I've been struggling to deploy my shiny app using the tesseractpackage. It seems that it can't 'reach' the downloaded languages. In my case: English and Dutch.
When setting up the language, the resulting object should 'point' to a path. That's the part where shiny can't open the connection.
Any help would be much appriciated!
Kind regards, R
Below I've copied the error message and the relevant code.
This is the error message I get after deployment:
Warning in file(con, "wb") :
cannot open file '/usr/share/tesseract-ocr/tessdata/nld.traineddata': Permission denied
Error in value[3L] : cannot open the connection
Calls: local ... tryCatch -> tryCatchList -> tryCatchOne ->
Execution halted
This is my code
#loading software requirement
library(tesseract)
#download language (dutch)
tesseract_download('nld')
tesseract_download('eng')
#set language parameters for later use.
dutch <- tesseract('nld')
english <- tesseract('eng')
I've managed to get it working myself. The key was taking the following steps:
Creating a subdirectory (of folder) which is called 'tessdata'. This subdirecty is the directory you can download the languages in and 'set' the languages.
When deploying your app, you have to deploy this tessdata-subdirectory as well. So in the deployement prompt, you 'tick' the boxes of this folder as well.
Then make sure the tesseract engine points at the following path:
Screenshot of how to upload the tessdata-folder along with the app
enter image description here
Please see the code below
#loading software requirementlibrary(tesseract)
#Make sure the tesseract package is 'pointing' at the right 'parent directory'
#which is in this case the path your shiny app is working from.
#That's why you need the dot ("."). Which is in essence the workdir.
Sys.setenv(TESSDAT_PREFIX = ".")
#so combining the workdir and the pre-installed folder 'tessdata'
path <- paste0(getwd(), '/tessdata')
#use this path for downloading
#download languages (dutch and english)
tesseract_download('nld', datapath = path)
tesseract_download('eng', datapath = path)
#set language parameters for later use, using the same path
dutch <- tesseract('nld', datapath = path)
english <- tesseract('eng', datapath = path)
Related
Currently I am working a project that has have been using the pathlib library so I can work on my Windows desktop when I need too and on my MacBook Pro. Essentially be able to work between both operating systems. I have not have any issues at all until right now. Here is the set up:
I have a pipeline set up to automatically save a .joblib and a whole lot of .png files that will go to a directory called
output_dir = Path('../Trained_Models/Differential_gene_analysis/A Kidney Cancer Transcriptome Molecular Signature Identifies Tumors with Tumor Thrombus/Models train on TCGA data and test on Rodriguez data/Oct-XX-20XX')
For example, if I want to save a .joblib file under the name RandomForest_TumorThrombus_104.joblib,I would use the command
joblib.dump(model ,output_dir / 'RandomForest_TumorThrombus_104.joblib')
On my MacBook Pro, I have no issues when this is ran, but on Windows it gives me the following error
FileNotFoundError: [Errno 2] No such file or directory: '..\\Trained_Models\\Differential_gene_analysis\\A Kidney Cancer Transcriptome Molecular Signature Identifies Tumors with Tumor Thrombus\\Models train on TCGA data and test on Rodriguez data\\Oct-17-2022\\RandomForest_TumorThrombus_104.joblib'
I have tried to use the .resolve() method to get the absolute path but still gives me the same error. I have tried to experiment to try to see what is goin on such as using os.path.exists(). When using the os.path.exists() method I get True for the follwoing command:
os.path.exists(output_dir)
So it does indeed recognize that the directory exists. The next thing I tried was to rename the file to something like dddddd.joblib and that worked. But I find that only a few names for the file would allow me to save the files. During debug I found that the most recent Traceback occurs here:
with open(filename, 'wb') as f:```
I was wondering if anyone here had any idea what was going on here and how I can fix this issue? Please and Thank you.
The solution was to enable long paths on Windows.
I have a web.py server hosted on pythonanywhere.com doing some handy things with python.
Now I'd like to just serve a straightforward html file from the same server i.e. just return the contents of a static html file to the client
The comments/answers below state that it should be possible, out of the box, to serve static files in the static directory, located in the same directory as the main python file which contains the following :
import web
urls = (
'/', 'hello'
)
app = web.application(urls, globals())
class hello:
def GET(self):
return 'Hello, Joe'
if __name__ == "__main__":
app.run()
The server above works fine, when I go to http://myhost/ it displays "Hello , Joe".
The directory static exists and contains a file small.jpg but when I try the url http://myhost/static/small.jpg it gives me "not found"
Previous text of question up to Nov 9th 2022 is below :
original question title : Trying to return a html file in web.py but getting "No template named ....." error message
So I've looked at the web.py documentation on serving static files and templating and I think the following code should work :
import web
render = web.template.render('static/')
# have also tried render = web.template.render('/full/path/to/static/')
urls = (
'/getlatlongEIRCODE', 'getlatlongEIRCODE', #other stuff
'/getlatlongGOOGLE', 'getlatlongGOOGLE', #other stuff
'/getmonthlyPV', 'getmonthlyPV', #other stuff
'/Tomas', 'Tomas',
)
class Tomas:
def GET(self):
return render.Tomas()
I have created a folder static at the same level as my file above (which works fine for the other scripts) and i have created a file Tomas.html in the static folder containing
<h1>Help me</h1>
However I get an error message when I go to https://example.com/Tomas
<class 'AttributeError'> at /Tomas
No template named Tomas
P.S. From the static files page it seems to say I should just be able to put the Tomas.html file in a folder called "static" and then access is via https://example.com/static/Tomas.html but that is not working (it returns "not found")
You're using a relative path to your template directory without paying attention to the working directory. See https://help.pythonanywhere.com/pages/NoSuchFileOrDirectory/
You're working too hard. 'static' is built in.
As the documentation says, http://localhost/static/logo.png will return the file logo.png from the existing directory static, which is relative to your webserver root.
Do not use render() for this (not needed). Also, do not list your desired file ('/Tomas') in the urls list (not needed).
Anything under the static directory can be accessed with the url https://localhost/static/...
"static" is hardcoded in the web.py server, so you cannot (easily) change this to some other folder. The suggestion in the web.py documents is to have nginx or apache host your application and use an Alias there to go to web.py static. (I think you can also add StaticMiddleware to your web.py application, but you'd need to investigate that yourself -- look at web.application.run()
The case of the disappearing /static/ directory was related to the fact that I'm hosting on pythonanywhere.com
Even though the web.py documentation says that the /static/ folder is plugged in by default, that's not the case in pythonanywhere and you need to expressly make the link between the url http://yourhost/static/ and /path/to/static in the Web part of the dashboard.
Hello i have one more problem with deploying my app by Streamlit. It works localy but when I want to upload it on git hub it doesnt work..Have no idea whats wrong. It seems that there is problem with path to the file:
"File "/app/streamlit/bobrza.py", line 14, in <module>
bobrza_locations = pd.read_csv(location)"
Here is link to my github repo. Will be very very grateful for help. Thank in advance.
https://github.com/Bordonous/streamlit
The problem is you are hard coding the path of the bobrza1.csv and route.csv to the path on your computer so when running the code on a different environment the path in not legal.
The solution is to make location independent from running environment, for this we will use the following:
__file__ variable - the path to the current python module (the .py file).
os.path.dirname() - a function to get directory name from path.
os.path.abspath() - a function to get a normalized absolutized version of path.
os.path.join() - a function to join one or more path components.
Now you need to change your location and location2 variables in the code to the following:
# get the absolute path to the directory contain the .csv file
dir_name = os.path.abspath(os.path.dirname(__file__))
# join the bobrza1.csv to directory to get file path
location = os.path.join(dir_name, 'bobrza1.csv')
# join the route.csv to directory to get file path
location2 = os.path.join(dir_name, 'route.csv')
Resulting in an independent path of the bobrza1.csv and route.csv.
I tried to train the tesseract 4.1 using OCRD project but after training completed I copied the lang.traineddata but getting above error.
The tesseractWiki page is very confusing to understand asking to use combine_lang_model after making lstmf file. So Actually I have the lstmf file. I created these file by using tif/box pair.
Please help me for further step.
Related discussions：Failed to load any lstm-specific dictionaries for lang xxx
Suppose your training folder like this:
OCRD/makefile
OCRD/data/foo-ground-truth.
You could try as following steps:
Find the WORDLIST_FILE/NUMBERS_FILE/PUNC_FILE in the makefile, and change them to:
WORDLIST_FILE := data/$(MODEL_NAME).wordlist
NUMBERS_FILE := data/$(MODEL_NAME).numbers
PUNC_FILE := data/$(MODEL_NAME).punc
Suppose your base traineddata is eng.traineddata.
2.1 Download the .wordlist/.numbers/.punc files from the langdata_lstm.
2.2 Place them in OCRD/data
2.3 if the MODEL_NAME = foo, rename them as: foo.wordlist, foo.numbers, foo.punc
if you don't have the base traineddata, you could try this too. But if your base traineddata is afr, you should download the files from langdata_lstm/afr.
make training again
The cause of this error：
In OCRD, the default path of the above three files is $ (OUTPUT_DIR) = data / $ (MODEL_NAME), and all files in this path are automatically generated during the training process.
If the variable START_MODEL is not assigned, the makefile will not generate any related files under this path;
If the variable START_MODEL has been assigned, the foo.lstm-number-dawg、foo.lstm-punc-dawg、foo.lstm-word-dawg and so on will be produced in data / $ (MODEL_NAME). But they are not the right one. So there may be a bug in OCRD.
I need to write a program where I run a set of instructions and create a file in a directory. Once the file is created, when the same code block is run again, it should not run the same set of instructions since it has already been executed before, here the file is used as a guard.
var Directory: String = "Dir1"
var dir: File = new File("Directory");
dir.mkdir();
var FileName: String = Directory + File.separator + "samplefile" + ".log"
val FileObj: File = new File(FileName)
if(!FileObj.exists())
// blahblah
else
{
// set of instructions to create the file
}
When the programs runs initially, the file won't be present, so it should run the set of instructions in else and also create the file, and after the first run, the second run it should exit since the file exists.
The problem is that I do not understand new File, and when the file is created? Should I use file.CreateNewFile? Also, how to write this in functional style using case?
It's important to understand that a java.io.File is not a physical file on the file system, but a representation of a pathname -- per the javadoc: "An abstract representation of file and directory pathnames". So new File(...) has nothing to do with creating an actual file - you are just defining a pathname, which may or may not correspond to an existing file.
To create an empty file, you can use:
val file = new File("filepath/filename")
file.createNewFile();
If running on JRE 7 or higher, you can use the new java.nio.file API:
val path = Paths.get("filepath/filename")
Files.createFile(path)
If you're not happy with the default IO APIs, you an consider a number of alternative. Scala-specific ones that I know of are:
scala-io
rapture.io
Or you can use libraries from the Java world, such as Google Guava or Apache Commons IO.
Edit: One thing I did not consider initially: I understood "creating a file" as "creating an empty file"; but if you intend to write something immediately in the file, you generally don't need to create an empty file first.