This question already has answers here:
Rounding a double value to x number of decimal places in swift
(34 answers)
Closed 3 years ago.
I am trying to reduce the amount of characters in a double. How Would I reduce this:
59.5220000
to
59.5
this in swift?
A double doesn't have characters. A string rendering of it does. Rather than using the standard String() initializer (which is really only for development use, it's terrible for end-users), use NumberFormatter.
perhaps use a formatted string?
let str = String(format: "%.2f", 59.5220000)
Related
This question already has answers here:
Assured 6 digit random number
(8 answers)
Closed 1 year ago.
I am new to Gatling and Scala Environment.
How to generate a Random Numeric String having 6 digits, in Gatling?
For example, I need to feed "123456" for an attribute in Gatling.
Thanks for the help.
You could start with what you've got and make the following change...
...filter(_.isDigit).take(6).mkString
...but I'd be more inclined toward the following.
(Random.nextInt(900000)+100000).toString
Note: For the 1st proposed solution, leading zeros are possible, "010203" for example. That's not the case for the 2nd. Not sure which is preferred.
Scala 2.13.x option:
util.Random.between(100000, 1000000)
//minimum (inclusive)--^ ^--maximum (exclusive)
This question already has answers here:
Special characters in Flutter
(6 answers)
Closed 2 years ago.
I would like to use a dollar sign in a flutter, how can I do this?
like this:
Text('$21.99')
Use Escape Sequence Character,
Text('\$21.99')
You can use raw string by suffixing r.
Like this
Text(r'$21.99')
This question already has answers here:
Remove nth character from string
(4 answers)
Closed 4 years ago.
I'm trying to remove the third character from a string. however, there does not seem to be a clean way to do this. I couldn't find an extension that does this and using a library is a bit overkill
I probably could take the first start range up to this character, then the last range and concatenating these together feels quite wrong and there must be a better way IMO
Any help is appreciated!, Thanks!
You can do that the below way:
var str = "I am Bla Bla"
if str.count > 2 {
str.remove(at: String.Index(encodedOffset: 2))
print(str)
}
Hope this helps.
This question already has answers here:
How String Comparison happens in Swift
(4 answers)
What does it mean that string and character comparisons in Swift are not locale-sensitive?
(3 answers)
Closed 5 years ago.
Documentation > Swift > ClosedRange
let values = "a"..."z"
print(values.contains("c")) //true
Could someone please explain why this prints true?
This question already has answers here:
Swift string formula into a real calculation
(3 answers)
Swift - Resolving a math operation in a string
(4 answers)
Closed 6 years ago.
How can I eval a string in Swift?
My strings are composed by numbers and logic operators.
Some examples are:
"2+2"
"2%2"
"2+2"
"2=3"
"2>3"
"2/5"
I've thought, if is too complex to write a function to do this, to parse a string and execute that as external process in bin/bash process than read a result. Any ideas?
Other questions, like this, are solution if there are only arithmetics operators. In my cases appears bool operators that returns error in NSExpression eval.