Querying a table and one of the filters I want to use is a date between i.e. 02/08/19 and 02/10/19. For whatever reason the table I was working with for this filter has a Varchar(50) column made to look like a DateTime 120 style (yyyy-dd-mm hh:mm:ss.fff). How do I convert this to a Date (mm/dd/yy) format? If it were a real DateTime I would typically just cast it As Date.
So far I've tried:
select convert(varchar(50), a.alpha, 1), a.bravo, sum(a.charlie)
from table a
where convert(varchar(50), a.alpha, 1) between '02/08/19' and '02/10/19'
group by convert(varchar(50), a.alpha, 1), a.bravo
order by sum(a.charlie)
This doesn't seem to pull any records. I then switched it to 120 instead of 1 and switched the filters to '2019-02-08 00:00:00.000' and '2019-02-10 00:00:00.000' and it worked, but this isn't the format I need. I tried casting these converts as date i.e. cast(convert(varchar(50), a.alpha, 1) as date) and that didn't work either.
What should I do now?
Thanks,
You're trying to convert a varchar to a varchar while you should do it to a date. Even in that case, conversion will fail so you can do the conversion twice to let it filter with no error. This should work for you:
SELECT CONVERT(CONVERT(date, a.alpha),1), a.bravo, sum(a.charlie)
FROM table a
WHERE CONVERT(CONVERT(date, a.alpha),1) BETWEEN '02/08/19' and '02/10/19'
GROUP BY convert(convert(date, a.alpha),1) , a.bravo
ORDER BY sum(a.charlie)
Related
The column is a nvachar(20).
select [shipment_posted_date_arch]
FROM [RxIntegrity].[dbo].[DiscrepancyReport_Receipts]
When I pull this, the date is in this format of 1200819 for that column. I need to convert to normal date.
This seemed to work:
cast(convert(nvarchar(20), (19000000 + CONVERT(int, shipment_posted_date_arch))) as date)
Below is a script i am trying to run in Presto; Subtracting today's date from an integer field I am attempting to convert to date. To get the exacts days between. Unfortunately, it seems the highlighted block does not always convert the date correctly and my final answer is not correct. Please does anyone know another way around this or a standard method on presto of converting integer values to date.
Interger value in the column is in the format '20191123' for year-month-date
select ms, activ_dt, current_date, date_diff('day',act_dt,current_date) from
(
select ms,activ_dt, **CAST(parse_datetime(CAST(activ_dt AS varchar), 'YYYYMMDD') AS date) as act_dt**, nov19
from h.A_Subs_1 where msisdn_key=23480320012
) limit 19
You can convert "date as a number" (eg. 20180527 for May 27, 2018) using the following:
cast to varchar
parse_datetime with appropriate format
cast to date (since parse_datetime returns a timestamp)
Example:
presto> SELECT CAST(parse_datetime(CAST(20180527 AS varchar), 'yyyyMMdd') AS date);
_col0
------------
2018-05-27
You can use below sample query for your requirement:
select date_diff('day', date_parse('20191209', '%Y%m%d'), current_timestamp);
I have the following mysqli query in my search.php file with ajax.
SELECT demand2.* FROM demand2
WHERE ddate >= '$dto' AND ddate >= '$dfrom' AND !(mach='--' OR mach='-' OR mach='' OR mach='----' OR mach='-----' OR mach='---');
field ddate is datatype of varchar2
as I entered Date From 01-01-2019 and Date To 30-01-2019, it shows the result with previous date like 29-12-2019.
So I can't find the solution to get result within specified range. Please Help.
Just as rypskar said, your type of field should be date.
If you don't want to change the datatype of the fiels, then you have to convert the string to date with STR_TO_DATE(ddate, '%d-%m-%Y'). But this is not recommended, as it will cause performance degradation on larger tables.
So your query would be like that (not tested!):
SELECT demand2.* FROM demand2
WHERE STR_TO_DATE(ddate, '%d-%m-%Y') >= STR_TO_DATE('$dto', '%d-%m-%Y') AND STR_TO_DATE(ddate, '%d-%m-%Y') >= STR_TO_DATE('$dfrom', '%d-%m-%Y') AND !(mach='--' OR mach='-' OR mach='' OR mach='----' OR mach='-----' OR mach='---');
If you want to keep the varchar type of field and not make any runtime conversions, then you have to change the format to Y-m-d, so the comparison with character set will work the same as a date comparison.
Right now, you are getting the result of 29-12-2019 because 29 is between 1 and 30.
I'm trying to select records from a DB2 Iseries system where the date field is greater than the first of this year.
However, the date fields I'm selecting from are actually PACKED fields, not true dates.
I'm trying to convert them to YYYY-MM-DD format and get everything greater than '2018-01-01' but no matter what I try it says it's invalid.
Currently trying this:
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYY-MM-DD') >= '2018-01-01';
it says expression not valid using format string specified.
Any ideas?
char(dateshp) is going to return a string like '20180319'
So your format string should not include the dashes.. 'YYYYMMDD'
example:
select to_date(char(20180101), 'YYYYMMDD')
from sysibm.sysdummy1;
So your code should be
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYYMMDD') >= '2018-01-01';
Charles gave you a solution that converts the Packed date to a date field, and if you are comparing to another date field, this is a good solution. But if you are comparing to a constant value or another numeric field, you could just use something like this:
select *
from table1
where val = 145
and dateShp >= 20180101;
I'm trying to convert value for DIM_DT_ID to MMddYY. I'm successful in doinf that. However, query fails because ultimately I'm comparing a character value to date here. Is there a way by which I can get value for DIM_DT_ID in MMddyy format and its data type still remains DATE ?
Here DIM_DT_ID
SELECT DIM_DT_ID
DIM_DT_ID >= FORMATDATE('MMddyy',ADDDAY(TO_date('yyyy-MM-dd','2016-12-21'), -25)); from abc;
Regards,
Ajay
In Denodo, to convert a string to a date field, use "to_date()" (which returns a date).
Then, don't convert back to a string, leave that field as a date (so don't use "Formatdate()", which returns a string).
So:
SELECT *
FROM MyTable
WHERE now() >= to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate)
In my example, "now()" is a date, and so is the output of the to_date function... so you can do a comparison.
If you try to convert the date back to a string using formatdate, it won't work:
#This doesn't work:
SELECT *
FROM MyTable
WHERE now() >= formatdate('MMddyy',to_date('yyyy-MM-dd',myStringFieldThatLooksLikeADate))
It doesn't work because we are comparing a date ("now()") to a string.