Am trying to create a Query that either matches all rows that equal tier or are NULL. Using Query Methods as described in Spring JPA Docs. The Default implementation below works if I just pass in the tier:-
#Entity
#Table(name = "tier")
class UuTier {
Long id;
Long tierId;
}
#Entity
#Table(name = "user")
class User {
#OneToOne
#JoinColumn(name="tier_id")
UuTier uuTier;
// Other Relationships
}
public interface UserRepository extends Repository<User, Long> {
List<User> findByTier_Id(#Param("tier")Long tier);
}
What I need is something like this, which is throwing an error " No property null found for type User". Can I achieve this ask using Query Methods?:-
public interface UserRepository extends Repository<User, Long> {
List<User> findByTierOrNull_Id(#Param("tier")String tier);
}
Following up from one of the responders (who for some reason deleted her post) - I got this to work!!
#Query("SELECT entity FROM User entity LEFT JOIN UuTier uuTier ON entity.uuTier.tier = uuTier.tier"
+ " WHERE entity.uuTier.tier = :tier OR entity.uuTier.tier IS NULL")
public List<User> findByTierOrNull_Id(#Param("tier") Long tier);
I need help to get the data from another document I have the following class.
#Data
#Document(collection = "tmVersion")
public class TmVersion {
#Id
private String id;
private String cVrVersionId;
#DBRef
private TaApplicationVersion taApplicationVersion;
}
and
#Data
#Document(collection = "taApplicationVersion")
public class TaApplicationVersion {
#Id
private String id;
private String dVrAppName;
private String dVrAppCode;
}
This is my repository in which I map what I want to be shown but in taApplicationVersion I need to show all this object also how is it done?
#Query(value="{}", fields="{'cVrVersionId': 1, 'taApplicationVersion.dVrAppName': 2,
'dVrVersionNumber': 3}")
Page<TmVersion> getAllVersionWithOutFile(Pageable pageable)
Couple of things to mention here.
If you want this kind of join between tables, then you need to rethink your choice of Mongodb as database. No Sql Databases thrive on the fact that there is very less coupling between tables(collections). So if you are using #DBRef, it negates that. Mongodb themselves do not recommend using #DBRef.
This cannot be achieved with the method like you have in the repository. You need to use Projections. Here is the documentation for that.
Create a Porjection interface like this. Here you can control which fields you need to include in the Main class(TmVersion)
#ProjectedPayload
public interface TmVersionProjection {
#Value("#{#taApplicationVersionRepository.findById(target.taApplicationVersion.id)}")
public TaApplicationVersion getTaApplicationVersion();
public String getId();
public String getcVrVersionId();
}
Change the TmVersionRepository like this
public interface TmVersionRepository extends MongoRepository<TmVersion, String> {
#Query(value="{}")
Page<TmVersionProjection> getAllVersionWithOutFile(Pageable pageable);
}
Create a new Repository for TaApplicationVersion. You can add #Query on top of this method and control which fields from subclass needs to be returned.
public interface TaApplicationVersionRepository extends MongoRepository<TaApplicationVersion, String> {
TaApplicationVersion findById(String id);
}
The model is simplified for the question.
I have this entity:
#Entity
public class Formation {
#Id
Long id;
String login;
String code;
String level;
// geters and Setters
With this repository:
public interface FormationRepository extends JpaRepository<Formation, Long> {
#Query(value = "SELECT UNIQUE l.id, l.login, d.code,d.level\n"
" FROM table_login l,\n" +
" table_diploma d,\n" +
" WHERE
" l.fhab_key = d.fhab_key\n" +
" AND l.login= :login", nativeQuery = true)
List<Formation> findAllByLogin(#Param("login")String login);
So far so good, this works.
Now I want to add test for the repository (with and h2database). But I can't save data, as the entity isn't mapped to a single table.
So this won't work:
#RunWith(SpringRunner.class)
#SpringBootTest(classes = Application.class)
#DirtiesContext(classMode = DirtiesContext.ClassMode.AFTER_EACH_TEST_METHOD)
public class FormationRepositoryTest {
#Autowired
FormationRepository formationRepository;
#Test
public void communeRepositoryTest() {
Formation formation = new Formation();
formation.setId(123L);
formation.setDlog_login("123");
formationRepository.save(formation); // ok
formationRepository.findAllByLogin("123"); // ko -> Caused by: Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: scolarite.scol_droit_login is not mapped
}
}
Here I need to add, that I don't want sql files in my app.
So what would be a solution here ?
Change my model to create an entity by table ? (in real, my request use 8 inner joins, so it will be quite long to code all that...)
Another solution ?
If you do not want to create the entities for all your tables, you could pre-populate your testing H2 database by defining schema.sql and data.sql on your classpath.
schema.sql will contain the DDL statements to create all tables involved (you mention 8 tables).
data.sql will contain the insert statements needed to make your custom sql return login = 123.
You can find an example here.
Then your test code would be like:
#RunWith(SpringRunner.class)
#SpringBootTest(classes = Application.class)
#DirtiesContext(classMode = DirtiesContext.ClassMode.AFTER_EACH_TEST_METHOD)
public class FormationRepositoryTest {
#Autowired
FormationRepository formationRepository;
#Test
public void communeRepositoryTest() {
List<Formation> formations = formationRepository.findAllByLogin("123");
Assert.assertEquals(formations.size(), 1);
}
}
I have the following working without FetchType.LAZY:
#Entity
public class Test {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String text;
#ManyToOne
#JoinColumn(name = "lazy_id")
private Lazy lazy;
//getters and setters
}
#Entity
public class Lazy {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String text;
//getters and setters
}
And the query method:
public List<Test> all() {
try {
return em.createQuery("FROM Test t").getResultList();
} catch (NoResultException e) {
return null;
}
}
This is the JSON result:
[{"id":1,"text":"test 1","lazy":{"id":1,"text":"lazy 1"}},
{"id":2,"text":"test 2","lazy":{"id":2,"text":"lazy 2"}}]
However I want to return just the id and text data, so I tried to change the #ManyToOne(fetch = FetchType.LAZY)
Then I get this errors:
Severe: Generating incomplete JSON
Severe: org.hibernate.LazyInitializationException: could not initialize proxy [model.Lazy#1] - no Session
I could do something like changing the query to fetch only the fields I want:
public List<Test> all() {
try {
return em.createQuery("SELECT t.id, t.text FROM Test t").getResultList();
} catch (NoResultException e) {
return null;
}
}
But then my response in the JavaScript front end is:
[[1,"test 1"],[2,"test 2"]]
Not a array of objects anymore, mapping everything giving the amount of entities I have is far from ideal.
Most of the content I found is how to fetch the data afterwards, which is not my concern, all I need is to send only fields I want in the first place. I`m not sure whether the EJB #TransactionAttribute should be used or not, I couldn't find a working example. I also tried to change the strategy to a #OneToMany in the Lazy class but to no avail.
Since your question dates back a bit, I hope it's still relevant for you:
If you declare a mapping as lazy (or it is like that by the default behaviour), JPA won't fetch it until it is accessed. So your Lazy class will only be accessed if JSON tries to convert the whole thing and at that point it seems that you no longer have an open session, so the data can't be fetched and will result in an org.hibernate.LazyInitializationException.
If you stick with a lazy mapping (which is in general mostly fine), you have to explicitely fetch or access it, if you need the data for an use case.
Check out Vlad's excellent explanation on the topic.
currently I am wrestling with being able to fetch only the data I need. The findAll() method needs to fetch data dependant on where its getting called.
I do not want to end up writing different methods for each entity graph.
Also, I would avoid calling entitymanagers and forming the (repetitive) queries myself.
Basicly I want to use the build in findAll method, but with the entity graph of my liking. Any chance?
#Entity
#Table(name="complaints")
#NamedEntityGraphs({
#NamedEntityGraph(name="allJoinsButMessages", attributeNodes = {
#NamedAttributeNode("customer"),
#NamedAttributeNode("handling_employee"),
#NamedAttributeNode("genre")
}),
#NamedEntityGraph(name="allJoins", attributeNodes = {
#NamedAttributeNode("customer"),
#NamedAttributeNode("handling_employee"),
#NamedAttributeNode("genre"),
#NamedAttributeNode("complaintMessages")
}),
#NamedEntityGraph(name="noJoins", attributeNodes = {
})
})
public class Complaint implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue
private long id;
private Timestamp date;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "customer")
private User customer;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "handling_employee")
private User handling_employee;
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name="genre")
private Genre genre;
private boolean closed;
#OneToMany(mappedBy = "complaint", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private List<ComplaintMessage> complaintMessages = new ArrayList<ComplaintMessage>();
//getters and setters
}
And my JPARepository
#Repository
public interface ComplaintRepository extends JpaRepository<Complaint, Long>{
List<Complaint> findByClosed(boolean closed);
#EntityGraph(value = "allJoinsButMessages" , type=EntityGraphType.FETCH)
#Override
List<Complaint> findAll(Sort sort);
}
We ran into a similar problem and devised several prospective solutions but there doesn't seem to be an elegant solution for what seems to be a common problem.
1) Prefixes. Data jpa affords several prefixes (find, get, ...) for a method name. One possibility is to use different prefixes with different named graphs. This is the least work but hides the meaning of the method from the developer and has a great deal of potential to cause some non-obvious problems with the wrong entities loading.
#Repository
#Transactional
public interface UserRepository extends CrudRepository<User, Integer>, UserRepositoryCustom {
#EntityGraph(value = "User.membershipYearsAndPreferences", type = EntityGraphType.LOAD)
User findByUserID(int id);
#EntityGraph(value = "User.membershipYears", type = EntityGraphType.LOAD)
User readByUserId(int id);
}
2) CustomRepository. Another possible solutions is to create custom query methods and inject the EntityManager. This solution gives you the cleanest interface to your repository because you can name your methods something meaningful, but it is a significant amount of complexity to add to your code to provide the solution AND you are manually grabbing the entity manager instead of using Spring magic.
interface UserRepositoryCustom {
public User findUserWithMembershipYearsById(int id);
}
class UserRepositoryImpl implements UserRepositoryCustom {
#PersistenceContext
private EntityManager em;
#Override
public User findUserWithMembershipYearsById(int id) {
User result = null;
List<User> users = em.createQuery("SELECT u FROM users AS u WHERE u.id = :id", User.class)
.setParameter("id", id)
.setHint("javax.persistence.fetchgraph", em.getEntityGraph("User.membershipYears"))
.getResultList();
if(users.size() >= 0) {
result = users.get(0);
}
return result;
}
}
#Repository
#Transactional
public interface UserRepository extends CrudRepository<User, Integer>, UserRepositoryCustom {
#EntityGraph(value = "User.membershipYearsAndPreferences", type = EntityGraphType.LOAD)
User findByUserID(int id);
}
3) JPQL. Essentially this is just giving up on named entity graphs and using JPQL to handle your joins for you. Non-ideal in my opinion.
#Repository
#Transactional
public interface UserRepository extends CrudRepository<User, Integer>, UserRepositoryCustom {
#EntityGraph(value = "User.membershipYearsAndPreferences", type = EntityGraphType.LOAD)
User findByUserID(int id);
#Query("SELECT u FROM users WHERE u.id=:id JOIN??????????????????????????")
User findUserWithTags(#Param("id") final int id);
}
We went with option 1 because it is the simplest in implementation but this does mean when we use our repositories we have have to look at the fetch methods to make sure we are using the one with the correct entity graph. Good luck.
Sources:
JPA EntityGraph with different views using Spring
https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#repositories.query-methods
I don't have enough reputation to post all of my sources. Sorry :(
We had the same issue and built a Spring Data JPA extension to solve it :
https://github.com/Cosium/spring-data-jpa-entity-graph
This extension allows to pass named or dynamically built EntityGraph as an argument of any repository method.
With this extension, you would have this method immediatly available:
List<Complaint> findAll(Sort sort, EntityGraph entityGraph);
And be able to call it with an EntityGraph selected at runtime.
Use #EntityGraph together with #Query
#Repository
public interface ComplaintRepository extends JpaRepository<Complaint, Long>{
#EntityGraph(value = "allJoinsButMessages" , type=EntityGraphType.FETCH)
#Query("SELECT c FROM Complaint ORDER BY ..")
#Override
List<Complaint> findAllJoinsButMessages();
#EntityGraph(value = "allJoins" , type=EntityGraphType.FETCH)
#Query("SELECT c FROM Complaint ORDER BY ..")
#Override
List<Complaint> findAllJoin();
...
}
Using the #EntityGraph annotation on a derived query is possible, as I found out from This article. The article has the example:
#Repository
public interface ArticleRepository extends JpaRepository<Article,Long> {
#EntityGraph(attributePaths = "topics")
Article findOneWithTopicsById(Long id);
}
But I don't think there's anything special about "with" and you can actually have anything between find and By. I tried these and they work (this code is Kotlin, but the idea is the same):
interface UserRepository : PagingAndSortingRepository<UserModel, Long> {
#EntityGraph(attributePaths = arrayOf("address"))
fun findAnythingGoesHereById(id: Long): Optional<UserModel>
#EntityGraph(attributePaths = arrayOf("address"))
fun findAllAnythingGoesHereBy(pageable: Pageable): Page<UserModel>
}
The article had mentioned the caveat that you can't create a method similar to findAll which will query all records without having a By condition and uses findAllWithTopicsByIdNotNull() as an example. I found that just including By by itself at the end of the name was sufficient: findAllWithTopicsBy(). A little more terse but maybe a little more confusing to read. Using method names which end with just By without any condition may be in danger of breaking in future versions in Spring since it doesn't seem like an intended use of derived queries name.
It looks like the code for parsing derived query names in Spring is here on github. You can look there in case you're curious about what's possible for derived queries repository method names.
These are the spring docs for derived queries.
This was tested with spring-data-commons-2.2.3.RELEASE
EDIT: this doesn't actually work. Ended up having to go with https://github.com/Cosium/spring-data-jpa-entity-graph. The default method LOOKS correct, but doesn't successfully override the annotations.
Using JPA, what I found works is to use a default method, with a different EntityGraph annotation:
#Repository
public interface ComplaintRepository extends JpaRepository<Complaint, Long>{
List<Complaint> findByClosed(boolean closed);
#EntityGraph(attributePaths = {"customer", "genre", "handling_employee" }, type=EntityGraphType.FETCH)
#Override
List<Complaint> findAll(Sort sort);
#EntityGraph(attributePaths = {"customer", "genre", "handling_employee", "messages" }, type=EntityGraphType.FETCH)
default List<Complaint> queryAll(Sort sort){
return findAll(sort);
}
}
You don't have to do any of the re-implementation, and can customize the entity graph using the existing interface.
Can you try create EntiyGraph name with child that you will request and give same name to the find all method.
Ex:
#EntityGraph(value = "fetch.Profile.Address.record", type = EntityGraphType.LOAD)
Employee getProfileAddressRecordById(long id);
For your case:
#NamedEntityGraph(name="all.Customer.handling_employee.genre", attributeNodes = {
#NamedAttributeNode("customer"),
#NamedAttributeNode("handling_employee"),
#NamedAttributeNode("genre")
})
method name in repository
#EntityGraph(value = "all.Customer.handling_employee.genre" , type=EntityGraphType.FETCH)
findAllCustomerHandlingEmployeeGenre
This way you can keep track of different findAll methods.