Using a where clause in a combination with a subquery which result is a record containin an array - postgresql

Question

I found some results/answers, regarding searching in array, but:
WHERE = ANY, works with a column, but not with a subquery that returns one record that contains an array as a result, triggers error
WHERE IN, also triggers the same error
I also tested untest on the subquery, similar error as the first 2
I don't want to check if a value is in an array but get/execute the query for the values in the array, like WHERE IN (1,2,3,4), not like in the other questions/answers
The error:
No operator matches the given name and argument types. You might need
to add explicit type casts.
or
No operator matches int = int[]
path is an int[]array type.
Structure:
id | name | | slug | path | parent_id
1 name1 slug1 {1} null
2 name2 slug2 {1,2} 1
3 name3 slug3 {1,2,3} 2
4 nam4 slug4 {4} null
What I tries as base:
SELECT t.id, t.name, t.slug FROM types AS t
WHERE t.id in (SELECT t.path FROM types AS t WHERE t.id = 24)
ORDER BY depth ASC
Basically path is like a breadcrumb , {grandparent,parent,type}

Answer 1

Here's one using IN and unnest()
SELECT t1.id,
t1."name",
t1.slug
FROM types t1
WHERE t1.id IN (SELECT un.e
FROM types t2
CROSS JOIN LATERAL unnest(t2.path) un (e)
WHERE t2.id = 2)
ORDER BY array_length(t1.path, 1);
And another one using the array is contained by operator <#.
SELECT t1.id,
t1."name",
t1.slug
FROM types t1
WHERE ARRAY[t1.id] <# (SELECT t2.path
FROM types t2
WHERE t2.id = 2)
ORDER BY array_length(t1.path, 1);
And one using = ANY.
SELECT t1.id,
t1."name",
t1.slug
FROM types t1
WHERE t1.id = ANY ((SELECT t2.path
FROM types t2
WHERE t2.id = 2)::integer[])
ORDER BY array_length(t1.path, 1);
db<>fiddle
You didn't include depth in your sample data so I replaced it with array_length(t1.path, 1) which is probably what it is.