How to extract efficiently multiple columns from a single string column RDD? - scala

Question

I have a file with 20+ columns of which I would like to extract a few. Until now, I have the following code. I'm sure there is a smart way to do it, but not able to get it working successfully. Any ideas?
mvnmdata is of type RDD[String]
val strpcols = mvnmdata.map(x => x.split('|')).map(x => (x(0),x(1),x(5),x(6),x(7),x(8),x(9),x(10),x(11),x(12),x(13),x(14),x(15),x(16),x(17),x(18),x(19),x(20),x(21),x(22),x(23) ))```

Answer 1

The next solution provides an easy and scalable way to manage your column names and indices. It is based on a map which determines the column name/index relation. The map will also help us to handle both the index of the extracted column and its name.
import org.apache.spark.sql.Row
import org.apache.spark.sql.types.{StringType, StructType, StructField}
val rdd = spark.sparkContext.parallelize(Seq(
"1|500|400|300",
"1|34|67|89",
"2|10|20|56",
"3|2|5|56",
"3|1|8|22"))
val dictColums = Map("c0" -> 0, "c2" -> 2)
// create schema from map keys
val schema = StructType(dictColums.keys.toSeq.map(StructField(_, StringType, true)))
val mappedRDD = rdd.map{line => line.split('|')}
.map{
cols => Row.fromSeq(dictColums.values.toSeq.map{cols(_)})
}
val df = spark.createDataFrame(mappedRDD, schema).show
//output
+---+---+
| c0| c2|
+---+---+
| 1|400|
| 1| 67|
| 2| 20|
| 3| 5|
| 3| 8|
+---+---+
First we declare dictColums in this example we will extract the cols "c0" -> 0 and "c2" -> 2
Next we create the schema from the keys of the map
The one map (which you already have) will split the line by |, the second one will create a Row containing the values that correspond to each item of dictColums.values
UPDATE:
You could also create a function from the above functionality in order to be able to reuse it multiple times:
import org.apache.spark.sql.DataFrame
def stringRddToDataFrame(colsMapping: Map[String, Int], rdd: RDD[String]) : DataFrame = {
val schema = StructType(colsMapping.keys.toSeq.map(StructField(_, StringType, true)))
val mappedRDD = rdd.map{line => line.split('|')}
.map{
cols => Row.fromSeq(colsMapping.values.toSeq.map{cols(_)})
}
spark.createDataFrame(mappedRDD, schema)
}
And then use it for your case:
val cols = Map("c0" -> 0, "c1" -> 1, "c5" -> 5, ... "c23" -> 23)
val df = stringRddToDataFrame(cols, rdd)

Answer 2

As below,if you don't want to write repeated x(i),you can process it in a loop. Example 1:
val strpcols = mvnmdata.map(x => x.split('|'))
.map(x =>{
val xbuffer = new ArrayBuffer[String]()
for (i <- Array(0,1,5,6...)){
xbuffer.append(x(i))
}
xbuffer
})
If you only want to define the index list with start&end and the numbers to be excluded, see Example 2 of below:
scala> (1 to 10).toSet
res8: scala.collection.immutable.Set[Int] = Set(5, 10, 1, 6, 9, 2, 7, 3, 8, 4)
scala> ((1 to 10).toSet -- Set(2,9)).toArray.sortBy(row=>row)
res9: Array[Int] = Array(1, 3, 4, 5, 6, 7, 8, 10)
The final code you want:
//define the function to process indexes
def getSpecIndexes(start:Int, end:Int, removedValueSet:Set[Int]):Array[Int] = {
((start to end).toSet -- removedValueSet).toArray.sortBy(row=>row)
}
val strpcols = mvnmdata.map(x => x.split('|'))
.map(x =>{
val xbuffer = new ArrayBuffer[String]()
//call the function
for (i <- getSpecIndexes(0,100,Set(3,4,5,6))){
xbuffer.append(x(i))
}
xbuffer
})