node. Trying to make a query to retrieve the most recent posts (example being the 10 most recent posts) across all documents in a collection.
I tried querying this a few different ways.
MessageboardModel.find({"posts": {"time": {"$gte": ISODate("2014-07-02T00:00:00Z")}}} ...
I tried doing the above just to try getting to the proper nested time property, but everything I was trying throws an error. I'm definitely missing something here...
Here is an example document in the collection:
{
"_id": {
"$oid": "5c435d493dcf9281500cd177"
},
"movie": 433249,
"posts": [
{
"replies": [],
"_id": {
"$oid": "5c435d493dcf9281500cd142"
},
"username": "Username1",
"time": {
"$date": "2019-01-19T17:24:25.204Z"
},
"post": "This is a post title",
"content": "Content here."
},
{
"replies": [],
"_id": {
"$oid": "5c435d493dcf9281500cd123"
},
"username": "Username2",
"time": {
"$date": "2019-01-12T17:24:25.204Z"
},
"post": "This is another post made earlier",
"content": "Content here."
}
],
"__v": 0
}
There are many documents in the collection. I want to get, say the most recent 10 posts, across all of the documents in the entire collection.
Any help?
You can try using aggregation query:
Steps:
1> Match Specific doc
2> Stretch docs of its array using $unwind.
3> Sort using the time field from the posts.
4> Select fields , if specific fields needs to be shown.
5> Add limit, how many docs you want.
<YOUR_MODEL>.aggregate([
{$match:{
"movie": 433249 //you may add find conditions here, otherwise you can keep {} or remove $match from here
}},
{$unwind:"$posts"}, //this will make the each array element with different different docs.
{$sort:{"posts. time":1}}, // sort using the date field now, depends on your requirement use -1 /1
{$project:{posts:1}}, //select docs only from posts field. [u can remove if you want every element, or may modify]
{$limit:10} //you want only last 10 posts
]).exec();
let me know if you still having any issue or getting any error.
would love answer.
Related
I have a collection in MongoDB containing search history of a user where each document is stored like:
"_id": "user1"
searchHistory: {
"product1": [
{
"timestamp": 1623482432,
"query": {
"query": "chocolate",
"qty": 2
}
},
{
"timestamp": 1623481234,
"query": {
"query": "lindor",
"qty": 4
}
},
],
"product2": [
{
"timestamp": 1623473622,
"query": {
"query": "table",
"qty": 1
}
},
{
"timestamp": 1623438232,
"query": {
"query": "ike",
"qty": 1
}
},
]
}
Here _id of document acts like a foreign key to the user document in another collection.
I have backend running on nodejs and this function is used to store a new search history in the record.
exports.updateUserSearchCount = function (userId, productId, searchDetails) {
let addToSetData = {}
let key = `searchHistory.${productId}`
addToSetData[key] = { "timestamp": new Date().getTime(), "query": searchDetails }
return client.db("mydb").collection("userSearchHistory").updateOne({ "_id": userId }, { "$addToSet": addToSetData }, { upsert: true }, async (err, res) => {
})
}
Now, I want to get search history of a user based on query only using the db.find().
I want something like this:
db.find({"_id": "user1", "searchHistory.somewildcard.query": "some query"})
I need a wildcard which will replace ".somewildcard." to search in all products searched.
I saw a suggestion that we should store document like:
"_id": "user1"
searchHistory: [
{
"key": "product1",
"value": [
{
"timestamp": 1623482432,
"query": {
"query": "chocolate",
"qty": 2
}
}
]
}
]
However if I store document like this, then adding search history to existing document becomes a tideous and confusing task.
What should I do?
It's always a bad idea to save values are keys, for this exact reason you're facing. It heavily limits querying that field, obviously the trade off is that it makes updates much easier.
I personally recommend you do not save these searches in nested form at all, this will cause you scaling issues quite quickly, assuming these fields are indexed you will start seeing performance issues when the arrays get's too large ( few hundred searches ).
So my personal recommendation is for you to save it in a new collection like so:
{
"user_id": "1",
"key": "product1",
"timestamp": 1623482432,
"query": {
"query": "chocolate",
"qty": 2
}
}
Now querying a specific user or a specific product or even a query substring is all very easily supported by creating some basic indexes. an "update" in this case would just be to insert a new document which is also much faster.
If you still prefer to keep the nested structure, then I recommend you do switch to the recommended structure you posted, as you mentioned updates will become slightly more tedious, but you can still do it quite easily using arrayFilters for updating a specific element or just using $push for adding a new search
I am beginner in MongoDB and struck at a place I am trying to fetch data from nested array but is it taking so long time as data is around 50K data, also it is not much accurate data, below is schema structure please see once -
{
"_id": {
"$oid": "6001df3312ac8b33c9d26b86"
},
"City": "Los Angeles",
"State":"California",
"Details": [
{
"Name": "Shawn",
"age": "55",
"Gender": "Male",
"profession": " A science teacher with STEM",
"inDate": "2021-01-15 23:12:17",
"Cars": [
"BMW","Ford","Opel"
],
"language": "English"
},
{
"Name": "Nicole",
"age": "21",
"Gender": "Female",
"profession": "Law student",
"inDate": "2021-01-16 13:45:00",
"Cars": [
"Opel"
],
"language": "English"
}
],
"date": "2021-01-16"
}
Here I am trying to filter date with date and Details.Cars like
db.getCollection('news').find({"Details.Cars":"BMW","date":"2021-01-16"}
it is returning details of other persons too which do not have cars- BMW , Only trying to display details of person like - Shawn which have BMW or special array value and date too not - Nicole, rest should not appear but is it not happening.
Any help is appreciated. :)
A combination of $match on the top-level fields and $filter on the array elements will do what you seek.
db.foo.aggregate([
{$match: {"date":"2021-01-16"}}
,{$addFields: {"Details": {$filter: {
input: "$Details",
as: "zz",
cond: { $in: ['BMW','$$zz.Cars'] }
}}
}}
,{$match: {$expr: { $gt:[{$size:"$Details"},0] } }}
]);
Notes:
$unwind is overly expensive for what is needed here and it likely means "reassembling" the data shape later.
We use $addFields where the new field to add (Details) already exists. This effectively means "overwrite in place" and is a common idiom when filtering an array.
The second $match will eliminate docs where the date matches but not a single entry in Details.Cars is a BMW i.e. the array has been filtered down to zero length. Sometimes you want to know this info so if this is the case, do not add the final $match.
I recommend you look into using real dates i.e. ISODate instead of strings so that you can easily take advantage of MongoDB date math and date formatting functions.
Is a common mistake think that find({nested.array:value}) will return only the nested object but actually, this query return the whole object which has a nested object with desired value.
The query is returning the whole document where value BMW exists in the array Details.Cars. So, Nicole is returned too.
To solve this problem:
To get multiple elements that match the criteria you can do an aggregation stage using $unwind to separate the different objects into array and match by the criteria you want.
db.collection.aggregate([
{
"$match": { "Details.Cars": "BMW", "date": "2021-01-26" }
},
{
"$unwind": "$Details"
},
{
"$match": { "Details.Cars": "BMW" }
}
])
This query first match by the criteria to avoid $unwind over all collection.
Then $unwind to get every document and $match again to get only the documents you want.
Example here
To get only one element (for example, if you match by _id and its unique) you can use $elemMatch in this way:
db.collection.find({
"Details.Cars": "BMW",
"date": "2021-01-16"
},
{
"Details": {
"$elemMatch": {
"Cars": "BMW"
}
}
})
Example here
You can use $elemenMatch into query or projection stage. Docs here and here
Using $elemMatch into query the way is this:
db.collection.find({
"Details": {
"$elemMatch": {
"Cars": "BMW"
}
},
"date": "2021-01-16"
},
{
"Details.$": 1
})
Example here
The result is the same. In the second case you are using positional operator to return, as docs says:
The first element that matches the query condition on the array.
That is, the first element where "Cars": "BMW".
You can choose the way you want.
I have two collection, there name are post and comment.
The model structure is in the following.
I want to use aggregation query post and sort by comments like length sum, currently I can query a post comments like length sum in the following query statement.
My question is how can I query post and join comment collection in Mongo version 2.6. I know after Mongo 3.2 have a lookup function.
I want to query post collection and sort by foreign comments likes length. Is it have a best way to do this in mongo 2.6?
post
{
"_id": ObjectId("5a39e22c27308912334b4567"),
"uid": "0",
"content": "what is hello world mean?",
}
comment
/* 1 */
{
"_id": ObjectId("5a595d8c2703892c3d8b4567"),
"uid": "1",
"post_id": "5a39e22c27308912334b4567",
"comment": "hello world",
"like": [
"2"
]
}
/* 2 */
{
"_id": ObjectId("5a595d8c2703892c3d8b4512"),
"uid": "2",
"post_id": "5a39e22c27308912334b4567",
"comment": "hello stackoverflow",
"like": [
"1",
"2"
]
}
Query a post comments like sum
db.getCollection('comment').aggregate([
{
"$match": {
post_id: "5a39e22c27308912334b4567"
}
},
{
"$project": {
"likeLength": {
"$size": "$like"
},
"post_id": "$post_id"
}
},
{
"$group": {
_id: "$post_id",
"likeLengthSum": {
"$sum": "$likeLength"
}
}
}
])
There is no "best" way to query, as it'll really depend on your specific needs, but... you cannot perform a single query across multiple collections (aside from the $lookup aggregation pipeline function in later versions, as you already are aware).
You'll need to make multiple queries: one to your post collection, and one to your comment collection.
If you must perform a single query, then consider storing both types of documents in a single collection (with some identifier property to let you filter on either posts or comments, within your query).
There is no other way to join collections in the current MongoDB v6 without $lookup,
I can predict two reasons that causing you the issues,
The $lookup is slow and expensive - How to improve performance?
$lookup optimization:
Follow the guideline provided in the documentation
Use indexs:
You can use the index on the reference collection's fields, as per your sample data you can create an index for post_id field, an index for uid field, or a compound index for both the fields on the basis of your use cases
You can read more about How to Improve Performance with Indexes and Document Filters
db.comment.createIndex({ "post_id": -1 });
db.comment.createIndex({ "uid": -1 });
// or
db.comment.createIndex({ "post_id": -1, "uid": -1 });
Document Filters:
Use the $match, $limit, and $skip stages to restrict the documents that enter the pipeline
You can refer to the documentation for more detailed examples
{ $skip: 0 },
{ $limit: 10 } // as per your use case
Limit the $lookup result:
Try to limit the result of lookup by $limit stage,
Try to coordinate or balance with improved query and the UI/Use cases
You want to avoid $lookup - How to improve the collection schema to avoid $lookup?
Store the analytics/metrics:
If you are trying to get the total counts of the comments in a particular post then you must store the total count in the post collection whenever you get post get a new comment
{
"_id": ObjectId("5a39e22c27308912334b4567"),
"uid": "0",
"content": "what is hello world mean?",
// new fields
"total_comments": 10
}
Store minimum reference data:
If you want to show the comments of a particular post, you can limit the result for ex: show 5 comments per post
You can also store a max of 5 latest comments in the post collection to avoid the $lookup, whenever you get the latest comment then add it and just remove the oldest comment from 5 comments
{
"_id": ObjectId("5a39e22c27308912334b4567"),
"uid": "0",
"content": "what is hello world mean?",
// new fields
"total_comments": 10,
"comments": [
{
"_id": ObjectId("5a595d8c2703892c3d8b4567"),
"uid": "1",
"comment": "hello world"
},
{
"_id": ObjectId("5a595d8c2703892c3d8b4512"),
"uid": "2",
"comment": "hello stackoverflow"
}
]
}
Must read about Reduce $lookup Operations
Must read about Improve Your Schema
We have a mongodb document as given below, and we configured text index on messageTopic, messageTopicQuestion and answer fields, if i search with a text string then I expect only matched embedded records in the results not the entire document.
For example in below document if i search with word "private", then results should only return the first embedded document not both the records. How to retrieve only matched embedded documents and exclude unmatched ones.
{
"_id": ObjectId("586e8efdde81e56032000084"),
"messageTopic": "My Private",
"messageText": [{
"messageTopicQuestion": "agent private",
"answer": "agent private",
"_id": ObjectId("586e8efdde81e56032000085"),
"keywords": ["private"]
}, {
"messageTopicQuestion": "Greetings Checking",
"answer": "Heloo I am good What about u",
"_id": ObjectId("586fc80ccced739407000f4e"),
"keywords": ["Hi-Good", "Heloo"]
}],
"__v": 3
}
I am using below script
db.getCollection('messagetemplates').aggregate([{
$match: {
$text: {$search: 'private'},
visible: 'PUB'
}
},{ $sort: { score: { $meta: "textScore" } } }])
Appreciate help. Thanks.
I believe the question is a variation of this problem How to get a specific embedded document inside a MongoDB collection?
The issue is how to get the single embedded document and exclude the rest. My suggestion is to use db.collection.find() instead of aggregation.
Something in that sense
db.collection.find({ 'messageText.keyword': 'private' }, {'messageText.$': 1});
, as indicated by the answer above.
messageText.keyword can be replaced with whichever field you want to be searched.
I can confirm that the scenario works on my database.
I'm trying to sort this in MongoDB with mongojs on a find():
{
"songs": {
"bNppHOYIgRE": {
"id": "bNppHOYIgRE",
"title": "Kygo - ID (Ultra Music Festival Anthem)",
"votes": 1,
"added": 1428514707,
"guids": [
"MzM3NTUx"
]
},
"izJzdDPH9yw": {
"id": "izJzdDPH9yw",
"title": "Benjamin Francis Leftwich - Atlas Hands (Samuraii Edit)",
"votes": 1,
"added": 1428514740,
"guids": [
"MzM3NTUx"
]
},
"Yifz3X_i-F8": {
"id": "Yifz3X_i-F8",
"title": "M83 - Wait (Kygo Remix)",
"votes": 0,
"added": 1428494338,
"guids": []
},
"nDopn_p2wk4": {
"id": "nDopn_p2wk4",
"title": "Syn Cole - Miami 82 (Kygo Remix)",
"votes": 0,
"added": 1428494993,
"guids": []
}
}
}
and I want to sort the keys in the songs on votes ascending and added descending.
I have tried
db.collection(coll).find().sort({votes:1}, function(err, docs) {});
but that doesn't work.
If this is an operation that you're going to be doing often, I would strongly consider changing your schema. If you make songs an array instead of a map, then you can perform this query using aggregation.
db.coll.aggregate([{ "$unwind": "$songs" }, { "$sort": { "songs.votes": 1, "songs.added": -1 }}]);
And if you put each of these songs in a separate songs collection, then you could perform the query with a simple find() and sort().
db.songs.find().sort({ "votes": 1, "added": -1 });
With your current schema, however, all of this logic would need to be in your application and it would get messy. A possible solution would be to get all of the documents and while iterating through the cursor, for each document, iterate through the keys, adding them to an array. Once you have all of the subdocuments in the array, sorting the array according to votes and added.
It is possible, but unnecessarily complex. And, of course, you wouldn't be able to take advantage of indexes, which would have an impact on your performance.
You already include the key inside the subdocument, so I would really recommend you reconsider your schema.